10110; BR = 11100111; CR = 10110001; DR = 10111010 Determine the 8-bit values in each register after the execution of the following sequence of microopera
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The 8-bit register AR, BR, CR, and DR initially have the following values: [5]
AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010
Determine the 8-bit values in each register after the execution of the following sequence
of microoperations.
AR AR + BR Add BR + AR
CR CR AND DR, BR BR + 1 AND DR to CR, Increment BR
AR AR - CR Subtract CR from AR
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- A(n) __________ is a storage location implemented in the CPU.The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010010; BR = 11111111; CR = 10101001; DR = 10101010Determine the 8-bit values in each register after the execution of the following sequence ofmicrooperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from ARThe 8-bit register AR, BR, CR, and DR initially have the following values: AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR AR + BR Add BR + AR CR CR AND DR, BR BR + 1 AND DR to CR, Increment BR AR AR - CR Subtract CR from AR
- Design a binary multiplier that multiplies two 8-bit binary number by following design rules that shown in class. The Q and B are the two separate 8-bit binary inputs, C is the 3-bit sequence counter and R is the 16-bit result. (Note: Explain the registers that you will use to establish given process.)(Hint: Morris Mano, Computer System Architecture, Chapter 10.6.) QxB B Clock Start -Busy/ReadyThe 8-bit register AR, BR, CR, and DR initially have the following values:AR = 11010010; BR = 11111111; CR = 10101001; DR = 10101010Determine the 8-bit values in each register after the execution of the following sequence ofmicrooperations.AR <- AR + BR Add BR + ARCR <- CR AND DR, BR <- BR + 1 AND DR to CR, Increment BRAR <- AR - CR Subtract CR from ARIdentify the addressing modes & the value of the register Ro for each of given instructions if initial values of Ro= 1500, R1=3000, PC = 4000. ADDRESS VALUE 1000 1260 2000 1570 2900 1400 3000 1650 4000 1750 4102 1150 4500 1760 5000 1850 i) Ld Ro. #125 11) Ld. Ro. [3000] i11) Ld Ro. [Ri] iv) Ld Ro. -100[Ri] v) Ld Ro. [PC+100]
- LIST P = 16F877AUsing INCLUDE "P16F877A.INC" and PWM (Pulse Width Modulation), write the microprocessor code that enables the fan to operate at 80% if the button on the 5th bit is pressed, and 30% if the button on the third bit is pressed.For the given values of D, shr, shr_in, Id, and clk, indicate the register's Q value. Dis 111, shr_in is 0, shr is 1, Id is 0, and Q is 101. clk rises. What does Q become? Function table thr Id | Register function IP shr in- 0 0 Maintain 01Lood 0 Shuft-right 1Maintain 13 12 i1 0 13 12 it 0 13 12 it 10 she st 4xl 4x1 4xl Block ymbol DFF OFF DFF to she in 3-bit ahift-rht/lend ragister she at ahirightad ld Pegiter O 010 O 110 O 101 O 111Q2- Write a program in assembly language for the 8085 microprocessor to receive one byte of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When receive the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception(start bits 1 1 ), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit 0 ). The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay time
- Q5 Please convert the following C/C++ function to RISC-V assembly (RV321). Function: swap Registers: ra = x1 (return address) &v[0] -> a0 = x10 (arguments/return values) k-> a1 = x11 (arguments/return values) to = x5 (temporary) t1 = x6 (temporary) t2 = x7 (temporary) hint: void swap(int v[], int k) { int temp; temp = v[k]; v[k] = v[k+1]; v[k+1] = temp; %3D }Part 3: Putting it all together Consider the situation where the EAX and EBX registers are storing the values listed below. EAX: 01100001 10101110 00101111 11111111 EBX: 11101010 00000000 00000010 10101101 We want to add the values of EAX and EBX together. When we perform this addition, the result is stored EBX, overwriting the value that was already in there. What is the result of the addition stored in EBX? Give your result in binary. What value is stored in BL? Give your result in hexadecimal. What flags are set after the operation is complete?The 8-bit register AR, BR, CR, and DR initially have the following values:AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequence of microoperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR
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