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- (5) A sample of sodium phosphate is dissolved in water to give 100.00 mL of solution (Solution A). Then this solution is diluted 5 times to give the final solution (Solution B). Solution B is Known to contain 3.920 x 1022 number of PO43- ions, which has an absorption peak at 460 nm and absorbance value of 0.355 in a 1.000 cm cuvette. (i) Calculate the molar absorptivity of Solution B. (ii) What mass of sodium phosphate (MM 163.94 g/mol) dissolved in Solution A.Calculate the molar absorptivity and absorbance of a 1.00 x 104 M solution, which has atransmittance of 32.1% , when the path length is 2.5 cm at 650 nm. (At 350 nm, the absorbance of a solution of 60.06-ppm K2Cr207 in 0.0050 M H2SO, in 0.640 (b=1). What is the molar absorbitivity of K2Cr207 at this wavelength?
- Absorbance at 453 nm 8393939 7 fl. oz./20 ml Beer-Lambert's Law (Spectrophotometry) #1 Fe (aq) + KSCN(s) FESCN "(aq) + K" (aq) 3+ To determine the moles of Fe (aq) in a 100. mL sample of an unknown solution, excess KSCN(s) is added to convert all the Fe (aq) into the dark red species FeSCN"(aq), as represented by the equation above. The absorbance of FESCN"(aq) at different concentrations is shown in the graph below. 2+ 0.50 目0.40 0.30 0.20 01 0. 0. 5 x 10-5 10 x 10-5 Concentration of FESCN2+ (M) If the absorbance of the mixture is 0.20 at 453 nm, haw many moles of Fe (aq) were present in the 100. mL sample? (Assume that any volume change due to adding the KSCN(s) Iis negligible.) 3+, 4x10-4 mol 3 x 104 mol (B) 4x 10-6 mol 3x 10-6 mol3.) The accuracy of a spectrophotometer is evaluated by preparing a solution of 60.06 ppm K2Cr2O7 and measuring its absorbance at a wavelength of 350 nm in a cell with a pathlength of 1.00 cm. The expected absorbance is 0.640. What is the expected molar absorptivity of K2Cr2O7 at this wavelength?A 2.78 ✕ 10−4 M solution of a compound has an absorbance of 0.417 at 520 nm in a 1.00 cm cell. The solvent's absorbance under the same conditions is 0.020. (a) What is the molar absorptivity of the unknown compound? M -1cm-1(b) What is the concentration of the compound in a solution, if the absorbance of the solution in a 1.00 cm cell at 520 nm is 0.391? M
- Q4) A 5 M solution of a red-orange pigment has an absorbance of 0.750 at 453 nm in 1.00 cm cuvette. Calculate the molar absorptivity of the pigment at 453 nm?5. A 7.25x104 M solution of Potassium cyanide (KCN) has a transmittance of 45.2% when measured in a 2 cm cell at a wavelength of 525 nm. Calculate (a) the absorbance of this solution; (b) the molar absorptivity of KMNO4.At 590 nm, crystal violet (a biological stain) has a molar absorptivity (ε) of 8.7×104 M-1cm-1. Using Beer's Law, calculate the concentration of crystal violet in a solution with a measured absorbance (A) of 1.254. The path length (b) is 1.00 cm.
- A 2.78 x 10-4 M solution of a compound has an absorbance of 0.469 at 520 nm in a 1.00 cm cell. The solvent's absorbance under the same conditions is 0.024. (a) What is the molar absorptivity of the unknown compound? 4.0 1687 X M-¹cm-1The transmittance of a solution measured at 590 nm in a 1.5-cm cuvette was 76.2%. (a) What is the corresponding absorbance?(b) If the concentration is 0.0802 M, what is the absorptivity of this species at this wavelength? (c) If the absorptivity is 10,000 L mol-1 cm-1, what is the concentration?The absorbance of 1.48x 105 M methyl red solution, prepared in 0.1 M HCI, was measured using a 1.0 cm cell (cuvette) and found to be 0.550 at 524 nm. Calculate the molar absorption of methyl red under these conditions. Select one: 42956 M¹ cm-¹ < 18524 M²¹ cm 1 O37162 M.¹ cm ¹ 12760 M¹¹cm¹