can someone answer this for me please? The following is the DNA sequence of the entire protein-coding region for some small gene in a eukaryote. Shown is the codingstrand. The first row is the original sequence with no mutations. Subsequent rows represent a single mutation.MutationDNA SequenceNone5'.ΑΤGCTGT GGA G сТА А.. 3'A5'..А Т G A C GCT GTG G A GCTA А.. 3'В5'..А Т GC G C T G T GA A G C T A A.. 3'C5' ..А TG GCGCT СТGGA GCTАA.. 3'The region without a mutation is transcribed, and then translated. Give the protein that is translated from this section of DNA. Usethe single letter abbriviations for amino acids with no spaces.N--CDetermine the molecular basis for each mutation and what effect there would be on the protein.Mutation Molecular BasisEffect on ProteinABCםם

Mutations in the DNA molecule are caused by a spontaneous alteration. After a synonym mutation, the…

The following is the DNA sequence of the entire protein-coding region for some small gene in a eukaryote. Shown is the codir strand. The first row is the original sequence with no mutations. Subsequent rows represent a single mutation. Mutation DNA Sequence None 5' ..А T GGCG C ТGTG GAGCT АА.. 3' A 5' ..A T G A C G C T GTG GAG C T A A.. 3' В 5' ..A T G G C G C T GTGA AG C T A A.. 3' C 5' ..А T GGCG C тстG GA GCT АА.. 3' The region without a mutation is transcribed, and then translated. Give the protein that is translated from this section of DNA. the single letter abbriviations for amino acids with no spaces.

The following is the DNA sequence of the entire protein-coding region for some small gene in a eukaryote. Shown is the codir strand. The first row is the original sequence with no mutations. Subsequent rows represent a single mutation. Mutation DNA Sequence None 5' ..А T GGCG C ТGTG GAGCT АА.. 3' A 5' ..A T G A C G C T GTG GAG C T A A.. 3' В 5' ..A T G G C G C T GTGA AG C T A A.. 3' C 5' ..А T GGCG C тстG GA GCT АА.. 3' The region without a mutation is transcribed, and then translated. Give the protein that is translated from this section of DNA. the single letter abbriviations for amino acids with no spaces.

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter10: Control Of Gene Expression

Section: Chapter Questions

Problem 4CT: The photos below show flowers from two Arabidopsis plants. The plant on the left is wild-type...

