EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
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Suppose an electron (q= -e = -1.6 x 10^-19 C, m = 9.1 x 10^-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. Use the template in the attached photo to solve for the problem.
When an electron is accelerated from
rest to potential V, the final velocity of
electron is
eV
eV
(a) 2m
(b)
4eV
2eV
(c) \
(d)*
m
m
How much work (in eV) does it take to move a 7 protons through a 2 V potential difference?
Chapter 23 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
Ch. 23.1 - Prob. 1AECh. 23.2 - Prob. 1BECh. 23.3 - Prob. 1CECh. 23.3 - Prob. 1DECh. 23.8 - Prob. 1FECh. 23.8 - Prob. 1GECh. 23 - If two points are at the same potential, does this...Ch. 23 - If a negative charge is initially at rest in an...Ch. 23 - State clearly the difference (a) between electric...Ch. 23 - Suppose the charged ring of Example 238 was not...
Ch. 23 - Consider a metal conductor in the shape of a...Ch. 23 - Equipotential lines are spaced 1.00 V apart. Does...Ch. 23 - Prob. 1PCh. 23 - Prob. 3PCh. 23 - Prob. 4PCh. 23 - Prob. 9PCh. 23 - Prob. 11PCh. 23 - (II) The electric potential of a very large...Ch. 23 - (II) The Earth produces an inwardly directed...Ch. 23 - (II) A 32-cm-diameter conducting sphere is charged...Ch. 23 - (II) An insulated spherical conductor of radius r1...Ch. 23 - (II) Determine the difference in potential between...Ch. 23 - (II) Suppose the end of your finger is charged....Ch. 23 - (II) Estimate the electric field in the membrane...Ch. 23 - (III) A hollow spherical conductor, carrying a net...Ch. 23 - (III) A very long conducting cylinder (length ) of...Ch. 23 - Prob. 31PCh. 23 - (I) Draw a conductor in the shape of a football....Ch. 23 - (II) Equipotential surfaces are to be drawn 100 V...Ch. 23 - (II) Calculate the electric potential due to a...Ch. 23 - (III) The dipole moment, considered as a vector,...Ch. 23 - (I) Show that the electric field of a single point...Ch. 23 - (I) What is the potential gradient just outside...Ch. 23 - (II) The electric potential between two parallel...Ch. 23 - () The electric potential in a region of space...Ch. 23 - (II) In a certain region of space, the electric...Ch. 23 - (II) A dust particle with mass of 0.050 g and a...Ch. 23 - (III) Use the results or Problems 38 and 39 to...Ch. 23 - (I) How much work must be done to bring three...Ch. 23 - (I) What potential difference is needed to give a...Ch. 23 - If the electrons in a single raindrop, 3.5 mm in...Ch. 23 - By rubbing a nonconducting material, a charge of...
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- Unreasonable Results A proton has a mass of 1.671027 kg. A physicist measures the proton's total energy to be 50.0 MeV. (a) What is the proton's kinetic energy? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardSuppose an electron (q = -e = -1.6 x 10¬9 C,m=9.1 x 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for %3D the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forwardA uniform electric field is created by two horizontal parallel plate electrodes of length 10 cm separated by a vertical distance d = 5 cm and held at a potential difference V = 250V. A beam of electrons is introduced between the two plates with a horizontal velocity v = 5 x 106 m/s. What is the deflection distance towards the positive plate when the electron beam leaves the electric field?arrow_forward
- : In parallel-plate diode, the anode is at 250 V with respect to the cathode which is 4 mm away from it. An electron is emitted from cathode with an initial velocity towards anode of 2x106 m/s. Calculate : (i) the arrival velocity of the electron at anode (ii) time of transit (iii) the velocity and distance traveled by the electron after 0.5×10-⁹ S.arrow_forwardAnswers: a) 3.3 C c/m² 6. Two electrons are fixed 2.00 cm apart. Another electron is shot from infinity and comes to rest midway between the two. What was its initial speed? Answer: 318 m/sarrow_forwardAn experimental form of cancer therapy involves the use of a beam of highly ionized carbon atoms with a charge of +6e (all six electrons have been removed). The mass of the ions is 11.172 GeV/2. The accelerator is 5.50 m long and the ions are accelerated through a 120-MV potential difference. What is the ion's kinetic energy? MeVarrow_forward
- A small charged ball is accelerated from rest to a speed v by a 500 V potential difference. If the potential difference is changed to 16,000 V, what will the new speed of the ball be? O 16v 0 4v O 2v W.arrow_forwardThis scanning electron microscope image of a bacterium was produced using a beam of electrons accelerated through an 30 kV potential difference. What is the speed of the electrons?arrow_forwardA positron (a particle with a charge +e and a mass equal to that of electron) that is accelerated from rest between two points at a fixed potential difference acquires a speed of 9.0x10^7 m/s. What speed is achieved by a proton accelerated from rest between the same two points? (Disregard relativistic effects.) a) 2.5x10^6 m/s b) 2.1x10^6 m/s c) 2.8x10^7 m/s d) 4.9x10^7m/s e) None of the Abovearrow_forward
- Four parallel plates are connected in a vacuum as shown in the picture. An electron with initial velocity, 1.02 x 10°m/s in the hole of plate X is accelerated to the right. Gravity is negligible once the electron passes through holes at W and Y. However due to the high air viscosity, the electrons loses 1.6 × 10-17) of 1V = energy between the plate W to plate Y. It then passes through the hole at Y and slows down as it heads to plate Z. Calculate the distance, in centimetres, from plate Z to the point at which the electron changes direction. - 6.0 cm→6.0 cm→<6.0 cm - W Y 4.0 x 10² V 7.0 × 103 V Narrow_forwardWhat is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference? Express your answer as a fraction of cc.arrow_forwardThe uniform electric field between two charged parallel plates has a magnitude of 4400 V/m (note that 1 V/m = 1 N/C). If the plates are separated by 0.0100 m and an electron is released from the far negative side of the gap, what will the electron's kinetic energy (in eV) and speed be when it just reaches the positive plate? Note that the electron charge = -1.602 x 10-19 C and the electron mass = 9.11 x 10-31 kg. KE V= ev m/sarrow_forward
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