QUESTIONProvide a detailed theory, discussion, and conclusion for the activity in the document below. Laboratory Exercise 1 | Numbers and DisplaysThis is an exercise in designing combinational circuits that can perform binary-to-decimal numberconversion and binary-coded-decimal (BCD) addition, using Proteus Design Suite.Part IFigure 1a shows a sum-of-products circuit that implements a 2-to-1 multiplexer with a select input s.Ifs=0 the multiplexer's output is equal to the input x, and if s = 1 the output is equal to y. Figure1b gives a truth table for this multiplexer, and part c shows its circuit symbol.a) CircuitVX3Y3x₂.2 -xoYoCoutYou are to use four instances of the circuit shown above to create the circuit given in Figure 2a. Thiscircuit has two four-bit inputs, X and Y, and produces the four-bit output M. If s = 0 then M = X, whileif s = 1 then M = Y. We refer to this circuit as a four-bit wide 2-to-1 multiplexer. It has the circuitsymbol shown in Figure 2b, in which X, Y, and M are depicted as four-bit wires.mComparator9Circuit ASum3FullAdder3AFigure 1: A 2-to-1 multiplexerBm3a) Circuitb) SymbolFigure 2: A four-bit wide 2-to-1 multiplexerCinm₂moPart IIYou are to design a circuit that converts a four-bit binary number V = √3v2v₁v0 into its two-digitdecimal equivalent D - dido. Table 1 shows the required output values. A partial design of thiscircuit is given in Figure 3. It includes a comparator that checks when the value of V is greater than 9and uses the output of this comparator in the control of the 7-segment displays. You are to completethe design of this circuit.C₂ZA100110101011S011100110111101111b) Truth tableV3V2V1V0 d₁ do0000 0 00001010010 0 2Table 1: Binary-to-decimal conversion values.The output z for the comparator circuit can be specified using a single Boolean expression, with thefour inputs V3-0. Design this Boolean expression by making a truth table that shows the values ofthe inputs V3-0 for which z must be 1.FullAdder2Sumzm4XyXY1C₂10 901210634501SumFullAdder₁Figure 3: Partial design of the binary-to-decimal conversion circuitNotice that the circuit in Figure 3 includes a 4-bit wide 2-to-1 multiplexer. The purpose of thismultiplexer is to drive digit do with the value of V when z = 0, and the value of A when z = 1. Todesign circuit A, consider the following. For the input values V≤ 9, circuit A does not matter,because the multiplexer in Figure 3 just selects V in these cases. But for the input values V 9, themultiplexer will select A. Thus, A must provide output values that properly implement Table 1 when V 9. You need to design circuit A so that the input V = 1010 gives an output A = 0000, the input V =1011 gives the output A = 0001, ..., and the input V = 1111 gives the output A = 0101. Designcircuit A by making a truth table with the inputs V3-0 and the outputs A3-0.Part IIIYou are to design a circuit that adds the two BCD digits. The inputs to your circuit are the numbers Xand Y, plus a carry-in, cin. You should use the four-bit ripple-carry adder/subtractor (RCAS4) circuitin Figure 4 below to produce a four-bit sum and carry-out for the operation X + Y. This result is to bedisplayed on 7-segment displays as a two-digit sum S₁So. For a sum equal to zero you would displayS₁S0 = 00, for a sum of one S₁S0 = 01, for nine S₁S0 = 09, for ten S₁S0 = 10, and so on. Note that theinputs X and Y are assumed to be decimal digits, which means that the largest sum that needs to behandled by this circuit is S₁S0 = 9 + 9 + 1 = 19.C₁GMFullAdderoSumo0Figure 4 Schematic diagram 4-bit ripple-carry adder/subtractor (RCAS4)c) SymbolSumCoutFigure 5 Circuit diagram for a full adder4d₁06m063112|-||~||~||

