Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 17, Problem 45E
Interpretation Introduction
Interpretation:
The oxidation number of sulfur in sodium tetrathionate,
Concept introduction:
A species gains or loses electrons to form anions or cations respectively. A gain in electron is classified as a reduction reaction and loss of electron is classified as an oxidation reaction. The oxidation number is allocated to maintain track of an electron's loss or gain.
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Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Ch. 17 - Prob. 1CECh. 17 - Prob. 2CECh. 17 - Prob. 3CECh. 17 - Prob. 4CECh. 17 - Prob. 5CECh. 17 - Prob. 6CECh. 17 - Prob. 7CECh. 17 - Prob. 8CECh. 17 - Prob. 9CECh. 17 - Prob. 10CE
Ch. 17 - Prob. 1KTCh. 17 - Prob. 2KTCh. 17 - Prob. 3KTCh. 17 - Prob. 4KTCh. 17 - Prob. 5KTCh. 17 - Prob. 6KTCh. 17 - Prob. 7KTCh. 17 - Prob. 8KTCh. 17 - Prob. 9KTCh. 17 - Prob. 10KTCh. 17 - Prob. 11KTCh. 17 - Prob. 12KTCh. 17 - Prob. 13KTCh. 17 - Prob. 14KTCh. 17 - Prob. 15KTCh. 17 - Prob. 16KTCh. 17 - Prob. 17KTCh. 17 - Prob. 18KTCh. 17 - Prob. 19KTCh. 17 - Prob. 1ECh. 17 - Prob. 2ECh. 17 - Prob. 3ECh. 17 - Prob. 4ECh. 17 - Prob. 5ECh. 17 - Prob. 6ECh. 17 - Prob. 7ECh. 17 - Prob. 8ECh. 17 - Prob. 9ECh. 17 - Prob. 10ECh. 17 - Prob. 11ECh. 17 - Prob. 12ECh. 17 - Prob. 13ECh. 17 - Prob. 14ECh. 17 - Prob. 15ECh. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - Prob. 20ECh. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - Prob. 26ECh. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Prob. 29ECh. 17 - Prob. 30ECh. 17 - Prob. 31ECh. 17 - Prob. 32ECh. 17 - Prob. 33ECh. 17 - Prob. 34ECh. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - Prob. 38ECh. 17 - Prob. 39ECh. 17 - Prob. 40ECh. 17 - Prob. 41ECh. 17 - Prob. 42ECh. 17 - Prob. 43ECh. 17 - Prob. 44ECh. 17 - Prob. 45ECh. 17 - Prob. 46ECh. 17 - Prob. 47ECh. 17 - Prob. 48ECh. 17 - Prob. 49ECh. 17 - Prob. 50ECh. 17 - Prob. 51ECh. 17 - Prob. 52ECh. 17 - Prob. 1STCh. 17 - Prob. 2STCh. 17 - Prob. 3STCh. 17 - Prob. 4STCh. 17 - Prob. 5STCh. 17 - Prob. 6STCh. 17 - Prob. 7STCh. 17 - Prob. 8STCh. 17 - Prob. 9STCh. 17 - Prob. 10STCh. 17 - Prob. 11ST
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- Phosphorous acid, H3PO3, is oxidized to phosphoric acid, H3PO4, by nitric acid, which is reduced to nitrogen monoxide, NO. Write the balanced equation for this reaction.arrow_forwardThe reaction of elemental phosphorus and excess oxygen produces P4O10. Name the compound. (a) phosphorus oxide (b) phosphoric acid (c) phosphorus decaoxide (d) tetraphosphorus decaoxidearrow_forwardThe amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine; ClO- is reduced to Cl-. The amount of iodine produced by the redox reaction is determined by titration with sodium thiosulfate, Na2S2O3; I2 is reduced to I-. The sodium thiosulfate is oxidized to sodium tetrathionate, Na2S4O6. In this analysis, potassium iodide was added in excess to 5.00 mL of bleach (d=1.00g/cm3) . If 25.00 mL of 0.0700 M Na2S2O3 was required to reduce all the iodine produced by the bleach back to iodide, what is the mass percent of NaClO in the bleach?arrow_forward
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