Consider the cell. Cu Cu²+ (0.00576 M) Pb2+ (0.00668 M) Pb Calculate the half-cell reduction potential at 298 K at the cathode. 0.2738 Ecathode = V Incorrect Calculate the half-cell reduction potential at 298 K at the anode. -0.0657 Eanode = V Incorrect What is the initial potential needed to provide a current of 0.0700 A if the resistance of the cell is 4.68 Q? Assume that T = 298 K. 0.3276 Eapplied V Incorrect

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