Computer Science: An Overview (12th Edition)
12th Edition
ISBN: 9780133760064
Author: Glenn Brookshear, Dennis Brylow
Publisher: PEARSON
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Chapter 12.6, Problem 4QE
Program Plan Intro
Decrypting Keys in RSA public key cryptography:
The keys used to decrypt an encrypted message in RSA cryptography are called Decrypting keys in RSA public keys cryptography. These keys are denoted by n and d.
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RSA encryption uses a famous formula for encryption/decryption. Given that N= 12345 , decryption key d = 1961, cipher in numeric form =170826 . what is the decrypted number ?
A symmetric block encryption algorithm is shown below.
16-bit blocks of plaintext P are encrypted using a 32-bit
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C = (P EX_OR Ko) + K1
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16 bits of K, K1 is the rightmost 16 bits of K, EX_OR is
bitwise exclusive OR, and + is binary addition.
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Chapter 12 Solutions
Computer Science: An Overview (12th Edition)
Ch. 12.1 - Prob. 1QECh. 12.1 - Prob. 2QECh. 12.1 - Prob. 3QECh. 12.1 - Prob. 4QECh. 12.2 - Prob. 1QECh. 12.2 - Prob. 2QECh. 12.2 - Prob. 3QECh. 12.2 - Prob. 4QECh. 12.2 - Prob. 5QECh. 12.3 - Prob. 1QE
Ch. 12.3 - Prob. 3QECh. 12.3 - Prob. 5QECh. 12.3 - Prob. 6QECh. 12.4 - Prob. 1QECh. 12.4 - Prob. 2QECh. 12.4 - Prob. 3QECh. 12.5 - Prob. 1QECh. 12.5 - Prob. 2QECh. 12.5 - Prob. 4QECh. 12.5 - Prob. 5QECh. 12.6 - Prob. 1QECh. 12.6 - Prob. 2QECh. 12.6 - Prob. 3QECh. 12.6 - Prob. 4QECh. 12 - Prob. 1CRPCh. 12 - Prob. 2CRPCh. 12 - Prob. 3CRPCh. 12 - In each of the following cases, write a program...Ch. 12 - Prob. 5CRPCh. 12 - Describe the function computed by the following...Ch. 12 - Describe the function computed by the following...Ch. 12 - Write a Bare Bones program that computes the...Ch. 12 - Prob. 9CRPCh. 12 - In this chapter we saw how the statement copy...Ch. 12 - Prob. 11CRPCh. 12 - Prob. 12CRPCh. 12 - Prob. 13CRPCh. 12 - Prob. 14CRPCh. 12 - Prob. 15CRPCh. 12 - Prob. 16CRPCh. 12 - Prob. 17CRPCh. 12 - Prob. 18CRPCh. 12 - Prob. 19CRPCh. 12 - Analyze the validity of the following pair of...Ch. 12 - Analyze the validity of the statement The cook on...Ch. 12 - Suppose you were in a country where each person...Ch. 12 - Prob. 23CRPCh. 12 - Prob. 24CRPCh. 12 - Suppose you needed to find out if anyone in a...Ch. 12 - Prob. 26CRPCh. 12 - Prob. 27CRPCh. 12 - Prob. 28CRPCh. 12 - Prob. 29CRPCh. 12 - Prob. 30CRPCh. 12 - Prob. 31CRPCh. 12 - Suppose a lottery is based on correctly picking...Ch. 12 - Is the following algorithm deterministic? Explain...Ch. 12 - Prob. 34CRPCh. 12 - Prob. 35CRPCh. 12 - Does the following algorithm have a polynomial or...Ch. 12 - Prob. 37CRPCh. 12 - Summarize the distinction between stating that a...Ch. 12 - Prob. 39CRPCh. 12 - Prob. 40CRPCh. 12 - Prob. 41CRPCh. 12 - Prob. 42CRPCh. 12 - Prob. 43CRPCh. 12 - Prob. 44CRPCh. 12 - Prob. 46CRPCh. 12 - Prob. 48CRPCh. 12 - Prob. 49CRPCh. 12 - Prob. 50CRPCh. 12 - Prob. 51CRPCh. 12 - Prob. 52CRPCh. 12 - Prob. 1SICh. 12 - Prob. 2SICh. 12 - Prob. 3SICh. 12 - Prob. 4SICh. 12 - Prob. 5SICh. 12 - Prob. 6SICh. 12 - Prob. 7SICh. 12 - Prob. 8SI
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Similar questions
