Essential University Physics
4th Edition
ISBN: 9780134988566
Author: Wolfson, Richard
Publisher: Pearson Education,
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Chapter 34, Problem 64P
To determine
The energy of the free electron.
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The light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying
EH=−RH/n2EH=−RH/n2
where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state.
Be careful about units. The Rydberg constant in eV is
13.605693009 eV
That would be multiplied by the charge on the electron 1.602× 10-19 C to give
2.18× 10-18 J
A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules.
The following questions are intended to help you understand the connection between…
In a He-Ne gas laser an electrical discharge pumps helium atoms to a 20.61 eV excited state. This excited helium level is very close to a 20.66 eVlevel in neon, so that upon collision of a helium atom and a neon atom, the energy can be transferred from the He to the Ne atom. From this excited state, the neon atom then drops toa lower 18.70 eV state thereby emitting a photon. What is the wavelength of this photon?
a. The electron of a hydrogen atom is excited into a higher energy level from a lower energy level. A short time later the electron relaxes down to the no = 1 energy level, releasing a
photon with a wavelength of 93.83 nm. Compute the quantum number of the energy level the electron relaxes from, nhi. Note: the Rydberg constant in units of wavenumbers is 109,625
cm-1
nhi =16
b. What would the wavenumber, wavelength and energy of the photon be if instead no = 1 and nhi = 4?
V: 6.9121e14 x (cm-¹)
λ:
(nm)
E: 45.8e-20
✓ (1)
Chapter 34 Solutions
Essential University Physics
Ch. 34.2 - Prob. 34.1GICh. 34.3 - If you replot Fig. 34.7 for a material with a...Ch. 34.3 - Prob. 34.3GICh. 34.4 - Prob. 34.4GICh. 34.5 - Prob. 34.5GICh. 34.6 - Prob. 34.6GICh. 34 - Prob. 1FTDCh. 34 - Prob. 2FTDCh. 34 - Prob. 3FTDCh. 34 - Prob. 4FTD
Ch. 34 - Prob. 5FTDCh. 34 - Prob. 6FTDCh. 34 - Prob. 7FTDCh. 34 - Prob. 8FTDCh. 34 - Prob. 9FTDCh. 34 - Prob. 10FTDCh. 34 - Prob. 11ECh. 34 - The surface temperature of the star Rigel is 104K....Ch. 34 - Prob. 13ECh. 34 - Prob. 14ECh. 34 - Prob. 15ECh. 34 - Prob. 16ECh. 34 - Prob. 17ECh. 34 - Prob. 18ECh. 34 - Prob. 19ECh. 34 - Prob. 20ECh. 34 - Prob. 21ECh. 34 - Prob. 22ECh. 34 - Prob. 23ECh. 34 - Prob. 24ECh. 34 - Prob. 25ECh. 34 - Prob. 26ECh. 34 - Prob. 27ECh. 34 - Prob. 28ECh. 34 - Prob. 29ECh. 34 - Prob. 30ECh. 34 - Prob. 31ECh. 34 - Prob. 32ECh. 34 - Prob. 33ECh. 34 - Prob. 34ECh. 34 - Prob. 35ECh. 34 - Prob. 36ECh. 34 - Prob. 37ECh. 34 - Prob. 38ECh. 34 - Prob. 39ECh. 34 - Prob. 40ECh. 34 - Prob. 41ECh. 34 - Prob. 42PCh. 34 - Prob. 43PCh. 34 - Prob. 44PCh. 34 - Prob. 45PCh. 34 - Prob. 46PCh. 34 - Prob. 47PCh. 34 - Prob. 48PCh. 34 - Prob. 49PCh. 34 - Prob. 50PCh. 34 - Prob. 51PCh. 34 - Prob. 52PCh. 34 - Prob. 53PCh. 34 - Prob. 54PCh. 34 - Prob. 55PCh. 34 - Prob. 56PCh. 34 - Prob. 57PCh. 34 - Prob. 58PCh. 34 - Prob. 59PCh. 34 - Prob. 60PCh. 34 - Prob. 61PCh. 34 - Prob. 62PCh. 34 - Prob. 63PCh. 34 - Prob. 64PCh. 34 - Prob. 65PCh. 34 - Prob. 66PCh. 34 - Prob. 67PCh. 34 - Prob. 68PCh. 34 - Prob. 69PCh. 34 - Prob. 70PCh. 34 - Prob. 71PCh. 34 - Prob. 72PCh. 34 - Prob. 73PCh. 34 - Prob. 74PCh. 34 - Prob. 75PCh. 34 - Prob. 76PCh. 34 - Prob. 77PCh. 34 - Prob. 78PCh. 34 - Prob. 79PCh. 34 - Prob. 80PCh. 34 - Prob. 81PCh. 34 - Prob. 82PPCh. 34 - Prob. 83PPCh. 34 - Prob. 84PPCh. 34 - Prob. 85PP
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