If CS=2000 H, DS=4000 H, SS=6000 H, ES=9000 H, BX=1358 H, BP=2122 H, SP=3500 H, SI=4100 H, DI=5147 H, IP=1547 H; Mention the addressing mode and calculate the 20 bit physical address of the instruction: MOV [BX+SI+1597H], AH
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A: Given:
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- A segment at an absolute address like 40h must be defined in some way.Calculate the Physical and offset address of the following registers . i. SS: 3860H, SP: 1735H, BP: 4826H ii. BX: 2025H , IP: 0580H , DI: 4247H iii. CS=1111H, DS=3333H, DI=0020HWhat is the addressing mode for each of the following. MOV CX, [SI] MOV CX, [DI + 0A2H] JZ 0CH MOV CL, DH MOV DX, [BP + DI + 0CH] MOV DL, 08H MOV BX, [1354H] MOV AX, [BX + 08H]
- 28 A paging scheme uses a TLB. A TLB access takes 10ns and main memory access takes 50ns. What is the effective access time (in ns) if the TLB hit ratio is 90%? 50 65 70 55For a computer system, which utilizes pure segmentation, segmentation table and list of virtual addresses (a: segment number, b: offset) are given below. Please, write corresponding physical addresses for each virtual address given: Segment No Base Limit 219 600 a. 0,430 1 2300 14 b. 1,10 90 100 c. 2,500 3 1327 580 d. 3,400 4 1952 96 e. 4,112 -----According to the following table if the destination address is 11001000 00010111 00011100 10101010 Destination Address Range Link interface 11001000 00010111 00010*** ********* 11001000 00010111 00011000 ********* 1 11001000 00010111 00011*** ***** 2 otherwise 3 The link interface will be O A 1 OB. 3 OC. O D.0
- A system using segmentation provides the segment below. Compute the physical address for each of the logical addresses. If the address generates a segment fault, indicate so а. 0, 323 b. 1, 856 C. 2, 234 d. 3, 1009 е. 2, 533 Length 400 900 Segment Base 1311 1 2711 2 411 500 3 4211 1100On a system using simple segmentation, compute the physical address for each of the logical addresses, given the following segment table. If the address generates a segment fault, indicate SO Length 500 Segment Base 1100 1 2500 1000 200 600 3 4000 1200 а. 0, 300 b. 2, 800 C. 1, 600 d. 3, 1100 е. 1, 1111The MC68000 standard stipulates which types of destination name addressing are prohibited and why.
- How many address bits are required if a total of 1024K words are to be stored?What is the effective address generated by thefollowing combinations if they are valid. If not give reason.Initially BX=0x0100, SI=0x0010, DI=0x0001,BP=0x0200, andSP=0xFFFF a- bx-si b- bx-bp c- bx+10 d- bx-10 e- bx+sp- f- bx+diConsider a simple segmentation system that has the following segment table: Starting Address Length (bytes) 830 346 110 110 1,508 408 770 812 For each of the following logical addresses, determine the physical address or indicate of a segment fault occurs: а. 0,228 b. 2,648 с. 3,776 d. 1,98