1 Derive a Boolean expression for the following digital circuit and sketch the true table.
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- Question 4: For the number display below, we would like to identify Boolean expression for LEDS (outputs a through g2) that indicate numbers 11, 14, and 15. a. Please write the Boolean expressions for the two LEDS (outputs a through g2) based on the input signals So to S3. You do not need to simplify the Boolean expressions. b. Please draw the logit circuit for outputs a through g2 a2 Logic circuit 2. 88 5,5,5,50Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.DConsider the given logic equation below. Draw the logic diagram then simplify it using Boolean Algebra. Draw the logic diagram based on the simplified logic equation. X = A'BC' + A'B'C' + AB'C + AB'C' + A'B'C From the given logic diagram, trace the output using all possible input combination. Give it a conclusion upon completion..
- 2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CIH.W: Draw a logic eircuit of the following Boolean expression before and after simplification using karnough map and Boolean expression. Y-AB+ AB A B Y 1 1USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
- Simplify the following Boolean expressions using Karnaugh Map and draw the logic circuits. f = wxyz + wxyz + wxyż + wxỹz + wxyz + wxyz + wxỹz + wãyzAssuming we are given a Logic Gate network, the output of the circuit is given by the following equation Q=A.B+A.C+ A.B.C By using the Boolean Logic rules for simplification, select which of the following equations is the correct simplified one. Note that, the answer None of the above may sometimes be the correct response. Q=A+(B.C) O Q=A.(B.C) O Q=Ā. (B+C) ⒸQ=A. (B+C) None of the above O Not answered(B)- Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+ (C+ B).D 2) Y= A.B.C+B. D. (A OB)+C 3) Y= A.B (C+ D) +D+ A OB
- (m. Simplify the given expression using Boolean algebra and implement the simphifie expression using basic logic gates. Y = A.B.C+ A.B.C + A.B.C + A.B.C1 - Design 3-bit Gray code generator 1-1 Construct the Truth Table of the 3-bit Gray code generator Logic Circuit. 1-2 1-3 1-4 Write down Standard SOP expression of the three output bits B2, B1, BO Without using minimization. Simplify the logic by using K-map. Write down the simplified expressions of B2, B1, B0. Sketch the logic circuit with basic gates.Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A. B+ C+(C+B).D 2) Y= A.B.C+B.D. (A OB)+C - 3) Y=A.B (C+D) + D+A OB