a. Explanation Concept Used: In this we have to use the concept of limits. Calculation: We note that x − 2 is negative when x < 2 , and positive when x > 2 .So to write the function without the absolute value ,it becomes g ( x ) = { x 2 + x − 6 − ( x − 2 ) , i f x < 2 ; x 2 + x − 6 x − 2 , i f x > 2 Putting the negative there makes the denominator positive when x > 2 ,so the expression can have the same value as the original with the absolute value. (i) For x − > 2 + we use the x > 2 version of g(x) lim x → 2 + x 2 + x − 6 x − 2 = lim x → 2 + ( x + 3 ) ( x − 2 ) x − 2 = b. To determine To find whether the lim x → 2 g ( x ) exists. c. To determine To draw the graph of g.

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Question

Chapter 2.4, Problem 37E

To determine

To find the limit of limx→2+g(x) and limx→2−g(x) .

To determine

To find whether the limx→2g(x) exists.

To determine

To draw the graph of g.

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Chapter 2.4, Problem 36E

Chapter 2.4, Problem 38E

Chapter 2 Solutions

Biocalculus

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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Prob. 9CS

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To find the limit of lim x → 2 + g ( x ) and lim x → 2 − g ( x ) .

Solution Summary: The author calculates the limit of undersetx to 2+mathrmlimg(x), and the denominator is positive.

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To find the limit of limx→2+g(x) and limx→2−g(x) .

To find whether the limx→2g(x) exists.

To draw the graph of g.

Want to see the full answer?

Chapter 2 Solutions