What is displayed on the console when running the following program? public class Test { public static void main (String[] args) { try { System.out.println("Welcome to Java"); } catch (Exception ex) { System.out.println("Exception"); } finally { System.out.println("The finally clause is executed"); } } }

What is displayed on the console when running the following program? public class Test { public static void main (String[] args) { try { System.out.println("Welcome to Java"); } catch (Exception ex) { System.out.println("Exception"); } finally { System.out.println("The finally clause is executed"); } } }

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter12: Exception Handling

Section: Chapter Questions

Problem 20RQ

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1.public class Test{ public static void main(String args[]){ Person p = null; try{ } p.talk(); } catch (NullPointerException e) { System.out.print("There is a NullPointerException."); } catch(Exception e) { System.out.print("There is an Exception."); } System.out.print("Everything went fine."); } what will be the result if you run this program? O There is a NullPointerException. Everything went fine. O There is a NullPointerException. There is a NullPointerException. There is an Exception. This code will not compile, because in Java there are no pointers.
Look at the following program and tell what it will output when run:public class ExceptionTest{public static void main(String[] args){int number;String str;try{str = "xyz";number = Integer.parseInt(str);System.out.println("A");}catch(NumberFormatException e){System.out.println("B");}catch(IllegalArgumentException e){System.out.println("C");}System.out.println("D");}}
Code completion and explain. public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } }.
public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } } Complete and explain.
void foo () { try { throw new Exception1 (); print (" A "); throw new Exception2 (); print (" B "); } catch ( Exception1 e1 ) { print " handler1 "; } print (" C "); throw new Exception2 (); } void main () { try { try { foo (); print (" D "); } catch ( Exception1 e1 ) { print " handler2 "; } print (" E "); } catch ( Exception2 e2 ) { print " handler3 "; } } Write down the output of the program and justify why it is the output. Instead of the “replacement” semantics of exception handling used in modern languages, a very early design of exception handling introduced in the PL/I language uses a “binding” semantics. In particular, the design dynamically tracks a sequence of “catch” blocks that are currently active; a catch block is active whenever the corresponding try block is active. What will be the output of the following program if the language uses the “binding” semantics? Give the reasoning for your answer.
Checked exceptions in Java are those exceptions that are checked at compile time and must be either caught or declared in the method's throws clause. (True/False)
A method can use the throws clause to pass the responsibility of handling any exceptions to the caller of the method. This is usually seen as better programming discipline than handling exceptions inside of methods. Why is that? In JAVA CODE
Java Questions - (Has 2 Parts). Based on each code, which answer out of the choices "A, B, C, D, E" is correct. Each question has one correct answer. Thank you. Part 1 - The following code will cause a(n) ___ exception. class Sample{public static void main(String[] args) { int x = 0; int y = 10; int z = y/x; } } A. ArithmeticExceptionB. ArrayIndexOutOfBoundsExceptionC. StringIndexOutOfBoundsExceptionD. NullPointerExceptionE. ClassNotFoundException Part 2 - A programmer carelessly assigned a negative value as an index of an array. Which type of exception will be raised during execution? A. An IndexOutOfBoundsException is thrown.B. A NumberFormatException is thrown.C. The first slot of the array is used.D. This is an Error, so the program immediately terminates no matter what.E. The last slot of the array is used.
// JumpinJive.java - This program looks up and prints the names and prices of coffee orders. // Input: Interactive. // Output: Name and price of coffee orders or error message if add-in is not found. import java.util.Scanner; public class JumpinJive { public static void main(String args[]) throws Exception { // Declare variables. String addIn; // Add-in ordered by customer. final int NUM_ITEMS = 5; // Named constant // Initialized array of add-ins. String addIns[] = {"Cream", "Cinnamon", "Chocolate", "Amaretto", "Whiskey"}; // Initialized array of add-in prices. double addInPrices[] = {.89, .25, .59, 1.50, 1.75}; boolean foundIt; int x; // Loop control variable. double orderTotal = 2.00; // All orders start with a 2.00 charge // Get user input. Scanner input = new Scanner(System.in); System.out.print("Enter coffee add-in or XXX to quit: "); addIn = input.nextLine();…
in java, Explain what happens if an exception is not caught.
A method can use the throws clause to pass the responsibility of handling any exceptions to the caller of the method. This is usually seen as better programming discipline than handling exceptions inside of methods. Why is that?
Analyze the following code: public class Test{ public static void main(String[] args) { try { String s = "5.6"; Integer.parseInt(s); // Cause a NumberFormatException } } catch (Exception ex) { System.out.println("NumberFormatException"); int i = 0; int y = 2/i; } catch (RuntimeException ex) { } } System.out.println("RuntimeException"); The program displays NumberFormatException. The program displays RuntimeException. The program displays NumberFormatException followed by RuntimeException. The program has a compile error.