Concept explainers
a.
To calculate center and spread of data.
a.
Answer to Problem 10.8STP
Median of M is more than E
Explanation of Solution
Given information:
Calculation:
Data set of M: 3, 5, 5, 6, 7, 9, 10, 10, 13, 14, 19, 23, 28, 32, 35, 35, 35, 36, 37, 37, 39, 40, 40, 41, 41, 41, 42, 44, 46, 60, 63, 67
From above data median of M=35
Data set of E: 9, 16, 16, 17, 18, 19, 19, 19, 20, 21, 22, 22, 23, 24, 26, 27, 28, 30, 31, 33, 34, 45, 46
From above data median of E=22.5
Median of M is more than E
b.
To tell about spread of data set.
b.
Answer to Problem 10.8STP
Spread of M is greater than E
Explanation of Solution
Given information:
Data set of M: 3, 5, 5, 6, 7, 9, 10, 10, 13, 14, 19, 23, 28, 32, 35, 35, 35, 36, 37, 37, 39, 40, 40, 41, 41, 41, 42, 44, 46, 60, 63, 67
Data set of E: 9, 16, 16, 17, 18, 19, 19, 19, 20, 21, 22, 22, 23, 24, 26, 27, 28, 30, 31, 33, 34, 45, 46
Calculation:
For M
Q1=10
Q3=41
IQR=41-10=31
For E
Q1=19
Q3=28
IQR=28-19=9
Spread of M is greater than E
c.
To explain does data sets appears to be normal.
c.
Answer to Problem 10.8STP
E is appear to be approximate
M is does not appear to be approximate normally
Explanation of Solution
Given information:
E is appear to be approximate normally distributed data set because spread of both side of median is symmetric
M is does not appear to be approximate normally distributed data set because spread of both side of median is not symmetric
Chapter ISG Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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