Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 5, Problem 120P
To determine
The minimum coefficient of static friction.
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A 5.0kg crate is tasting on a horizontal plank. The coefficient of static friction is 0.50. You raise one end of the plank slowly. What is the maximum angle (with horizontal) you can go without the crate sliding down the incline?
A 100kg box is at rest on a 10◦ ramp and is being held up by the force of static friction. What is the minimum coefficient of static friction between the box and the ramp to make sure that the box doesn't slip?
A small box is held in place against a rough wall by someone pushing on it with a force directed upward at an angle of 260 above the horizontal. The coefficient of static and kinetic friction between the box and the wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has a magnitude of 13 N. What is the mass of the box?
Chapter 5 Solutions
Physics for Scientists and Engineers
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- A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The book has a mass of m = 1.7 kg and the coefficient of static friction between her hand and the book is μs = 0.59. Force minimum?arrow_forwardIn the early afternoon, a car is parked on a street that runs down a steep hill, at an angle of 35.0 relative to the horizontal. Just then the coefficient of static friction between the tires and the street surface is 0.725. Later, after nightfall, a sleet storm hits the area, and the coefficient decreases due to both the ice and a chemi- cal change in the road surface because of the temperature decrease. By what percentage must the coefficient decrease if the car is to be in danger of sliding down the street?arrow_forwardThe coefficient of kinetic friction between a box and the floor is μk = 0.14 and the coefficient of static friction is μs = 2.0μk. Calculate the ratio of static to kinetic friction force if m = 8 kg.arrow_forward
- A 4.00 kg box sits atop a 10.0 kg box on a horizontal table. The coefficient of kinetic friction between the two boxes and the lower box and table is 0.600, while the coefficient of static frction between these same surfaces is 0.800. A horizontal pull of 150.0 N to the right is exerted on the lower box, and the boxes move together. What is the friction force on the upper box?arrow_forwardA box is placed at one end of a 2.00-m plank. That end of the plank is slowly raised until the box begins to slide. How much time does it take the box to slide to the other (bottom) end of the plank? The coefficients of static and kinetic friction between the box and the plank are, respectively, μs=0.400 and μk=0.200.arrow_forwardProblem 12: A box slides down a plank of length d that makes an angle of 0 with the horizontal, as shown. The kinetic and static coefficients of friction are µk and us, respectively. Omin = 1 Part (a) Enter an expression for the minimum angle at which the box, if initially at rest, will begin to slide. ^^^ 4 acotan(us) atan(us) cos(a) ( ) 7 8 9 cos(p) cos(0) sin(a) 5 6 sin(o) sin(0) 0 α 1 2 3 Mk d t Hints: 0% deduction per hint. Hints remaining: 2 Submit m Hint + * 0 BACKSPACE DEL HOME Feedback END CLEAR I give up! Feedback: 0% deduction per feedback. m 0 Part (b) Enter an expression for the nonconservative work done by kinetic friction as the block slides down the plank. Assume the box starts from rest, and is large enough that it will slide down the plank. the angle Part (c) For a plank of any length, at what angle, in degrees, will the final speed of the box at the bottom of the plank be 0.51 times the final speed of the box when there is no friction present? Assume μ = 0.39.arrow_forward
- A constant force Fa pushes a 22.5-kg box across a rough horizontal surface. The magnitude of Fa is 185 N and the force is inclined at an angle of θ = 30.0° below the horizontal. The coefficient of kinetic friction between the box and the surface is μk = 0.500. What is the magnitude of the box's acceleration?arrow_forwardA 150-lb block rests on a horizontal surface. The coefficient of static and kinetic frictions between the block and the surface are 0.30 and 0.20, respectively. What is the acceleration of the block when P = 90 lb. P μs=0.30, μk=0.20 150 lbarrow_forwardA large box of mass 11.4 kg sits on a ramp that makes an angle of 30.1 degrees with the horizontal. The surface of the ramp is rough and the coefficients of static and kinetic friction are given as 0.56 and 0,38, respectively. We exert a force up the ramp (parallel to the ramp surface) so that the box does not move. Calculate the maximum and the minimum magnitude of the force we can exert so that the box does not move. Enter the difference between the maximum and the minimum force values here: Fmax-Fmin (in Newtons). On your paper, show all the forces on free-body diagrams, clearly show your work, your derivation and calculations. Make sure to include your physics-based reasoning.arrow_forward
- A block of mass is pushed up against a wall by a force P that makes an angle of 0=50°with the horizontal as shown in the figure. The coefficient of static friction between the block and the wall is 0.250. Determine the maximum value for the magnitude of P that allow the block to remain stationary.arrow_forwardSuppose a 25.0 kg block rests on a horizontal plane, and the static friction coefficient between the surfaces is 0.220. (a) What is the maximum allowable static frictional force that could act on the block? (b) What is the actual static frictional force acting on the block if a 25.0 N external force acts horizontally? Assume g = 9.80 m/s2.arrow_forwardProblem 2: Determine the force P necessary to start the V-shaped wedge to the right if the coefficient of friction is f= 0.445 at each of the three surfaces of contact. Wg =1000N WA =200N в P- 30° 150arrow_forward
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