3. Each of the two channels of the power supply pictured here can provide 30 V, but we want to run a 60 V hair dryer motor. So we put the two channels in series for double the voltage. Only "isolated" or "floating" supplies can do this safely (i.e., the supplies are initially electrically separate from each other). The following circuit represents isolated supplies hooked up to supply the dryer. Isolated Power Supply Channel2 30V 3.3A max Droop2 Red 1mQ Channel1 30V 3.3A max Droop1 I mi 1m0 Black Red Black JumperCable >26mQ 15A max (Continued on next page.) Motor 1200 Needs -60V (a) Show that the voltage across the motor is close to 60 V. (b) Show that the current through the supply channels is below their maximum current rating. (c) Show that the total power that leaves the power supply is less than the 195 W maximum for the Rigol DP832 power supply.

3. Each of the two channels of the power supply pictured here can provide 30 V, but we want to run a 60 V hair dryer motor. So we put the two channels in series for double the voltage. Only "isolated" or "floating" supplies can do this safely (i.e., the supplies are initially electrically separate from each other). The following circuit represents isolated supplies hooked up to supply the dryer. Isolated Power Supply Channel2 30V 3.3A max Droop2 Red 1mQ Channel1 30V 3.3A max Droop1 I mi 1m0 Black Red Black JumperCable >26mQ 15A max (Continued on next page.) Motor 1200 Needs -60V (a) Show that the voltage across the motor is close to 60 V. (b) Show that the current through the supply channels is below their maximum current rating. (c) Show that the total power that leaves the power supply is less than the 195 W maximum for the Rigol DP832 power supply.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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