Question

QUESTIONProvide a detailed theory, discussion, and conclusion for the activity in the document below. Laboratory Exercise 1 | Numbers and DisplaysThis is an exercise in designing combinational circuits that can perform binary-to-decimal numberconversion and binary-coded-decimal (BCD) addition, using Proteus Design Suite.Part IFigure 1a shows a sum-of-products circuit that implements a 2-to-1 multiplexer with a select input s.Ifs=0 the multiplexer's output is equal to the input x, and if s = 1 the output is equal to y. Figure1b gives a truth table for this multiplexer, and part c shows its circuit symbol.a) CircuitVX3Y3x₂.2 -xoYoCoutYou are to use four instances of the circuit shown above to create the circuit given in Figure 2a. Thiscircuit has two four-bit inputs, X and Y, and produces the four-bit output M. If s = 0 then M = X, whileif s = 1 then M = Y. We refer to this circuit as a four-bit wide 2-to-1 multiplexer. It has the circuitsymbol shown in Figure 2b, in which X, Y, and M are depicted as four-bit wires.mComparator>9Circuit ASum3FullAdder3AFigure 1: A 2-to-1 multiplexerBm3a) Circuitb) SymbolFigure 2: A four-bit wide 2-to-1 multiplexerCinm₂moPart IIYou are to design a circuit that converts a four-bit binary number V = √3v2v₁v0 into its two-digitdecimal equivalent D - dido. Table 1 shows the required output values. A partial design of thiscircuit is given in Figure 3. It includes a comparator that checks when the value of V is greater than 9and uses the output of this comparator in the control of the 7-segment displays. You are to completethe design of this circuit.C₂ZA100110101011S011100110111101111b) Truth tableV3V2V1V0 d₁ do0000 0 00001010010 0 2Table 1: Binary-to-decimal conversion values.The output z for the comparator circuit can be specified using a single Boolean expression, with thefour inputs V3-0. Design this Boolean expression by making a truth table that shows the values ofthe inputs V3-0 for which z must be 1.FullAdder2Sumzm4XyXY1C₂10 901210634501SumFullAdder₁Figure 3: Partial design of the binary-to-decimal conversion circuitNotice that the circuit in Figure 3 includes a 4-bit wide 2-to-1 multiplexer. The purpose of thismultiplexer is to drive digit do with the value of V when z = 0, and the value of A when z = 1. Todesign circuit A, consider the following. For the input values V≤ 9, circuit A does not matter,because the multiplexer in Figure 3 just selects V in these cases. But for the input values V> 9, themultiplexer will select A. Thus, A must provide output values that properly implement Table 1 when V> 9. You need to design circuit A so that the input V = 1010 gives an output A = 0000, the input V =1011 gives the output A = 0001, ..., and the input V = 1111 gives the output A = 0101. Designcircuit A by making a truth table with the inputs V3-0 and the outputs A3-0.Part IIIYou are to design a circuit that adds the two BCD digits. The inputs to your circuit are the numbers Xand Y, plus a carry-in, cin. You should use the four-bit ripple-carry adder/subtractor (RCAS4) circuitin Figure 4 below to produce a four-bit sum and carry-out for the operation X + Y. This result is to bedisplayed on 7-segment displays as a two-digit sum S₁So. For a sum equal to zero you would displayS₁S0 = 00, for a sum of one S₁S0 = 01, for nine S₁S0 = 09, for ten S₁S0 = 10, and so on. Note that theinputs X and Y are assumed to be decimal digits, which means that the largest sum that needs to behandled by this circuit is S₁S0 = 9 + 9 + 1 = 19.C₁GMFullAdderoSumo0Figure 4 Schematic diagram 4-bit ripple-carry adder/subtractor (RCAS4)c) SymbolSumCoutFigure 5 Circuit diagram for a full adder4d₁06m063112|-||~||~||

Accepted Answer

PART I:
SOLUTION: 
different methods to make This
method 1:
module mux2_1_8_bit(X,Y,S,out);
input…