What is the output of following Java program: class Test extends Exception {} class Main { public static void main(String args) { try { throw new Test(); } } catch (Test t) { System.out.println("Got the Test Exception"); } finally { } System.out.println("Inside finally block ");
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- 1.public class Test{ public static void main(String args[]){ Person p = null; try{ } p.talk(); } catch (NullPointerException e) { System.out.print("There is a NullPointerException."); } catch(Exception e) { System.out.print("There is an Exception."); } System.out.print("Everything went fine."); } what will be the result if you run this program? O There is a NullPointerException. Everything went fine. O There is a NullPointerException. There is a NullPointerException. There is an Exception. This code will not compile, because in Java there are no pointers.Code completion and explain. public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } }.Java : Write the code segments in main( ) and in methodA( ) for the following scenario: main( ) passes methodA an int variable called a. methodA generates an exception, but does not deal with it, if a is not between 1 and 100. Hint: main will try and catch the exception and methodA throws exception.
- Look at the following program and tell what it will output when run:public class ExceptionTest{public static void main(String[] args){int number;String str;try{str = "xyz";number = Integer.parseInt(str);System.out.println("A");}catch(NumberFormatException e){System.out.println("B");}catch(IllegalArgumentException e){System.out.println("C");}System.out.println("D");}}// JumpinJive.java - This program looks up and prints the names and prices of coffee orders. // Input: Interactive. // Output: Name and price of coffee orders or error message if add-in is not found. import java.util.Scanner; public class JumpinJive { public static void main(String args[]) throws Exception { // Declare variables. String addIn; // Add-in ordered by customer. final int NUM_ITEMS = 5; // Named constant // Initialized array of add-ins. String addIns[] = {"Cream", "Cinnamon", "Chocolate", "Amaretto", "Whiskey"}; // Initialized array of add-in prices. double addInPrices[] = {.89, .25, .59, 1.50, 1.75}; boolean foundIt; int x; // Loop control variable. double orderTotal = 2.00; // All orders start with a 2.00 charge // Get user input. Scanner input = new Scanner(System.in); System.out.print("Enter coffee add-in or XXX to quit: "); addIn = input.nextLine();…Analyze the following code: public class Test{ public static void main(String[] args) { try { String s = "5.6"; Integer.parseInt(s); // Cause a NumberFormatException } } catch (Exception ex) { System.out.println("NumberFormatException"); int i = 0; int y = 2/i; } catch (RuntimeException ex) { } } System.out.println("RuntimeException"); The program displays NumberFormatException. The program displays RuntimeException. The program displays NumberFormatException followed by RuntimeException. The program has a compile error.
- 5) What would be the output of the following code?public class Solution{public static void main(String args[]) { try {throw 5;}catch(int e) {System.out.print("Exception: " + e);}finally {System.out.print("Finally");}}}A) Exception: 5 FinallyB) FinallyC) Compilation errorD) Exception: 0 FinallyJAVA EXCEPTION HANDLING:Define a new exception, called ExceptionLineTooLong, that prints out the error message "The strings is too long". Write a program that reads phrase and throws an exception of type ExceptionLineTooLong in the case where a string is longer than 80 characters. For example: Input Result The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped over the lazy dogs. The quick brown fox jumped over the lazy dogs.The quick brown fox jumped…Write in Java language (Constructor Failure) Write a program that shows a constructor passing information about constructor failure to an exception handler. Define class SomeClass, which throws an Exception in the constructor. Your program should try to create an object of type SomeClass and catch the exception that’s thrown from the constructor.
- in java, Explain what happens if an exception is not caught.void foo () { try { throw new Exception1 (); print (" A "); throw new Exception2 (); print (" B "); } catch ( Exception1 e1 ) { print " handler1 "; } print (" C "); throw new Exception2 (); } void main () { try { try { foo (); print (" D "); } catch ( Exception1 e1 ) { print " handler2 "; } print (" E "); } catch ( Exception2 e2 ) { print " handler3 "; } } Write down the output of the program and justify why it is the output. Instead of the “replacement” semantics of exception handling used in modern languages, a very early design of exception handling introduced in the PL/I language uses a “binding” semantics. In particular, the design dynamically tracks a sequence of “catch” blocks that are currently active; a catch block is active whenever the corresponding try block is active. What will be the output of the following program if the language uses the “binding” semantics? Give the reasoning for your answer.public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (RuntimeException ex) /* Line 10 */ { System.out.print("B"); } catch (Exception ex1) { System.out.print("C"); } finally { System.out.print("D"); } System.out.print("E"); } public static void badMethod() { throw new RuntimeException(); } } Complete and explain.