Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 13, Problem 2PDQ
CONCEPT QUESTION Review the Chapter Concepts list on p. 283. These all center around how genetic information is stored in DNA and transferred to RNA prior to translation into proteins. Write a short essay that summarizes the key properties of the genetic code and the process by which RNA is transcribed on a DNA template.
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As we focused on the genetic code and the transcription of genetic information stored in DNA into complementary RNA molecules. Along the way, we found many opportunities to consider the methods and reasoning by which much of this information was acquired. From the explanations given in the chapter, what answers would you propose to the following fundamental questions:
Question: How do we know that the initial transcript of a eukaryotic gene contains noncoding sequences that must be removed before accurate translation into proteins can occur?
The diagram below depicts an active transcription bubble after a short period of RNA synthesis during the
transcription process of a prokaryotic gene. Redraw the diagram and label parts (i) to (v) on the diagram.
Motivate your answers.
(i)
the template and the non-template strands;
(ii) the orientation (direction) of both DNA strands and that of the newly synthesised RNA strand;
(iii) the location of a possible promotor sequence;
(iv) the location of a possible Shine-Dalgarno sequence;
(v)
the specific area of activity of a RNA polymerase.
briefly explain the importance of the degeneracy of the genetic code in the translation process. do not simply define the given
Chapter 13 Solutions
Concepts of Genetics (12th Edition)
Ch. 13 - In a mixed heteropolymer experiment using...Ch. 13 - When repeating copolymers are used to form...Ch. 13 - The following represent deoxyribonucleotide...Ch. 13 - Prob. 1CSCh. 13 - A 30-year-old woman was undergoing therapy for...Ch. 13 - A 30-year-old woman was undergoing therapy for...Ch. 13 - HOW DO WE KNOW? In this chapter, we focused on the...Ch. 13 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 13 - Assuming the genetic code is a triplet, what...Ch. 13 - The mRNA formed from the repeating tetranucleotide...
Ch. 13 - In studies using repeating copolymers, AC ......Ch. 13 - In a coding experiment using repeating copolymers...Ch. 13 - Prob. 7PDQCh. 13 - When the amino acid sequences of insulin isolated...Ch. 13 - Prob. 9PDQCh. 13 - Why doesnt polynucleotide phosphorylase (Ochoas...Ch. 13 - Refer to Table 13.1. Can you hypothesize why a...Ch. 13 - Predict the amino acid sequence produced during...Ch. 13 - A short RNA molecule was isolated that...Ch. 13 - A glycine residue is in position 210 of the...Ch. 13 - Refer to Figure 13.7 to respond to the following:...Ch. 13 - Most proteins have more leucine than histidine...Ch. 13 - Define the process of transcription. Where does...Ch. 13 - Prob. 18PDQCh. 13 - Describe the structure of RNA polymerase in...Ch. 13 - Prob. 20PDQCh. 13 - Messenger RNA molecules are very difficult to...Ch. 13 - Present an overview of various forms of...Ch. 13 - One form of posttranscriptional modification of...Ch. 13 - Describe the role of two forms of RNA editing that...Ch. 13 - Substitution RNA editing is known to involve...Ch. 13 - Prob. 26ESPCh. 13 - Prob. 27ESPCh. 13 - Prob. 28ESPCh. 13 - Shown here are the amino acid sequences of the...Ch. 13 - The genetic code is degenerate. Amino acids are...Ch. 13 - M. Klemke et al. (2001) discovered an interesting...Ch. 13 - Recent observations indicate that alternative...Ch. 13 - Isoginkgetin is a cell-permeable chemical isolated...
