Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 30, Problem 2P
To determine
The units of
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Use Ampere’s Law for a long, straight conductor (a wire), B = μoI/(2πd), to calculate B at a distance of 2.0 cm from a wire carrying a current of 24 A. (μo = 4π x 10-7 Tm/A)
If current flows through two parallel conductors in opposite directions, they experience between them a force of attraction. Select one: O True O False
The unit of surface current is A/m^2.
Select one:
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Chapter 30 Solutions
Physics for Scientists and Engineers
Ch. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10P
Ch. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Prob. 16PCh. 30 - Prob. 17PCh. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37PCh. 30 - Prob. 38PCh. 30 - Prob. 39PCh. 30 - Prob. 40PCh. 30 - Prob. 41PCh. 30 - Prob. 42PCh. 30 - Prob. 43PCh. 30 - Prob. 44PCh. 30 - Prob. 45PCh. 30 - Prob. 46PCh. 30 - Prob. 47PCh. 30 - Prob. 48PCh. 30 - Prob. 49PCh. 30 - Prob. 50PCh. 30 - Prob. 51PCh. 30 - Prob. 52PCh. 30 - Prob. 53PCh. 30 - Prob. 54PCh. 30 - Prob. 55PCh. 30 - Prob. 56PCh. 30 - Prob. 57PCh. 30 - Prob. 58PCh. 30 - Prob. 59P
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- In the SI system of units, one coulomb (1 C) is defined to be the charge that passes a point every second when a constant (electric) current of one ampere, also called one amp, (1 A) flows past that point. Thus, one coulomb equals one ampere second (1 C = 1A-s). If Q is the charge and / is the constant (or average) current past a point in a time t, Q=It. An average current of 2.0 A flows through all parts of a wire for 5.0 minutes. How much charge passes by any point in the wire in that time? 10.0 C О В. 120.0 С 600.0 C O D.2.0 C Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Save and Sub P Type here to search 23arrow_forwardPhysics students, wanted to investigate the forces of attraction (F) between two parallel conductors carrying currents li and l2 (also known as Ampere's Law) The students noticed that as the length of the parallel conductors (/) was increased the force of attraction between the conductors (F) also increased. The data collected is in the |L= SA conductor 1 average separation (d = 0.50m) table: conductor 2 Length, / (m) Force, F (x 10-5 N) 12= 5A 1.00 9.00 1.20 10.8 1.40 12,5 1.60 14.2 1.80 16.2 (iii) On the grid plot the force and length values from the table. (iv) Draw the line of best fit (v) Find the slope of the line of best fit. (c) Use the slope calculated and the Ampere's Law equation to determine the experimental value of the magnetic force constant, k.arrow_forwardPhysics students, wanted to investigate the forces of attractioh (F) between two parallel conductors carrying currents l1 and l2 (also known as Ampere's Law) The students noticed that as the length of the parallel conductors (/) was increased the force of attraction between the conductors (F) also increased. The data collected is in the |L= 5A conductor 1 average separation (d 0.50m) table: conductor 2 Length, I (m) Force, F (x 106 N) 12 = 5A 1.00 9.00 1.20 10.8 1.40 12,5 1.60 14.2 1.80 16.2 (iii) On the grid plot the force and length values from the table. (iv) Draw the line of best fit (v) Find the slope of the line of best fit. (c) Use the slope calculated and the Ampere's Law rmine the experimental value of equation to de the magnetic force constant, k.arrow_forward
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