Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the to const a calibration curve:
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- Question 13 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 µL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Peak Area Caffeine Benzoate Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Sheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0Question 15 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 µL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Peak Area Benzoate Caffeine Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…
- Question 16 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz 354.9 mL The following data were obtained: Peak Area Benzoate Caffeine Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Question 17 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Caffeine Peak Area Benzoate 3.54 Aspartame Std 1 2.30 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Question 14 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Caffeine Peak Area Benzoate 3.54 Aspartame Std 1 2.30 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…
- 22:12 Question 23 of 30 Submit How many grams of a solution that is 5.2 % sucrose by mass are needed to obtain 18 g of sucrose X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 18 100 g solution 3.5 6.022 x 1023 %m sucrose 0.052 5.2 g sucrose 94 350 0.0094 0.94 1 Tap here or pull up for additional resourcesCalculate the mass percent of the ascorbic acid in the same show full solution Situation: The pounded Vitamin C tablet was half into two below are the calculated data in the experiment. Each of the half are transfered in a 250ml erlen meyer flask and added 75ml of deionized water for the vitamin C to dissolve. Then it was prepared for titration where the burette was filled with 0.09794M standardize NaOH solution then a total of with 3 drops 2% phenolphthalein indicator was added to each erlen meyer flask l, swrill it and begin the titration. below are the following data gathered: Vitamins used: Nature Made vitamin C 500mg tablet Trial 1 Mass: 0.3108g of Vitamin C tablet Initial volume: 1.6mL Final volume: 15.4mL Trial 2 Mass: 0.3349g Initial volume: 15.4 mL Final volume: 30.2 mLSELECT correct responses only 1) Volume percent (v/v%) is temperature-independent. 2) There are three major approaches to expressing solution concentration in terms of percent concentration: weight percent, volume percent, and weight/volume percent. 3) Weight/volume percent (w/v%) is a unit-less quantity. 4) The term 'percent' refers to 'parts per thousand'. 5)A standard solution is a reagent of known concentration that is used to carry out a volumetric titration. 6) The endpoint of a titration is the theoretical point reached when the amount of added titrant is chemically equivalent to the amount of analyte in a sample. 7) A substance that changes color in response to chemical equivalence is known as an indicator. 8) Given a sufficiently diligent and experienced experimenter, it is sometimes possible to reach a titration volume error value of 0.
- 3:36 1 ull LTE O Send a chat What is the number of moles of glucose (C,H,206) in 0.500 of a 0.40 M solution? STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 36.04 0.020 1 0.40 0.20 1.3 180.18 0.500 6.022 x 1023 * Reflect in ePortfolioPrecipitimetry The chloride in a 4.321-g food sample was precipitated through the addition of 50.00 mL of a standard AgNO3 solution (10.00 mL AgNO3 = 11.22 mL KSCN). The precipitate was coated with nitrobenzene and the mixture was diluted to 250.0 mL. A 50.00 mL aliquot was taken from the diluted solution and required 4.56 mL back titration with a %3D standard KSCN solution (22.33 mL KSCN = 0.9758 g AgNO3). %3D Formula Masses: AgNO3 = 169.87; CI = 35.45 Calculate the following: 1. Molar concentration of KSCN solution M %3D 2. Molar concentration of AgNO3 solution M %3D 3. % (w/w) chloride in the original sample =Table 1: Volumes in of iodine in mL used to titrate mixtures of 10 mL of reaction mix and 10 mL of urine. student trial 1 trial 2 trial 3 total volume (mL) a 12.6 11.8 12.5 300 290 b. 10.6 10.7 10.6 11.1 118 12. 10.9 405 13.0 12.5 349 mg vit. C mL iodine TV (mL/hour) 10 mL urine aliquot TVC (mg/hour) =7 (mL) · CF !! What is the hourly vitamin C excretion rate (mg/h) of student b if the CF is 1.06? (include no more than two decimals in your answer, e.g.: 123.45, and do not type the units) 10.6 need ASAP