A force of 130 N, tilted upwards at an angle of 36.9 from the horizon, acts on a body of mass 40 kg placed on a rough horizontal surface with a coefficient of friction of 0.2, as in the figure below. Calculate the magnitude of the frictional force and acceleration of the body. F sine F = 130N 36.9° F cos

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.81P: Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center...
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A force of 130 N, tilted upwards at an angle of 36.9 from the
horizon, acts on a body of mass 40 kg placed on a rough horizontal
surface with a coefficient of friction of 0.2, as in the figure below.
Calculate the magnitude of the frictional force and acceleration of the
body.
F₁
F sine
F = 130N
36.9°
F cos 0
Transcribed Image Text:A force of 130 N, tilted upwards at an angle of 36.9 from the horizon, acts on a body of mass 40 kg placed on a rough horizontal surface with a coefficient of friction of 0.2, as in the figure below. Calculate the magnitude of the frictional force and acceleration of the body. F₁ F sine F = 130N 36.9° F cos 0
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