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- Which statements are true? Explain why or why not.1 The consequences of errors in transcription areless severe than those of errors in DNA replication.2 Since introns are largely genetic “junk,” they do nothave to be removed precisely from the primary transcriptduring RNA splicing.3 Wobble pairing occurs between the first positionin the codon and the third position in the anticodon.4 During protein synthesis, the thermodynamics ofbase-pairing between tRNAs and mRNAs sets the upperlimit for the accuracy with which protein molecules aremade.5 Protein enzymes are thought to greatly outnum-ber ribozymes in modern cells because they can catalyzea much greater variety of reactions and all of them havefaster rates than any ribozyme.arrow_forwardtrue or false 1.) The unique stem-loop structures of the transfer RNA helps the RNA perform its function of joining ribosomal proteins to form the sites for protein synthesis. 2.) DNA molecules can perform their function in replication and transcription as long as the 2 strands remain intact and not separated. 3.) Histone proteins are able to associate with DNA segments because of the anionic nature of the amino acids arg and lys. 4.) The long solenoid structure of the chromatin material binds to a protein scaffold and folds further to form the chromatin/chromosome structure. 5.) Primary amines and keto groups of the nitrogen bases are involved in base-pairing in double stranded DNA.arrow_forwardDiscuss why the genetic code is said to be degenerate.arrow_forward
- 8:52 Protein 1-10092015113603.pdf https:api.schoology.comv1attachment169963839... Name Class Date Section Protein Synthesis pages 148-153) 7-3 SECTION REVIEW In this section you studied the process of pro- tein synthesis. You learned that the informa- tion that DNA transfers to messenger RNA (MRNA) is in the form of a code. When the information is decoded, chains of amino acids, called polypeptides, are formed. Polypeptides During translation, each MRNA codon in turn make up proteins, which direct biochemical pathways and are responsible for cell structure and movement. The genetic code is determined by the arrangement of the nitrogenous bases in DNA and RNA. A code word in DNA consists of a group of three nucleotides. When transcribed into MRNA, each code word, or codon, desig- nates a specific amino acid that is to be placed in the polypeptide chain. More than one codon may code for a particular amíno acid. The MANA sequence AUG serves as an initiator, or "start," codon. Three other…arrow_forwardDefine both transcription and translation. In addition, describe the role(s) of each of the following in the processes of gene expression and protein synthesis: DNA, mRNA, tRNA, rRNA, ribosome(s), RNA polymerase, codon, anticodon, amino acid(s) and polypeptide(s). Be detailed in your answer.arrow_forwardListed below are five amino acids. Use the genetic code to determine the exact codon for each amino acid. A point mutation at the genetic level in each codon results in the change indicated. For each mutation, indicate whether it is due to a transition or a transversion, and then indicate the effect of each mutation at the protein (amino acid level) (i.e. silent, nonsense, missense). In addition, Please note, each of the three lines above an amino acid represents a single RNA base. For example, when you look at the codon chart AUG would stand for Met (methionine) Lys 1 Glu Ile 3 Stop Ile 4.arrow_forward
- Listed below are five amino acids. Use the genetic code to determine the exact codon for each amino acid. A point mutation at the genetic level in each codon results in the change indicated. For each mutation, indicate whether it is due to a transition or a transversion, and then indicate the effect of each mutation at the protein (amino acid level) (i.e. silent, nonsense, missense). In addition, Please note, each of the three lines above an amino acid represents a single RNA base. For example, when you look at the codon chart AUG would stand for Met (methionine) Lys 2 1 Glu Ile 4 Stop Ile Mutation 1: 1. Circle the appropriate answer: This mutation is a transition/transversion 2. Circle the appropriate answer: This mutation results in a missense/silent/nonsense mutation in the protein sequence. Mutation 2: 1. Circle the appropriate answer: This mutation is a transition/transversion 2. Circle the appropriate answer: This mutation results in a missense/silent/nonsense mutation in the…arrow_forwardWhat is the biological significance of the extensive degeneracy of the genetic code?arrow_forwardDiscuss the types of RNA transcripts and the functional roles theyplay. Why do some RNAs form complexes with protein subunits?arrow_forward
- A.C. 3.4 Q1. Protein synthesis is carried out by the processes of transcription and translation. A short length of DNA is shown: TACTCGTCGACGATGATC First base (a) State how many codons are present. (b) Using the table below, find the sequence of amino acids resulting from the transcription and translation of the length of DNA. Show your working. U U UUU Phenyl- UCU UUC alanine F UCC UCA -Leucine Lucc UUG-Le G CUU CUC CUA CUG A AUA -Leucine L AUU I AUC Isoleucine Methionine start codon AUG MMet GUUT GUC GUA GUG -Valine V CCU CCC CCA CCG ACU ACC ACA ACG C GCUT GCC GCA GCG Second base -Serine S -Proline P -Threonine -Alanine UAUT UAC A UAA UAG CAU CAC CAA CAG A Tyrosine Y Stop codon Stop codon -Histidine H -Glutamine AAA TAAG-Lysine AAC-Asparagine N GAU Aspartic GAC acid D GAG Glutamic G UGU-Cysteine C E UGC UGA UGG AGU AGC KAGG-Arginine CGUT CGC CGA CGG GGUT GGC GGA GGGJ Stop codon A Tryptophan -Arginine R Serine S R Glycine UCAG G SCAG SCAQ SCAG Third basearrow_forward39/ 50 Which of these is the function of a poly (A) signal sequence? A. It adds the poly (A) tail to the 3' end of the mRNA B It codes for a sequence in eukaryotic transcripts that signals termination of transcription-10-35 nucleotides away C. It allows the 3' end of the mRNA to attach to the ribosome DR is a sequence that codes for the hydrolysis of the RNA polymerase It adds a 7-methylguanosine cap to the 3' end of the mRNAarrow_forwardGiven the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'arrow_forward
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