> Question 32 What is displayed on the console when running the following program? class Test{ public static void main(String[] args) { try { method(); System.out.println("After the method call"); } catch (Runtime Exception ex) { System.out.println("RuntimeException"); } catch (Exception ex) { System.out.println("Exception"); } } static void method () throws Exception { try { Strings = "5.6"; Integer.parseInt(s); // Cause a NumberFormatException int i = 0; int y = 2/i; System.out.println("Welcome to Java"); } catch (Runtime Exception ex) { System.out.println("RuntimeException"); } catch (Exception ex) { System.out.println("Exception"); } } The program displays RuntimeException followed by After the method call. The program has a compilation error. }
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- 1.public class Test{ public static void main(String args[]){ Person p = null; try{ } p.talk(); } catch (NullPointerException e) { System.out.print("There is a NullPointerException."); } catch(Exception e) { System.out.print("There is an Exception."); } System.out.print("Everything went fine."); } what will be the result if you run this program? O There is a NullPointerException. Everything went fine. O There is a NullPointerException. There is a NullPointerException. There is an Exception. This code will not compile, because in Java there are no pointers.void foo () { try { throw new Exception1 (); print (" A "); throw new Exception2 (); print (" B "); } catch ( Exception1 e1 ) { print " handler1 "; } print (" C "); throw new Exception2 (); } void main () { try { try { foo (); print (" D "); } catch ( Exception1 e1 ) { print " handler2 "; } print (" E "); } catch ( Exception2 e2 ) { print " handler3 "; } } Write down the output of the program and justify why it is the output. Instead of the “replacement” semantics of exception handling used in modern languages, a very early design of exception handling introduced in the PL/I language uses a “binding” semantics. In particular, the design dynamically tracks a sequence of “catch” blocks that are currently active; a catch block is active whenever the corresponding try block is active. What will be the output of the following program if the language uses the “binding” semantics? Give the reasoning for your answer.Code completion and explain. public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } }.
- A method can use the throws clause to pass the responsibility of handling any exceptions to the caller of the method. This is usually seen as better programming discipline than handling exceptions inside of methods. Why is that? In JAVA CODEpublic class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } } Complete and explain.Look at the following program and tell what it will output when run:public class ExceptionTest{public static void main(String[] args){int number;String str;try{str = "xyz";number = Integer.parseInt(str);System.out.println("A");}catch(NumberFormatException e){System.out.println("B");}catch(IllegalArgumentException e){System.out.println("C");}System.out.println("D");}}
- 3. What will be the output of the program? public class X { public static void main(String [] args) { try { badMethod (); System.out.print ("A"); } catch (Exception ex) { System.out.print ("B"); finally { System.out.print ("C"); System.out.print ("D"); public static void badMethod () throw new Error (); /* Line 22 */ А. АВCD B. Compilation fails. C. Cis printed before exiting with an error message. D. BC is printed before exiting with an error message.Checked exceptions in Java are those exceptions that are checked at compile time and must be either caught or declared in the method's throws clause. (True/False)Analyze the following code: public class Test{ public static void main(String[] args) { try { String s = "5.6"; Integer.parseInt(s); // Cause a NumberFormatException } } catch (Exception ex) { System.out.println("NumberFormatException"); int i = 0; int y = 2/i; } catch (RuntimeException ex) { } } System.out.println("RuntimeException"); The program displays NumberFormatException. The program displays RuntimeException. The program displays NumberFormatException followed by RuntimeException. The program has a compile error.
- What is displayed on the console when running the following program? public class Test{ public static void main(String[] args) { try { } catch (RuntimeException ex) { System.out.println("RuntimeException"); } catch (Exception ex) { System.out.println("Exception"); } } method(); System.out.println("After the method call"); static void method() throws Exception [ try { String s = "5.6"; Integer.parseInt(s); // Cause a NumberFormatException } int i = 0; int y = 2/i; System.out.println("Welcome to Java"); } catch (NumberFormatException ex) { System.out.println("NumberFormat Exception"); throw ex; } catch (RuntimeException ex) { System.out.println("RuntimeException"); } The program displays Number FormatException twice. The program displays NumberFormatException followed by After the method call. The program displays Number FormatException followed by RuntimeException. The program has a compile error.using System; namespace ErrorHandlingApplication{class DivNumbers{int result; DivNumbers(){result = 0;}public void division(int num1, int num2){try{result = num1 / num2;}catch (DivideByZeroException e){Console.WriteLine("Exception caught: {0}", e);}finally{Console.WriteLine("Result: {0}", result);}}static void Main(string[] args){DivNumbers d = new DivNumbers();d.division(25, 0);Console.ReadKey();}}} Modify this c# program on which enables users to enter value desired.Java Questions - (Has 2 Parts). Based on each code, which answer out of the choices "A, B, C, D, E" is correct. Each question has one correct answer. Thank you. Part 1 - The following code will cause a(n) ___ exception. class Sample{public static void main(String[] args) { int x = 0; int y = 10; int z = y/x; } } A. ArithmeticExceptionB. ArrayIndexOutOfBoundsExceptionC. StringIndexOutOfBoundsExceptionD. NullPointerExceptionE. ClassNotFoundException Part 2 - A programmer carelessly assigned a negative value as an index of an array. Which type of exception will be raised during execution? A. An IndexOutOfBoundsException is thrown.B. A NumberFormatException is thrown.C. The first slot of the array is used.D. This is an Error, so the program immediately terminates no matter what.E. The last slot of the array is used.