To define gcd function for over 2 arguments by recursive expression gcd ( a 0 , a 1 , .... , a n ) = gcd ( a 0 , gcd ( a 1 , a 2 , .... , a n ) ) and demonstrate that gcd function returns similar solution independent of sequence in which arguments are stated. To also demonstrate how to discover integers x 0 , x 1 , ..... , x n so that gcd ( a 0 , a 1 , .... , a n ) = a 0 x 0 + a 1 x 1 + ...... + a n x n . To show that count of divisions done by the algorithm is O ( n + lg { max { a 0 , a 1 , .... , a n } ) ) .

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Chapter 31.2, Problem 7E

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To define gcd function for over 2 arguments by recursive expression gcd(a0,a1,....,an)=gcd(a0,gcd(a1,a2,....,an)) and demonstrate that gcd function returns similar solution independent of sequence in which arguments are stated. To also demonstrate how to discover integers x0,x1,.....,xn so that gcd(a0,a1,....,an)=a0x0+a1x1+......+anxn. To show that count of divisions done by the algorithm is O(n+lg{max{a0,a1,....,an})).

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