COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 9, Problem 67QAP
To determine

(a)

The number of strands needed to support a person having mass of 85 kg.

To determine

(b)

The diameter of the rope and reasons.

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Many caterpillars construct cocoons from silk, one of the strongest naturally occurring materials known. Each thread is typically 2.0 um in diameter, and the silk has a Young's modulus of 4.0 x 10° N/m². Assuming that there is no appreciable space between the parallel strands, how many strands N would be needed to N = strands make a rope 8.6 m long that would stretch only 1.06 cm when supporting a pair of 81-kg mountain climbers? Again assuming that there is no appreciable space between the parallel strands, what would be the diameter d of the rope? d = cm Question Source: Freedman College Physics 3e | Publisher: Mac 5:04 PM 69°E Partly sunny
Many caterpillars construct cocoons from silk, one of the strongest naturally occurring materials known. Each thread is typically 2.0 µm in diameter, and the silk has a Young's modulus of 4.0 x 10° N/m2. Assuming that there is no appreciable space between the parallel strands, how many strands N would be needed to N = strands make a rope 8.6 m long that would stretch only 1.02 cm when supporting a pair of 85-kg mountain climbers? Again assuming that there is no appreciable space between the parallel strands, what would be the diameter d of the rope? d = cm
Many caterpillars construct cocoons from silk, one of the strongest naturally occurring materials known. Each thread is typically 2.0 µm in diameter, and the silk has a Young's modulus of 4.0 × 10⁹ N/m². Assuming that there is no appreciable space between the parallel strands, how many strands N would be needed to make a rope 8.2 m long that would stretch only 1.02 cm when supporting a pair of 91-kg mountain climbers? N = Again assuming that there is no appreciable space between the parallel strands, what would be the diameter d of the rope? strands d = cm

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