Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 6.6, Problem 13P
Interpretation Introduction
(a)
Interpretation: Whether the starting material or product is favored at equilibrium is to be predicted on the basis of the given value of
Concept introduction: The change in Gibbs free energy and enthalpy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.
Interpretation Introduction
(b)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy and enthalpy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.
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Students have asked these similar questions
Considering each of the following values and neglecting entropy, tell whether the starting material or product is favored at equilibrium: (a) ΔHo = 80 kJ/mol; (b) ΔHo = −40 kJ/mol.
Given each of the following values, is the starting material or product favored at equilibrium?
a. Keq = 5.5
b.ΔGo = 40 kJ/mol
Given each value, determine whether the starting material or product is favored at equilibrium.
a. Keq = 0.5
b. ΔG° = −100 kJ/mol
c. ΔH° = 8.0 kJ/mol
d. Keq = 16
e. ΔG° = 2.0 kJ/mol
f. ΔH° = 200 kJ/mol
g. ΔS° = 8 J/(K · mol)
h. ΔS° = −8 J/(K · mol)
Chapter 6 Solutions
Organic Chemistry (6th Edition)
Ch. 6.2 - Prob. 2PCh. 6.3 - Problem 6.3 By taking into account...Ch. 6.3 - Problem 6.4 Use curved arrows to show the movement...Ch. 6.3 - Problem 6.5 Follow the curved arrows and draw the...Ch. 6.4 - Prob. 6PCh. 6.4 - Problem 6.7 Use the values in Table 6.2 to...Ch. 6.4 - Prob. 8PCh. 6.5 - aWhich Keq corresponds to a negative value of G,...Ch. 6.5 - Given each of the following values, is the...Ch. 6.5 - Given each of the following values, is the...
Ch. 6.5 - The equilibrium constant for the conversion of the...Ch. 6.6 - Prob. 13PCh. 6.6 - For a reaction with H=40kJ/mol, decide which of...Ch. 6.6 - For a reaction with H=20kJ/mol, decide which of...Ch. 6.7 - Draw an energy diagram for a reaction in which the...Ch. 6.7 - Prob. 17PCh. 6.7 - Prob. 18PCh. 6.8 - Problem 6.19 Consider the following energy...Ch. 6.8 - Draw an energy diagram for a two-step reaction,...Ch. 6.9 - Which value if any corresponds to a faster...Ch. 6.9 - Prob. 22PCh. 6.9 - Problem 6.23 For each rate equation, what effect...Ch. 6.9 - Prob. 24PCh. 6.10 - Identify the catalyst in each equation. a....Ch. 6 - Draw the products of homolysis or heterolysis of...Ch. 6 - Explain why the bond dissociation energy for bond...Ch. 6 - Classify each transformation as substitution,...Ch. 6 - Prob. 29PCh. 6 - 6.31 (a) Add curved arrows for each step to show...Ch. 6 - Prob. 35PCh. 6 - 6.39. a. Which value corresponds to a negative...Ch. 6 - Prob. 40PCh. 6 - For which of the following reaction is S a...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - 6.44 Consider the following reaction: .
Use curved...Ch. 6 - Prob. 45PCh. 6 - 6.50 The conversion of acetyl chloride to methyl...Ch. 6 - Prob. 50PCh. 6 - Prob. 53P
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- Given each of the following values, is the starting material or product favored at equilibrium?A.) Keq = 5.5b.) ΔGo = 40 kJ/molarrow_forward2) The equilibrium constant Ke for the reaction A B is 1 x 105 at room temperature (25°C). a) You make a solution containing compound A at a concentration of 1 M and compound B at a concentration of 1 mM of B, and let the reaction proceed to equilibrium. What are the equilibrium concentrations of A and B? b) Calculate the standard free-energy change (AG) for this reaction. c) What is the standard free-energy change (AG) for the inverse reaction (BA)?arrow_forwardFor each of the following processes predict the sign of AS for the reaction. In other words, will AS sys be positive (an increase in entropy) or negative (a decrease in entropy)? AS sys is expected to be positive (an increase in entropy) because one molecule is converted into two molecules. AS sys is expected to be negative (a decrease in entropy) because a cyclic compound is converted into acyclic compounds. O AS sys is expected to be positive (an increase in entropy) because an acyclic compound is converted into cyclic compounds. O AS sys is expected to be negative (a decrease in entropy) because two molecules are converted into one molecule.arrow_forward
- Calculate the energy change of the following reaction: 2NO + O2→ 2NO2 ΔH: NO = 90.0 kJ/mol NO2= 34.0 kJ/mol O2= 0.0 kJ/mol a -180 kJ b -112 kJ c 35.0 kJ d -248 kJarrow_forwardCalculate A,H for the following reaction: 5C(s) + 6H2(9) → C5H12(1) Use the following reactions and given ArH's. C5H12 (1) + 8 O2(g) → 5CO2(g) + 6H2O(g), A;H = -3505.8 kJ mol C(s) + 02(g) → CO2(g), ArH = -393.5 kJ mol1 2H2(g) + O2(9) → 2H2O(g) , A¡H = -483.5 kJ molarrow_forwardDiscuss the conditions needed to have a reaction with gaseous reagents and gaseous products so that The value of Kp increases with increasing temperature The value of ΔG° increases with increasing temperature The value of k increases with increasing temperature The conversion of one of the reagents increases with increasing pressurearrow_forward
- Which value (if any) corresponds to a faster reaction: (a) Ea = 40 kJ/mol or Ea = 4 kJ/mol; (b) a reaction temperature of 0 °C or a reaction temperature of 25 °C; (c) Keq = 10 or Keq = 100; (d) ΔH° = −10 kJ/mol or ΔH° = 10 kJ/mol?arrow_forward9C (s) + 12H2 (g) + 3/2 O2 (g) → 3C3H7 OH (1) The enthalpy change is -954 kJ and entropy increases. Using Le Chatelier's Principle, check all of the following disturbances that would allow you to obtain more propanol. increase temperature decrease temperature increase pressure decrease pressure increase hydrogen concentration remove product add carbon increase oxygen concentrationarrow_forward1A)Given the following value, tell whether the starting material or product is favored at equilibrium. Keq = 6 A. Starting material favored B. Product favored 2B) Given the following value, tell whether the starting material or product is favored at equilibrium. DG = 5 kcal/mol A. Starting material favored B. Product favoredarrow_forward
- но LOH он HCI (aq.) но- G+H +I но но. heat OH ÓMe но но H', CH3OH но- но. K (major product) онarrow_forwardUsing your knowledge of pK, values without a table, predict whether the reactants or products are favored? 4. Н reactants or products favored? -н reactants or products favored? reactants or products favored? Он ОН Н NH2 reactants or products favored? NH3arrow_forwardWhich value (if any) corresponds to a faster reaction: (a) Ea = 40 kJ/mol or Ea = 4 kJ/mol; (b) a reaction temperature of 0 °C or a reaction temperature of 25 °C; (c) Keq = 10 or Keq = 100; (d) ΔHo = −10 kJ/mol or ΔHo = 10 kJ/mol?arrow_forward
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