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5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. Write the resulting amino acid sequence using the 3 letter code. Write the answer in a all capital letters. Leave a space between the amino acids. Do not write 5' and 3'. 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G in Bold changes to a T, then the result will be A) A nonsense mutation B) A frameshift mutation C) A silent substitution D) A missense mutation 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G in Bold changes to a A, then the result will be A) A nonsenese mutation B) A frameshift mutation C) A silent substitution D) A missense mutation
The following is the DNA sequence of the entire protein-coding region for some small gene in a eukaryote. Shown is the coding strand. The first row is the original sequence with no mutations. Subsequent rows represent a single mutation. Mutation DNA Sequence None 5' ..A TGGGCGAGGT ATTATA G.. 3 5' ..A TGGGCGAGAT AT TA TA G.. 3' 5' ..A TGGGCGAG GTA CTATA G.. 3' C 5'..A TG GCCGAGG TATTATA G.. 3' The region without a mutation is transcribed, and then translated. Give the protein that is translated from this section of DNA. Use the single letter abbriviations for amino acids with no spaces. N- -C Determine the molecular basis for each mutation and what effect there would on the protein. Mutation Molecular Basis Effect on Protein
Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type: 5’ ATG GCT AGA GTC GAG TTG 3’ Mutant 1: 5’ ATG GCA GAG TCG AGT TG 3’ Mutant 2: 5’ ATG GCT TGA GTC GAG TTG 3’ Mutant 3: 5’ ATG GCT AGA GTT GAG TTG 3’ Mutant 4: 5’ ATG GCT AGA AGT CGA GTT G 3’ Mutant 5: 5’ ATG GCT AGA ATC GAG GTT 3’
Given Sequence: 3’-TACGGTCCGGATTCGGTAGCTAGCATC-5’ Provide: Complementary Strand: Transcript Amino Acid Sequence 2.Given Sequence: 5’-GGGCATATGCCGTTTACCGGTTTGACTAAATAACCA-3’ Provide: Complementary Strand: Transcript Amino Acid Sequence 3.Given Sequence: 3’-AAC CAA TAC GTG AGG ATA CCA AGT AAC ACT CCC-5’ Provide: Complementary Strand: Direct Transcript: Transcript for Translation: Amino Acid Sequence:
O The lac operon in E.coli encodes enzymes necessary for the breakdown of lactose. For each enzyme (lac Z and lac Y), indicate with a + or-whether or not it is made when there is no lactose or when there is lactose. B-galactosidase (lac Z) No Lactose Permease (lac Y) Lactose Lactose No Lactose Genotype PP0 Z Y/I P*O*Z•Y* I'POCZ Y*/I P* O©Z*Y° P O Z'Y/I P'OʻZ'Y* PP O ZY*/IP*O*Z*Y* IP OCZ Y /I P*O*Z•Y* IPO ZY*/I* P*O©Z*Y• I'PO*Z Y*/IP'O*Z*Y°
1 An Amino Acid Sequence Leu - Tyr - Gly-Gly - Val Which of the following changes to the mRNA that produces the amino acid sequence shown above would be characterized as a missense mutation? Select one: O A. CUC UAG GGU GGC GUA OB. CUC UAC GGG GGC GUA OC. CUC UAC GGU GGC GCU O D. CUC UAU GGU GGC GUA
Figure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5 TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5 46 77 90 5' AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 110 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5' 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3 ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. (i) Identify both the hexameric sequences of the promoter region in the coding strand above.
Figure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5' TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5' 46 5 AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5 77 90 110 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3' ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. Illustrate how termination of transcription occurs in the gene above. (Hint: position from 156 to 180)
Below is a DNA sequence of the coding strand for a small gene. This gene has no introns. +1 5'- TATAAGATGCGTAGGATGCAGCTGTTTCAGCAGCCACGGTCTCGGCCCAGATAGCAGATAATAAACACGC GTA-3 a. Is this gene for an eukaryote or a prokaryote? Give one reason (. b. How many amino acids are expected to be coded by this gene? c. There are five underlined nucleotide sequences, interpret the purpose of three of them ONLY?
EboV RNA from Guinea Pig EboV RNA from Guinea Pig GAU ACG UUC GUC AAU EboV DNA CTA TGC AAG CAG TTA Translated amino acids Asp Thr Phe Val Asn EboV Strain 1 EboV Strain 1 (Circle the mutated bases) CCA TGT AAG TGG TTA mRNA Protein Of the mutations you identified, how many are: _______substitutions __________ frameshifts The result of the caused by the mutation is (silent, missense, nonsense). Underline your answer.
EboV RNA from Guinea Pig EboV RNA from Guinea Pig GAU ACG UUC GUC AAU EboV DNA CTA TGC AAG CAG TTA Translated amino acids Asp Thr Phe Val Asn EboV Strain 2 EboV Strain 2 (Circle the mutated bases) TCA TGT CAG CAA CTA mRNA Protein Of the mutations you identified, how many are: _______substitutions __________ frameshifts The result of the caused by the mutation is (silent, missense, nonsense). Underline your answer.
Shown below is an E. coli's DNA sequence coding for XXR protein. The nucleotides are numbered 1 to 330. Transcription starts at the Transcription Start Site (TSS) that is the base located at position 57. -55 5' AATAAСTTGAGATTTTGATTGACАТССТТСТСАCAGAGCCTATAATACCТАТТТС 3' 3'TТАТTGAACTСТААААСТААСТGTAGCAACAGTGTCТСGGATATTATGGATAAAG 5' 56- 5' ТACGTATAGAСАСТСAGAGGAAAGACAGAGAGAGAGTTAGCATTGTACTАТСТСТ 3' 3' АTGCATATСТсTGAGTCTCCTTтстстстстстсТСААТСGTAACATGATAGAGA 5' 65- -105 --110 -140- 5' СТTTTAGATATATCTCТАТСТСТСТСАСТССАТСТТТСТCGTGTTAACACAAСА 3' 3' GAAAATCTATАTAGAGATAGAGAGAAGTGAGGTAGAAAGAGCACAAТТСTСТTGT 5' 111- -120- -130- -150- -160----165 166- --175- --185- -195 -205- -215-----220 ------- 5' GTCACAGACTCACAGATCTTTGTCGGTGATCGGAGATGGAGTTCCGGGAGAAGCT 3' 3' CAGTGTCTGAGTGTCТAGAAACAGCCACTАGССТСТАССТСААGGCCCTСТТCGA 5' 221- -230- 240 -250 -260 -270-----275 5' TTATAAGTTCAAGTTGCAATAGGTGTTTGCCTTTGTTTTATCTCTCCTCACCGTA 3' 3'ААТАТТСААGTTCAACGTTATCCАCAAACGGAAACAAAАТAGAGAGGAGTGGCAT 5' 276- -285- -295- -305 -315…