Thermodynamics, Statistical Thermodynamics, & Kinetics
Thermodynamics, Statistical Thermodynamics, & Kinetics
3rd Edition
ISBN: 9780321766182
Author: Thomas Engel, Philip Reid
Publisher: Prentice Hall
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Chapter 8, Problem 8.20NP
Interpretation Introduction

Interpretation: The normal boiling point and the normal standard point are to be calculated for liquid benzene. Whether the obtained result agrees with the value in the mentioned table or not should be explained.

Concept introduction: Normal boiling point is the point when the pressure becomes equal to 1 atm . The standard boiling point is the point when the pressure becomes equal to 1 bar . According to the Clausius Clapeyron equation, the rate at which the natural logarithm of the vapor pressure of a particular liquid changes with temperature is calculated by using the enthalpy of vaporization of the liquid, universal gas constant, and temperature of the system.

  lnP2P1=ΔHvaporizationR1T11T2

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1. Assume the molar Gibbs free energy of a gas is given by the equation: Gm - RT In(÷)+ (a + bT)P = 0, where po is the standard pressure and a and b are gas-dependent constants. Derive an equation of state for this gas. Show the final result in the form of PV=?.
At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2 D(g) were found to be PA 5.61 atm, PB = 4.31 atm, Pc = 5.66 atm, and P = 5.84 a %3D %3D What is the standard change in Gibbs free energy of this reaction at 25 °C? kJ AGixn mol
The standard enthalpy of formation of gaseous H₂0 at 298 K is -241.82 kJmol-¹. Estimate its value at 100 °C. Cp,H₂0 = 33.58 Jmol¯¹K−¹ Cp,H, = 28.84 Jmol-¹K-1 Cp,0₂ = 29.37 Jmol-¹K-¹

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Thermodynamics, Statistical Thermodynamics, & Kinetics

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