Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 30.1, Problem 1P
Interpretation Introduction
Interpretation:
HOMO and LUMO of ethylene and 1,3-butadiene for both ground and excited states.
Concept introduction:
The most important orbitals in molecules for reactivity are the two so called frontier orbitals. These are called the HOMO (highest occupied molecular orbital and LUMO (lowest unoccupied molecular orbital). The HOMO is the highest energy MO that has any electrons in it. Electrons from the HOMO are donated and mostly available for bonding. The LUMO is the next highest energy orbital (it will be empty). It is the lowest unoccupied molecular orbital which can receives electrons.
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In the electron paramagnetic resonance spectrum ofthe propyl radical, C3H5, the hyperfine splitting constant is1.45 mT for coupl ing to the protons on the terminal carbonatoms and 0.406 mT for coupl ing to the protons attached tothe central carbon atom. Taking 0= 2.25 mT, use the McConnellequation to estimate the unpaired electron density on eachcarbon atom.
or each of the following molecules, construct the MOS
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(a) Cyclobutadiene HC=CH
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(b) Allyl radical
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Indicate which, if any, of these orbitals have identical ener-
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io to S
5) Give a representation of the highest occupied л MO of 1,3-butadiene in its ground state
Chapter 30 Solutions
Organic Chemistry
Ch. 30.1 - Prob. 1PCh. 30.3 - Prob. 2PCh. 30.3 - Prob. 3PCh. 30.4 - Prob. 4PCh. 30.6 - What stereochemistry would you expect for the...Ch. 30.6 - Prob. 6PCh. 30.7 - Prob. 7PCh. 30.8 - Propose a mechanism to account for the fact that...Ch. 30.8 - When a 2, 6-disubstituted allyl phenyl ether is...Ch. 30.9 - Prob. 10P
Ch. 30.SE - Predict the product obtained when the following...Ch. 30.SE - Prob. 12VCCh. 30.SE - The following rearrangement of N-allyl-N,...Ch. 30.SE - Plastic photochromic sunglasses are based on the...Ch. 30.SE - Prob. 15MPCh. 30.SE - Prob. 16MPCh. 30.SE - Prob. 17MPCh. 30.SE - Prob. 18APCh. 30.SE - Prob. 19APCh. 30.SE - Prob. 20APCh. 30.SE - Prob. 21APCh. 30.SE - Prob. 22APCh. 30.SE - Prob. 23APCh. 30.SE - Prob. 24APCh. 30.SE - Prob. 25APCh. 30.SE - Prob. 26APCh. 30.SE - Prob. 27APCh. 30.SE - Prob. 28APCh. 30.SE - Propose a pericyclic mechanism to account for the...Ch. 30.SE - Prob. 30APCh. 30.SE - Prob. 31APCh. 30.SE - Prob. 32APCh. 30.SE - Prob. 33APCh. 30.SE - Bicyclohexadiene, also known as Dewar benzene, is...Ch. 30.SE - Prob. 35APCh. 30.SE - Prob. 36APCh. 30.SE - The 1H NMR spectrum of bullvalene at 100 C...Ch. 30.SE - Prob. 38APCh. 30.SE - Prob. 39APCh. 30.SE - Prob. 40APCh. 30.SE - In light of your answer to Problem 30-40, explain...
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- • Q: Calculate the wavelength of the radiation that will be absorbed in promoting an electron from the HOMO to the LUMO in butadiene.arrow_forwardAccording to the conventions above, what is the sign ( + or ) of the P.E. change (H) for Rxn 3?arrow_forwardWhich one of the following represents the HOMO of 1,3-butadiene in the ground State?arrow_forward
- 4) How many nodes, other than the node coincident with the molecular plane, are found in the highest energy л MO of 1,3-butadiene?arrow_forwardWhat is the totaly Pi electron binding energy of the ground state for the allyl radical? *CH2-CH=CH2arrow_forwardConsider the following compounds and answer the following question. 1) 2-Pentanone II) Hexanol III) Dimethylether IV) 2-Butene V) Cyclodecane VI) Acetamide Which compound(s) show π-n* electronic transitions in UV-Vis? Choose... Which compound(s) show n-n* electronic transitions in UV-Vis? Choose...arrow_forward
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