Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 15, Problem 33P
Describe how having the Cas
Figure 15.23
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Chapter 15 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 15 - 15.1 What purpose do the bla and lacZ genes serve...Ch. 15 - The human genome is 3109 bp in length. How many...Ch. 15 - 15.3 Ligase catalyzes a reaction between the...Ch. 15 - You have constructed four different libraries: a...Ch. 15 - Using the genomic libraries in Problem 4, you wish...Ch. 15 - The human genome is 3109bp. You wish to design a...Ch. 15 - 15.7 Using animal models of human diseases can...Ch. 15 - 15.8 Compare methods for constructing homologous...Ch. 15 - 15.9 Chimeric genefusion products can be used for...Ch. 15 - 15.10 Why are diseases of the blood simpler...
Ch. 15 - Injection of double-stranded RNA can lead to gene...Ch. 15 - Compare and contrast methods for making transgenic...Ch. 15 - 15.13 It is often desirable to insert cDNAs into a...Ch. 15 - 15.14 A major advance in the s was the development...Ch. 15 - 15.15 The bacteriophage lambda genome can exist in...Ch. 15 - 15.16 The restriction enzymes Xho and Sal cut...Ch. 15 - 15.17 The bacteriophage has a single-stranded DNA...Ch. 15 - 15.18 To further analyze the CRABS CLAW gene (see...Ch. 15 - You have isolated a genomic clone with an EcoR I...Ch. 15 - 15.20 You have identified a cDNA clone that...Ch. 15 - 15.21 You have isolated another cDNA clone of the...Ch. 15 - 15.22 You have identified five genes in S....Ch. 15 - You have generated three transgenic lines of maize...Ch. 15 - 15.24 Bacterial Pseudomonas species often possess...Ch. 15 - 15.25 Two complaints about some transgenic plants...Ch. 15 - 15.26 In Drosophila, lossoffunction Ultrabithorax...Ch. 15 - Prob. 27PCh. 15 - The highlighted sequence shown below is the one...Ch. 15 - Vitamin E is the name for a set of chemically...Ch. 15 - The RAS gene encodes a signaling protein that...Ch. 15 - 15.31 You have cloned a gene for an enzyme that...Ch. 15 - 15.32 About of occurrences of nonautoimmune type...Ch. 15 - Describe how having the Cas 9 gene at a genomic...Ch. 15 - 15.34 Would a gene drive system spread rapidly...
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- Diagram the fate of the dsRNA once it enters a cell, highlighting the enzymatic reactions that eventually result in down-regulation of gene function. What is the hypothesised molecular basis of the hypersensitivity to RNAi in the eri-1/lin15b mutants?arrow_forwardThe cI protein in bacteriophage l (lambda) is a transcriptional regulator - name the promoters in the phage genome that are regulated by this protein, and give the effect of the cI protein on each promoter you name (i.e. is the cI protein an activator or a repressor for that promoter).arrow_forwardGive the result(s) of the experiment in "MicroRNAs Control De Novo DNA Methylation Through Regulation of Transcriptional Repressors in Mouse Embryonic Stem Cell" and how the figure clearly demonstrates that outcome. Also, note the positive and/or negative controls for the experiment.arrow_forward
- The lac operon consists of three structural genes, lacZ, lacY and lacA that are transcribed as a single polycistronic mRNA. You are given a new strain of Escherichia coli with the following lac operon genotype: p+0°Z•Y*A +// P*O*Z*Y+ A- (i) Explain how the lac I gene affects gene expression. (ii) Explain the function of the lacP in the bacterial operon. (iii) Which part of the lac operon is cis-dominant? Explain.arrow_forwardThe tac promoter, an artificial promoter made from portions of the trp and lacUV5 promoters, has been introduced into a plasmid. It is a hybrid of the lac and trp (tryptophan) promoters, containing the −35 region of one and the −10 region of the other. This promoter directs transcription initiation more efficiently than either the trp or lac promoters. Why?arrow_forwardradioactively labeled cDNA is used to probe RNA isolated from kidney by Northern blotting. Twobands are seen on the blot. Which of the following reasons is least possible? A. A single pre mRNA is spliced into two different messagesB. There are two promoters for the geneC. There are two related genes expressed in kidneyD. The mRNA is cleaved in the cytoplasm as part of its degradation Explain why the answer is B or EE. There is a single mRNA produced but some is not polyadenylatedarrow_forward
