Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 7, Problem 7.9PFS
To determine
The design of
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Q2) The members of the truss structure shown below is plain concrete. The compressive
strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by
the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use
material factors and do not consider slenderness) Comment on your results briefly.
P
A&
2m
SC
2 m
1380
2m
D
Select all zero-force members in the truss shown below. Check the box for zero-
force members
3 m
3 m
12 m, 8 @ 1.5 m
DE
O LK
ЕР
O HF
O BC
BM
EF
OM
CD
BN
LO
O DK
FI
O co
Each bar of the truss has a rectangular cross section, 30 mm by 60 mm. Determine
the maximum vertical load P that can be applied at B if the working stresses are
100 MPa in tension and 80 MPa in compression. (A reduced stress in compression
is specified to reduce the danger of buckling.)
B
8m
Gm
10m
Chapter 7 Solutions
Structural Steel Design (6th Edition)
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- A plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.arrow_forwardAnswers: AB = kN E AH = kN Determine the force in each member of the loaded truss. All triangles are 3-4-5. Enter a the member is in tension, negative if in compression. BC - kN C 34kN kN BG E 34 kN BH - kN 15 kN BI = kN D B kN kN A E DE kN H G F DF = kN - 4 panels at 8 m- DG = kN DI kN EF = kN FG - kN GH = kNarrow_forwardThe rigid frame shown in Figure is unbraced in the plane of the frame. In the direction perpendicular to the frame, the frame is braced at the joints. The connections at these points of bracing are simple (moment-free) connections. Roof girders are W14 x 30, and floor girders are W16 x 36. Member BC is a W10 x 45. Use A992 steel and select a W-shape for AB. Assume that the controlling load combination causes no moment in AB. The service dead load is 25 kips and the service live load is 75 kips. a. Use LRFD. b. Use ASDarrow_forward
- A WT205 x 30 structural steel section (see Appendix B for cross-sectional properties) is used for a 8.8 m column. Assume pinned connections at each end of the column. Determine: (a) the slenderness ratio. (b) the Euler buckling load. Use E = 200 GPa for the steel. (c) the axial stress in the column when the Euler load is applied. Part 1 Use Appendix B to look up the cross-sectional area, the area moment of inertia, and the radius of gyration for a WT205 x 30 structural steel section. Answer: A = i mm2 Ix = i x 106 mm4 mm x 106 mm4 ry i mmarrow_forwarddetermine the member stresses of the truss shown. indicate if the stress in the member is in tension or compression. present complete and neat solutions. p1-30kN W-25kN/m P2=51kN AH Av Im P₂ Im P₂ Im P₂ Im Av W 1.6marrow_forwardSelect all zero-force members in the truss shown below. Check the box for zero- force members 3m 12 m, 8 @ 1.5 m O DE LK EP OHF O BC O BM O EF O OM O CD O BN LO O DK FI O co O O O O O O 0 0 O 0arrow_forward
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