COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 9, Problem 50QAP
To determine

What will the new dimensions of the cube be after the forces are applied ( B=46×109N/m2 for lead) if a cube of lead (each side is 5.0 cm) is pressed equally on all six sides with forces of 1.0×106N ?

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10N force is uniformly distributed over the surface of a sphere of radius 20cm. The force at each point acts inward along the normal at that point. Find the fractional change in volume if the compressibility of the sphere is 10-11m2/N. a) 3*10-10 b) 1.5*10-11 c) 1.98*10-10 d) 2*10-11
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4. Certain frictional forces have magnitude proportional to the square of the velocity of the moving object. Thus |Ffriction| = -yv² for some positive constant y. Here there is an annoying sign issue since the frictional force must have sign opposite to the velocity. One can write Felastic = -y|v|v. If an object of mass m is subject to this frictional force and no other forces, and the initial velocity is positive, then the velocity will always be positive and we can just say Ffriction Then the position y of the particle satisfies the equation -yo?. dy dt2 2 dy +y dt = 0. Write out a solution of this equation for the initial conditions y(0) = Yo, (dy/dt)(0) the substitution u = = vo. Hint: The equation reduces to first order. Use dy/dt and solve the first order equation to get u. Then integrate u to get y.

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