Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 105P
To determine
To obtain:The position functions of particle at origin in the given time.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A particle is moving at a velocity v = A cos (bt), where A and b are both constants. Find the position of the particle at t = 2 seconds.
CHOICES:
x(t=2s) = (A) (sin 2b) [m]
x(t=2s) = (A/b) (-sin b) [m]
x(t=2s) = (A/b) (cos 2b) [m]
x(t=2s) = (A/b) (sin 2b) [m]
A particle is moving with the given data. Find the position of the particle.
a(t) = 5 sin t – 2 cos t, s(0) = 0, s(2n) = 4
Position s(t)
A particle is moving on xy plane, with x=15sin(2t), and y = 20cos(2t)
Find the magnitude of the velocity as a function of time
Chapter 2 Solutions
Physics for Scientists and Engineers
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 92PCh. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - Prob. 95PCh. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 98PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The position of a particle moving in the xy plane varies with time, and its coordinates are given by the following expressions: x(t) = 4.00 m +r cos[(4.00/s)t] and y(t) = r sin[(4.00/s)t], where r = 2.00 m, and x and y will be in meters when t is in seconds. Determine the following for this particle. (a) speed of the particle at any time m/s (b) magnitude of the acceleration of the particle at any time m/s?arrow_forwardA particle moves with constant speed vo along the ellipse (x/a)^2 + (y/b)^2 = 1, where a > b. Determine the maximum acceleration of the particle.arrow_forwardSuppose that a particle's position is described by r(t) = ti+ (t + 1) k. Find the velocity vector for the particle at t = 1: v(1) = Find the acceleration vector for the particle at t = 1: a(t) = (Answer in terms of t.)arrow_forward
- At what times in the interval 0 ≤ t ≤ π are the velocity and acceleration vectors of the motion r(t) = i + (5 cos t)j + (3 sin t)k orthogonal?arrow_forwardA particle starts moving with the initial velocity v(0) = 1 and accelerates as a(t) = sin t + t for t > 0. (a) Find the velocity function for the particle. (b) What would be its velocity at time t = 5?arrow_forwardA particle moves along xy-plane with a position of x (t) = sin(2t) + 3 cos(4t) y (t) = 1/2 sin(t) – 6 cos(3t) a. Determine the average velocity from t = 1s to t= 3s.arrow_forward
- Given that the acceleration vector is a(t)=(−16cos(−4t))i+(−16sin(−4t))j+(1t)k, the initial velocity is v(0)=i+k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t)arrow_forwardA particle moves through 3-space in such a way that its velocity is v(t) = i + tj + t ²k Find the coordinates of the particle at time t = 1 given that the particle is at the point (−1, 2, 4) at time t = 0.arrow_forwardA particle moves in xy plane with a constant acceleration. At t = 0 the particle at r = (4.0m)ỉ + (3.0m)j, with velocity Vo. At t = 2.0s the particle has moved to r = (10.0m)ï – (2.0m)j and its velocity has changed to v; = (5.0")i- (6.0")j. a) Find the initial velocity of the particle vo. b) What is the acceleration of the particle ã? c) What is the velocity of the particle as a function of time i(t)? d) What is the position vector of the particle as a function of time 7(t)?arrow_forward
- The coordinates of a particle moving in a plane are given by r = 4 cos 6t and y = 6 sin 6t find the angle between position vector 7 and velocity vector i at time t: = T/12arrow_forwardThe acceleration vector of a particle is giving by a = -27 t2 j m/s4. The particle is located at the origin at t = 0 s and has an initial velocity Vo = 2(m/s) i + 3(m/s) j. Find: a) The velocity of the particle as a function of time. b) The maximum height the particle reaches.arrow_forwardAt time t = 0, the position vector of a particle moving in the x-y plane is r = 4.62i m. By time t = 0.011 s, its position vector has become (4.84i +0.54j) m. Determine the magnitude Vay of its average velocity during this interval and the angle 0 made by the average velocity with the positive x-axis. Answers: Vav 0= i i m/sarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Kinematics Part 3: Projectile Motion; Author: Professor Dave explains;https://www.youtube.com/watch?v=aY8z2qO44WA;License: Standard YouTube License, CC-BY