Explanation Positronium is an atom composed of an electron and a Positron and the mass of positron is equal to the mass of electron. The reduced mass is used for muon. Write the expression to calculate reduced mass. μ = m M m + M (I) Here, μ is the reduced mass of an atom, m is the mass of positron and M is the mass of electron. Since the mass of positron is equal to the mass of electron above equation can be written as: μ = m m m + m = m 2 Write the expression for a 0 . a 0 = 4 π ε 0 h 2 μ e 2 (II) Here, a 0 is the Bohr’s radius, e is the charge in electron and ( h ) is the h - bar constant . Write the expression for radius. r = 4 π ε 0 h 2 μ e 2 (III) Here, r is the radius. Substitute m 2 for μ in equation (III)

Modern Physics for Scientists and Engineers

4th Edition

ISBN: 9781133103721

Author: Stephen T. Thornton, Andrew Rex

Publisher: Cengage Learning

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Chapter 4, Problem 32P

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