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What is the molar absorptivity of a 1.0 x10-5 M analyte with an absorbance reading of 0.003 at 517 nm wavelength?
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- A 4.84×10−5 M sample of compound X in a solvent has an absorbance of 0.213 at 528 nm in a 1.000 cm cuvette. The solvent alone has an absorbance of 0.064. What is the molar absorptivity of compound X?Suppose that a solution has an absorbance of 0.226 at a wavelength of 450 nm. If the concentration of the solution is 24 μM, what is the value of the molar absorptivity? The data were taken with a standard 1-cm cuvette.The following data are obtained from three standard soltions using UV-Vis spectroscopy: What is the colar concentration (M) of an unknown solution with an absorbance of 0.180 at 255 nm? The unknown solution contains the same analyte as the standard solution does. The molar mass of the analyte is 188.65 g/mol a) 4.82x10-5b)1.9x10-3c)3.60x10-4d)1.9x10-5e)1.8x 10-4
- The measures absorbance of a solution with a pathlength of 1.00 cm is 0.544. If the concentration is 1.40 x 10^-3 M, what is the molar absorptivity for this analyte?Tablet powder containing 80 mg of promazine hydrochloride is ground to a paste with 10 ml of 2 M HCl. The paste is then diluted with 200 ml of water, shaken for 15 min and finally made up to 500 ml. A portion of the extract is filtered. Then, 5 ml of the filtrate is taken and diluted to 120 ml with 0.1 M HCl. – Absorbance reading=0.755 is read at a wavelength wavelength of 251 nm – A (1%, 1 cm) value of promazine.HCl at 251 nm=935 – Stated content of promazine.HCl per tablet=50 mg – Weight of 20 tablets=1.667 g – Weight of tablet powder taken for assay=163 mg expected content in tablet taken is: A-97.78 g/mL B-97.78 g/100ml C-0.0097g/mL D-97.78 mg/100ml Concentration in diluted tablet extract is: A-0.81g/mL B-80 g/100ml C-0.00081g/mL D-0.807 mg/100ml Concentration in original tablet extract is: A-19.38g/mL B-16.15 mg/100ml C-19.38 mg/100ml D-16.15 mg/mL Amount of promazine.HCl in original extract is: A-96.90mg B-80.75mg C-96.90mg/100ml D-80.75mg/100ml…A 5.00×10−4 M solution of analyte is placed in a sample cell that has a pathlength of 1.00 cm. At a wavelength of 490 nm, the solution’s absorbance is 0.338. What is the analyte’s molar absorptivity at this wavelength?
- Tablet powder containing 100mg of promazine hydrochloride is ground to a paste with 10 ml of 2 M HCl. The paste is then diluted with 300 ml of water, shaken for 15 min and finally made up to 500 ml. A portion of the extract is filtered. Then, 5 ml of the filtrate is taken and diluted to 200 ml with 0.1 M HCl. – Absorbance reading=0.855 is read at a wavelength wavelength of 251 nm – a (1%, 1 cm) value of promazine.HCl at 251 nm=950 – Stated content of promazine.HCl per tablet=60 mg – Weight of 24 tablets=1.500g – Weight of tablet powder taken for assay=180 mg expected content in tablet taken is: 172.8 mg 1000mg 100 mg 100g Concentration in diluted tablet extract is: 0.1g/mL 0.9 g/100ml 1.11 g/mL 0.9 mg/100ml Concentration in original tablet extract is: 36g/mL 36 mg/100ml 19.38 mg/100ml 16.15 mg/mL Amount of promazine.HCl in original extract is: 172.8mg 180mg/100ml 96.90mg 180mg percentage of stated content 99.1 % 96% 80.75mg/100ml 104.2%A 2.54 x 10-M sample of compound X in a solvent has an absorbance of 0.370 at 528 nm in a 1.000 cm cuvette. The solvent alone has an absorbance of 0.058. What is the molar absorptivity of compound X? € = M-1.cm- A different of compound X in the same solvent has an absorbance of 0.475 at 528 nm when measured with the same cuvette. What is the concentration of this second sample? mol X [X] = L * TOOLS |x10The measured absorbance of a solution with a pathlength of 1.00 cm is 0.544. If the concentration is 1.4010-3 M, what is the molar absorptivity for this analyte?
- 2. Answer ALL parts. (a) The absorbance of compound A was measured in a 1.00 cm cuvette at 238 nm. A 3.96 x 10 M solution of compound A exhibited an absorbance of 0.624. A blank solution containing only the solvent had an absorbance of 0.029 at the same wavelength. Calculate the molar absorptivity of compoundA in m' mole". (i) The absorbance of an unknown solution of Compound A in the same solvent and cuvette was 0.375 at 238 nm. Find the concentration of A in the unknown. (iii) A concentrated solution of Compound A in the same solvent was diluted from an initial volume of 2.00ml to a final volume of 25 ml and then had an absorbance of 0.733 under the same conditions. What is the concentration of A in the concentrated solution? (iv) What type of cuvette was used in the above analysis? Justify your answer. (b) Name ONE advantage and ONE disadvantage of a linear photodiode array detector compared to a traditional photomultiplier based spectrometer. (c) Why is an FTIR spectrum digital in…Calculate the molar absorptivity of benzene (FW = 78.11 g/mol) at 256 nm if a 25.80 mg of benzene per 250.0 mL solution using hexane (FW = 86.18 g/mol) as the solvent exhibited an absorbance of 0.2660 in a 10.00 cm cuvette. Pure hexane has negligible absorbance at this wavelength.The concentration of a glucose solution was determined via a DNS assay, and it was determined that a 150.0 mM solution would have an absorbance of 0.156. If the pathlength used was 0.95 cm, what is its molar absorptivity constant, in L cm mol 1?