- You then make a screen to identify potential mutants (shown as * in the diagram) that are able to constitutively activate Up Late operon in the absence of Red Bull and those that are not able to facilitate E. Coli growth even when fed Red Bull. You find that each class of mutations localize separately to two separate regions. For those mutations that prevent growth even when fed Red Bull are all clustered upstream of the core promoter around -50 bp. For those mutations that are able to constitutively activate the operon in the absence of Red Bull are all located between the coding region of sleep and wings. Further analysis of each DNA sequence shows that the sequence upstream of the promoter binds the protein wings and the region between the coding sequence of sleep and wings binds the protein sleep. When the DNA sequence of each is mutated, the ability to bind DNA is lost. Propose a final method of gene regulation of the Up Lateoperon using an updated drawn figure of the Up Late…arrow_forwardExamine the following theoretical operon (gen) in E. coli which contains structural genes (genC, genB, genA) that are involved in amino acid biosynthesis. The gen operon also includes the gene encoding for the regulator molecule within it. When the amino acid that this operon helps synthesize is present, it binds to the regulator forming a complex which can bind to the operator region. Assume that the regulator molecule only binds to the operator in the presence of the amino acid. Question 1 Promoter Operator genC genB gen operon Regulator genA Transcription occurs when: A. The amino acid is not bound to the regulator, causing the regulator to bind to the operator. B. The amino acid is bound to the regulator, causing the regulator to bind to the operator. C. The amino acid is not bound to the regulator, causing the regulator to fail to bind to the operator. D. The amino acid is bound to the regulator, causing the regulator to fail to bind to the operator. E. The operon is…arrow_forwardExamine the following theoretical operon (gen) in E. coli which contains structural genes (genC, genB, genA) that are involved in amino acid biosynthesis. The gen operon also includes the gene encoding for the regulator molecule within it. When the amino acid that this operon helps synthesize is present, it binds to the regulator forming a complex which can bind to the operator region. Assume that the regulator molecule only binds to the operator in the presence of the amino acid. Promoter || Operator genC genB gen operon Regulator genAarrow_forward
- lin-28 is a gene that is critical for stem cell integrity in mammals and is involved in tumourigenesis, but it was originally identified as a gene involved in developmental timing in C. elegans. It is targeted by the microRNAs lin-4 and let-7 and this affects its translation. Q2a) If the lin-4 sequence is 5’-UCCCUGAGACCUCAAG-3’, which of the following sequences might best correspond to the single target RNA sequence in the 3’UTR of lin-28. A) 3’ UTR- 5’-UCCCUGAGACCUCAAG-3’ B) 3’ UTR- 5’-CUUGAAAUCUCAGUUA-3’ C) 3’ UTR- 5’-CUUGAGGUCUCAGGGA-3’ Q2b) Then describe in 2 sentences/lines why you chose this target sequence.arrow_forwardThe following diagram show what is required for an active promoter of a gene of interest, where:A1 = Activator 1A2 = Activator 2Med = MediatorRep = Repressor Based on the following data, predict: Chromatin conformation Methylation state of the proximal promoter If protein A1 is present or absent If protein A2 is present or absent If the mediator is present or absent If the repressor is absence or present If this gene is likely to be transcribed or notPlease note that this is an "all or nothing" bonus question, and no partial credit will be awarded. Selecting all answers will result in zero points awarded. Selecting at least one incorrect answer will result in zero points being awarded. Question 28 options: Euchromatin Heterochromatin Methylated promoter Unmethylated promoter Activator A1 present Activator A1 absent Activator A2 present…arrow_forwardComplete Table 1, indicating how much (lots, little, none) of the above gene product would be made given the following mutations: • Mutation in the operator that reduces the affinity of the operator for the repressor protein (operator-constitutive mutants=0°)? Mutation in the promoter that reduces the affinity of the promoter for RNA polymerase (P)? Mutation in the repressor gene such that the protein has lost the ability to bind allolactose (superrepressor mutant = I³)? Mutation in the repressor gene such that the protein has lost the ability to bind the operator (I)? Gene Status normal 0° P- IS I- + lactose - lactosearrow_forward
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