Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 7, Problem 7.15PFS
To determine
The design of square base plate with A36 steel for a
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Determine (approximately) the force in each truss member of the portal frame.
Assume all members of the truss be pin connected at their ends. (Kindly embed your
answers).
Assume the diagonals can support either a tensile or compressive force. (Provide
complete solution, summary of results)
E
1.5 k
15 ft
F
2k
D
15 ft
– 2 k
C
15 ft
В
-15 ft
Q4: Calculate the forces induced in members KL, CL, and CB by the 20-ton load on the
cantilever truss.
M
L.
K
26
16'
G
E
B A
6 panels at 12
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Identify all zero-force members (you do not need to solve for member forces).
d
e
10'
10'
a
h
j
k
m
40k
50k
30k
8 @ 10'
Chapter 7 Solutions
Structural Steel Design (6th Edition)
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- Determine the force in bars BD, CD and DF. GO0 Ib 1200 1b (200 Ib 12' 1200 lb 4' Farrow_forwardDETERMINE THE STRESS IN EACH MEMBER OF TRUSS LOADED AND SUPPORTED AS SHOWN. RAN SOON. a 2 300N 300 H S 4 C 6 ५०० 7 f 12m d 9 10 11 300N 12 13 B R5 3marrow_forwardDetermine the force in each of the members located to the left of FG for the scissors roof truss shown. State whether each member is in tension or compression. 1 kN 2 kN Во C 2 kN Do E 2 m 2 m 1 kN Fo G 2 m 2 m H K 2 m J. 2 m 1 m 1 m 1 m 1 m L1 m Show complete solutions and diagrams. Original work please I will upvotearrow_forward
- Determine the forces in members CD, CJ, and DJ. M 8' A 7' B L 6 panels at 5' K C L J D L L 7 E H L F L Garrow_forwardCompute the force member EF,NF and NOarrow_forwardProblem 6.2 Determine the forces in members (a) AB, (b) BC, (c) CJ, (d) DI, and (e) JI in each truss. Note that the trusses are symmetrical and make sure to note if a given member is in tension (T) or compression (C). 4k 8k D VC 8k H 3' truss one 3' 8k H 4k I- 3' 3' 3' 3 8k 8k truss two H 8k 41arrow_forward
- W 14 x 142 is used as a column having a length of 8.48 m. long. It is hinged at the r end and fixed at the lower end but there is a lateral bracing perpendicular to minor axis of the W section at a point 4.78 m. above the bottom support. It is assumed to be pinned connected at the bracing point. Using A 36 steel Fy= 248 MPa the NSCP Specificatioris. E, = 200000 MPa. Properties of W 14 x 142 A = 26967.69 mm2 d= 374.65 mm bf= 393.70 mm tf= 27.00 mm tw= 17.27 mm4 Ix= 695.11 x 106 mm4 Iy = 274.71 x 106 mm4 rx = 160.53 mm rY = 100.84 mm Assume: Kx = 0.80 for 8.48 m. length KY = 1.9 for the length on the upper support KY = 0.80 for the length on the bottom support Compute the slenderness ratio along y-axis. Please show clear solution thank youarrow_forwardW 14 x 142 is used as a column having a length of 8.48 m. long. It is hinged at the r end and fixed at the lower end but there is a lateral bracing perpendicular to minor axis of the W section at a point 4.78 m. above the bottom support. It is assumed to be pinned connected at the bracing point. Using A 36 steel Fy= 248 MPa the NSCP Specificatioris. E, = 200000 MPa. Properties of W 14 x 142 A = 26967.69 mm2 d= 374.65 mm bf= 393.70 mm tf= 27.00 mm tw= 17.27 mm4 Ix= 695.11 x 106 mm4 Iy = 274.71 x 106 mm4 rx = 160.53 mm rY = 100.84 mm Assume: Kx = 0.80 for 8.48 m. length KY = 1.9 for the length on the upper support KY = 0.80 for the length on the bottom support Compute the slenderness ratio along y-axis.arrow_forward1. Determine the force in each member of the truss and state whether the force is tension or compression. (Use method of Joints) F H 14 ft A. В D 2 kip 4 kip 2 kip 10 ft 10 ft 10 ft 10 ftarrow_forward
- Compute the internal force of member CD & EFarrow_forwardSteel Design Two channels having the given properties shown is placed at a distance of 300 mm to back and is properly connected by a pair of lacings as shown. Properties of one channel A = 5595 mm2 d = 305 mm x = 17mm Ix = 67.3 x 106 mm4 Iy = 2.12 x 106 mm4 rx = 19.3 mm Assume K = 1.0 Determine the safe axial load in kN, that the column section could carry. Unsupported height of column is 6m.arrow_forwardThe wide-flange pinned-end column shown in the figure carries two loads, a force acting at the centroid P₁ = 450kN and a force P₂ = 270kN acting at distance s = 100 mm, from the centroid. The column is an HE 240B shape with L = 4.2m, E = 200 GPa, and Oy = 290 MPa. (a) What is the maximum compressive stress in the column?arrow_forward
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