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- The following data are from the HPLC assay of paracetamol 500 mg tablets using the calibration curve method: - Weight of active ingredient in powdered tablets taken for analysis: 180 mg • Initial extraction volume: 200 mL - Dilution steps: 10 mL into 100 mL, then 5 mL into 100 mL - Linear equation: y = 12000x - 50 %3! - Area of chromatographic peak for sample is 4750. What is the theoretical concentration in final solution in mg/100 mL? (2 decimal places). Please do not write the units, just numerical value. Answer:percentage purity of an ibuprofen sample was determined by a reversed phase HPLC method as follows: Y Der ● A calibration curve of peak area versus concentration (ug/mL) of pure ibuprofen was constructed The ibuprofen sample for analysis was prepared by taking 10.0204 g of powder and dissolving it in/1Lbf distilled water (solution A). 1 ml of the latter solution was further diluted to IL with distilled water (solution B). Solution B was analysed by HPLC analysis Results The equation for the best-fit line of the calibration curve is: y=26820x-1323.8. ● The average peak area for the ibuprofen sample (solution B) was 266796.2 Calculate the percentage purity of the ibuprofen powder.50 Percentage Red No. 40 Soln 100% 80% 60% 40% Table 4.1: Dilutions of Red No. 40 & Absorbance Volume of Red No. 40 Soln (mL) 10me 8mL опи 4mL Percentage Red No. 40 Soln 100% 80% 60% 40% 20% Volume of DI Water (mL) OML 2mL LIML M UML 8ML Table 4.2: Dilutions of Red No. 40 & Absorbance Concentration Red No. 40 2. Report the wavelength with the maximum absorbance of Red No. 40 dye. Absorbance 20% 2ML Part A: Making a Calibration Curve for Beer's Law 1. Calculate the concentrations of each of your diluted Red No. 40 solutions and add these to Table 4.2. Show at least one sample calculation in the space below. 0.251 0.192 Total Volume 0.181 0·119 0.060 (mL) 10 mL 10 mL 10 mL 10 mL 10 mL
- Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72Com X Bb Mas X Mas X Hom X K! Kahx Exan X K! Kah X Mitc X КI Kah X K Kah x K! Kah x Kah x K Kahx C session.masteringchemistry.com/myct/itemView?assignmentProblemID=134214560 Apps New Tab Effect of Salinity on... Sleep Disorders | M... P Philo American Journal ... Zeeshan JBAS Ic Wait for Next Quest... oramge juice Effect cThe percentage purity of a paracetamol sample was determined by a reversed phase HPLC method as follows: • A calibration curve of peak area versus concentration (ug/mL) of pure paracetamol was constructed The paracetamol sample for analysis was prepared by taking 10.0254 g of powder and dissolving it in IL of distilled water (solution A). 1 mL of the latter solution was further diluted to 1L with distilled water (solution B). Solution B was analysed by HPLC analysis Results • The equation for the best-fit line of the calibration curve is: y = 26811x – 1313.8 The average peak area for the paracetamol sample (solution B) was 266796.2 Calculate the percentage purity of the paracetamol powder.A lab pair’s Beer’s Law calibration graph 0.08 < A < 0.79 had a best-fit line of A = 0.013 C – 0.023. Data was: off-scale for both the stock solution and solution #1 (10.00 mL stock diluted to 25.00 mL); solution #2 (1.00 mL stock diluted to 25.00 mL) had A = 0.85, and solution #3 (1.00 mL of solution #1 diluted to 25.00 mL) had A = 0.73. What are the concentrations of solution #3 and the stock solution?-). A new procedure for determining cholesterol in blood serum was used with a NIST standard sample producing the following results: 2.24, 2.21, 2.16, 2.21, and 2.19 mg/ml. If the NIST certified value is 2.12 mg/ml, determine if there a significant difference between the mean of the results and the certified or "true" value at the 95% confidence level?6. The concentration of caffeine in an energy soft drink was determined by standard addition using HPLC. The following procedure was used: a standard caffeine solution was prepared by adding 0.09850g of caffeine to 25.0 cm3 of water.A series of solutions were prepared by adding known volumes of the standard solution to the soft drink before diluting to 100 cm3. The volume of standard and the caffeine peak area are shown in the table: Energy Drink (cm3) Added caffeine Std (cm3) Peak area 15 0 965 15 5 1352 15 10 1739 15 15 2126 15 20 2513 Determine the concentration of caffeine in the soft drink as mg cm-3. A. 3.3 B. 2.3 C. 4.3 D. 7.3w juce Trials asked to determine the percentages of citric acid in the freshly squeezed and bottled lemon following data were obtained. Freshly Squeezed lemon juice 12 3 Volume of Titrant (ml) 1 25.5 Types of Lemon Juice Freshly Squezzed Bottled II 25.5 25.5 Bottled Lemon juice 12 1 18.5 Mass of 25 ml (g) 25.6 26.7 18.3 Click Save and Submit to save and submit. Click Save All Answers to save all answers. 3 Given that the molarity of NaOH is 1.10 M (after standardization with KHP), determine the mass of citric acid in the Bottled juice (8) 18.3 15°CHow many replicate measurements are needed to decrease the 95 and 99% confidence limits for the analysis de- scribed in Problem 7-7 to + 2.2 ug Fe/ml?A 500.0 μL aliquot of a ferric chloride solution is added to a 50.00 mL volumetric flask. To this flask is added 10 mL of 2M sodium acetate, 2 mL of 10 wt% NH4OCI, 3 mL of 5 wt% 1,10-phenanthroline, and enough DI water to fill the remaining volume of the flask for a total volume of 50.00 mL. Based on the UV-Visible light absorbance, the concentration of [Fe2+]=2.6 ppm. What is the concentration of Fe3+ ion in the original ferric chloride solution? O 3.85 X 103 ppm O 260.0 ppm O 260 ppm O 130 ppmSEE MORE QUESTIONS