Given the following state of memory (in hexadecimal), answer the following questions for the instructions given in Pep/9 assembly language. Memory Address: Memory Contents: 00F1 4A 00F2 D1 00F3 29 00F4 C6 a. What are the contents of the A register in binary after the execution of the instructions: LDBA 0x00F1, i ADDA 0x00F2, d b. What are the contents of the A register in binary after the execution of the instructions: LDWA 0x00F3, d ADDA 0x0104, i

Given the following state of memory (in hexadecimal), answer the following questions for the instructions given in Pep/9 assembly language. Memory Address: Memory Contents: 00F1 4A 00F2 D1 00F3 29 00F4 C6 a. What are the contents of the A register in binary after the execution of the instructions: LDBA 0x00F1, i ADDA 0x00F2, d b. What are the contents of the A register in binary after the execution of the instructions: LDWA 0x00F3, d ADDA 0x0104, i

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 26VE: _____ is a CPU design technique in which instruction execution is divided into multiple stages and...

See similar textbooks

Similar questions

Most Intel CPUs use the __________, in which each memory address is represented by two integers.
_____ is a CPU design technique in which instruction execution is divided into multiple stages and different instructions can execute in different stages simultaneously.
Given the following state of memory (in hexadecimal), answer the following questions for the instructions given in Pep/9 machine language. Memory Address: Memory Contents: 00310B0032 0033 0034A3 08 3Fa. What are the contents of the A register in binary after the execution of the instruction: 1101 0001 0000 0000 0011 0001b. What are the contents of the A register in binary after the execution of the instruction: 1100 0001 0000 0000 0011 0011c. What are the contents of the A register in binary after the execution of the two instructions: 1101 0001 0000 0000 0011 0010 0110 0000 0000 0000 0011 0100d. What are the contents of the A register in binary after the execution of the two instructions: 1101 0000 0000 0000 0011 0001 0110 0001 0000 0000 0011 0011
Use the Fetch Decode Execution steps to execute the assembly language into machine instructions and execute the instruction as the computer would. Explain into detail what happens during the execution of each statement. # Machine Code 0 001 1 111100 1 010 0 110000 2 001 1 101000 3 010 0 110111 4 001 0 110000 5 011 0 110111 6 010 0 111000 7 111 0 000000 Mnemonics Table Op-Code Mnemonics 001 LOAD 010 STORE 011 ADD 100 SUB 101 EQUAL 110 JAMP 111 HALT
Use the Fetch Decode Execution steps to execute the assembly language into machine instructions and execute the instruction as the computer would. Explain into detail what happens during the execution of each statement. # machine code 0 001 1 111100 1 010 0 110000 2 001 1 101000 3 010 0 110111 4 001 0 110000 5 011 0 110111 6 010 0 111000 7 111 0 000000 Mnemonics Table
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word ofmemory.a. How many bits are needed for the opcode?b. How many bits are left for the address part of the instruction?c. What is the maximum allowable size for memory?d. What is the largest unsigned binary number that can be accommodated in one word of memory?
Use the Fetch Decode Execution steps to execute the assembly language into machine instructions and execute the instruction as the computer would. Explaininto detail what happens during the execution of each statement. # Machine code0 001 1 1111001 010 0 1100002 001 1 1010003 010 0 1101114 001 0 1100005 011 0 110111 6 010 0 111000 7 111 0 000000 Mnemonics Table
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory.Q.) How many bits are left for the address part of the instruction?
A computer has a 256K word addressable memory Module with 16 bits per word. The instruction set consists of 166 different instructions. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. Based on the above, answer the following questions: a. How many bits are there in the main memory? (Represent it in power of 2) b. How many bits are needed for the opcode? c. How many bits are left for the address part of the instruction? d. How many additional instructions can be added to the existing 166 without affecting the assigned size of the opcode part? Justify.
Use the Fetch Decode Execution steps to execute the assembly language into machine instructions and execute the instruction as the computer would. Explain into detail what happens during the execution of each statement.#Machine code0 001 1 1111001 010 0 1100002 001 1 1010003 010 0 1101114 001 0 1100005 011 0 1101116 010 0 1110007 111 0 000000
0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.
Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the assembly program's instruction set consists of 198 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. a. How many bits are needed for the opcode? b. How many bits are left for the address part of the instruction? c. How many additional instructions could be added to this instruction set without exceeding the assigned number of bits? Discuss and show your calculations.