For the Logic circuit shown below, Find Expression for F
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A: In this answer we will find the resultant expression of F as explained below.
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- Problem: Derive the logic expressions for a circuit that compares two unsigned numbers: X = x2x1xo and Y = = y2y1yo and generates three outputs: XGY, XEY, and XLY. One of these outputs is set to 1 to indicate that X is greater than, equal to, or less than Y, respectively.a) For the given logic circuit diagram write the program by using the gate level modeling. b) For the given truth table write the program by using the data flow Modelling. c) Write the test bench of the given logic circuit with all possibilities Y1 Y2 Y3 Y4 Y5 Y6 Y7 A2 A1 A0A B Prepare the truth table of the logic circuit (logic circuit) on the right. Then, using the truth table, write the function you have obtained according to the SOP (minterm) without any simplification and draw the logic circuit for the new function you have obtained. Make sure that the circuit you have drawn is understandable, the function you have written and the truth table are readable.
- Design a combinational circuit with four input lines that represent a decimal digit in BCD and four output lines that generate the 9's complement of the input digit. Provide a fifth output that detects an error in the input BCD number. This output should be equal to logic 1 when the four inputs have one of the unused combinations of the BCD code. Provide a schematic logic diagram of it. It will surely help me in my review. Thank you so much!2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CTask 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'C
- An X-input exclusive-OR gate and a Y-input exclusive-OR gate (where X=3, Y=4 have their outputs connected to a 2-input exclusive-NORgate. Do the following:a) Draw the logic diagram and analyze the logic expression of the output (in standard SOPform).b) List out all essential prime implicants.For a combinational logic circuit of four bits Binary Coded Decimal (BCD) inputs and one output having following conditions: • if the equivalent decimal number of the BCD is even then output is 0 • if the equivalent decimal number of the BCD is odd then output is 1 Draw the truth table 20. i) ii) Find the simplified logic function using K-Map ii) Draw the logic diagramQ1. Determine the output waveform and Boolean expression X of the logic circuit in given circuit. D. B Q 2. Find the all Boolean expression for Y1, Y2, Y3, and Y4 (in the Q-1) and the intermediate waveforms at each of points Y1, Y2, Y3, and Y4.
- Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FUsing truth table method prove the following equality (P+QR) + PQ = P + Q ii. For the logic diagram shown in Figure Q23 prove it is working as Ex-OR gate. 4x1 MUX I, .F Y I2 I3 S So A Banswere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.