- Calculate H(K), H(M) and H(C) and the unicity distance for the following cryptographic system:First encrypt your plaintext using(a) a Vernam cipher with key lengths 5 and 7.and then encrypt the cyphertext by(b) 2 x 2 Hill cipher mod 29The cypher system is the combined cypher of (a) and (b).arrow_forwardThe Public and Private Key pair comprise of two uniquely related cryptographic keys. Below is an example of a Public Key: 3048 0241 00C9 18FA CF8D EB2D EFD5 FD37 89B9 E069 EA97 FC20 5E35 F577 EE31 C4FB C6E4 4811 7D86 BC8F BAFA 362F 922B F01B 2F40 C744 2654 CODD 2881 D673 CA2B 4003 C266 E2CD CB02 0301 0001 (1) Explain the definition for both Public and Private Key.arrow_forwardIn symmetric-key cryptography, if every person in a group of 10 people needs to communicate with every other person in the group, how many secret keys are needed?arrow_forward
- Encrypt the 12-bit plaintext 101010100111 using Simplified B-DES and the 9-bit key K = 010001111. This is a non-computer problem and you need to show all the steps of the encryption processarrow_forwardIn symmetric-key cryptography, if every person in a group of 10 people needs to communicate with every other person in another group of 10 people, how many secret keys are needed?arrow_forwardLet M be the message to be sent by using RSA cryptosystem. If (n, e) is the public key and (n, d) is the private key, which of the following is the encryption function that will yield the cipher text that corresponds to M? О Е(M) — Ме mod (p - 1) (q — 1) О Е[M) — ма mod (p - 1)(q — 1) O E(M) = Me mod n О ЕМ) — Ма mod narrow_forward
- A block cipher has block length 3. When the key is k, the results of encrypting a block with this cipher are given in the table below: m E(m, k) m E(m, k) 000 011 100 101 001 111 101 110 010 001 110 010 011 000 111 100 (i) Decrypt the ciphertext 010011011 given that it was created by using this block cipher in CBC mode, with key k and IV 111. (ii) Decrypt the ciphertext 010011011 given that it was created by using this block cipher in ECB mode, with key k. (iii) Decrypt the ciphertext 010011011 given that it was created by using this block cipher in CTR mode, with key k and initial counter value 100.arrow_forwardBob has chosen p=11,q=17,and b=23 to be used in an RSA cryptosystem.(a) Determine n. (b) Determine a. (c) Choose all private parameter(s).arrow_forwardNote: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m 4. The plaintext given by 01110111 when encrypted by the LFSR produced the ciphertext 00001101 Y0Y1Y2Y3Y3Y5Y6Y7 What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3 = 0, p2 = 1, P1 = 0, Po = 1).arrow_forward
- The answer above is NOT correct. Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 11100010 — ХоXјX2XҙX4XsX6X7 when encrypted by the LFSR produced the ciphertext 11010110 — Уo У1 У2 Уз Уз У5 У6 Ут. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3 = 0, p2 = 1, p1 = 0, po = 1). 0010arrow_forward5. Use RSA public-key encryption to decrypt the message 111 using the private keys n = 133 and d = 5.arrow_forwardNote: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 11000101 — ХоXјX2XҙХ4X5X6X7 when encrypted by the LFSR produced the ciphertext 10010000 Уo У1 У2 Уз Уз У5 У6 Ут . What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, p2 = 1, p1 = 0, po = 1).arrow_forward
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