a. Explanation Given: log 2 6 − log 2 15 + log 2 20 Concept Used: Basic properties of logarithmic function: log p a + log p b = log p a b log p a − log p b = log p a b log p p n = n Where a > 0 , b > 0 and n is any real number Calculation: To find the exact value of log 2 6 − log 2 15 + log 2 20 Use basic property of logarithmic function as log 2 6 − log 2 15 + log 2 20 = log 2 ( 6 15 ) + b. To determine To calculate the exact value of the expression.

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Question

Chapter 1.5, Problem 37E

To determine

To calculate the exact value of the expression.

To determine

To calculate the exact value of the expression.

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Chapter 1 Solutions

Biocalculus

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - Prob. 51E Ch. 1.1 - Prob. 52E Ch. 1.1 - Prob. 53E Ch. 1.1 - Prob. 54E Ch. 1.1 - Prob. 55E Ch. 1.1 - Prob. 56E Ch. 1.1 - Prob. 57E Ch. 1.1 - Prob. 58E Ch. 1.1 - Prob. 59E Ch. 1.1 - Prob. 60E Ch. 1.1 - 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Prob. 39E Ch. 1.6 - Prob. 40E Ch. 1.6 - Prob. 1P Ch. 1.6 - Prob. 2P Ch. 1.6 - Prob. 3P Ch. 1.6 - Prob. 4P Ch. 1 - Prob. 1CC Ch. 1 - Prob. 2CC Ch. 1 - Prob. 3CC Ch. 1 - Prob. 4CC Ch. 1 - Prob. 5CC Ch. 1 - Prob. 6CC Ch. 1 - Prob. 7CC Ch. 1 - Prob. 8CC Ch. 1 - Prob. 9CC Ch. 1 - Prob. 10CC Ch. 1 - Prob. 11CC Ch. 1 - Prob. 12CC Ch. 1 - Prob. 13CC Ch. 1 - Prob. 14CC Ch. 1 - Prob. 15CC Ch. 1 - Prob. 16CC Ch. 1 - Prob. 1TFQ Ch. 1 - Prob. 2TFQ Ch. 1 - Prob. 3TFQ Ch. 1 - Prob. 4TFQ Ch. 1 - Prob. 5TFQ Ch. 1 - Prob. 6TFQ Ch. 1 - Prob. 7TFQ Ch. 1 - Prob. 8TFQ Ch. 1 - Prob. 9TFQ Ch. 1 - Prob. 10TFQ Ch. 1 - Prob. 11TFQ Ch. 1 - Prob. 12TFQ Ch. 1 - Prob. 1E Ch. 1 - Prob. 2E Ch. 1 - Prob. 3E Ch. 1 - Prob. 4E Ch. 1 - Prob. 5E Ch. 1 - Prob. 6E Ch. 1 - Prob. 7E Ch. 1 - Prob. 8E Ch. 1 - Prob. 9E Ch. 1 - Prob. 10E Ch. 1 - Prob. 11E Ch. 1 - Prob. 12E Ch. 1 - Prob. 13E Ch. 1 - Prob. 14E Ch. 1 - Prob. 15E Ch. 1 - Prob. 16E Ch. 1 - Prob. 17E Ch. 1 - Prob. 18E Ch. 1 - Prob. 19E Ch. 1 - Prob. 20E Ch. 1 - Prob. 21E Ch. 1 - 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To calculate the exact value of the expression.

Solution Summary: The author explains how to calculate the exact value of the expression using basic properties of logarithmic function.

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To calculate the exact value of the expression.

To calculate the exact value of the expression.

Chapter 1 Solutions