Evaluating a function In Exercises 11 and 12 evaluate the
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Chapter 12 Solutions
Calculus (MindTap Course List)
- Interpreting directional derivatives Consider the functionƒ(x, y) = 3x2 - 2y2.a. Compute ∇ƒ(x, y) and ∇ƒ(2, 3).b. Let u = ⟨cos θ, sin θ⟩ be a unit vector. At (2, 3), for what values of θ (measured relative to the positive x-axis), with 0 ≤ θ < 2π, does the directional derivative have its maximum and minimum values? What are those values?arrow_forwardSketch the plane curve represented by the vector-valued function and give the orientation of the curve. r(0) = cos(0)i + 6 sin(0)j O O -2 -2 y 5 -5 y -5 2 2 6 X X -6 -4 -2 -6 -4 -2 y 2 2 4 4 6 X Xarrow_forwardTangent lines Suppose the vector-valued function r(t) = ⟨ƒ(t), g(t), h(t)⟩ is smooth on an interval containing the point t0. The line tangent to r(t) at t = t0 is the line parallel to the tangent vector r'(t0) that passes through (ƒ(t0), g(t0), h(t0)). For each of the following functions, find an equation of the line tangent to the curve at t = t0. Choose an orientation for the line that is the same as the direction of r'.arrow_forward
- Tangent lines Suppose the vector-valued function r(t) = ⟨ƒ(t), g(t), h(t)⟩ is smooth on an interval containing the point t0. The line tangent to r(t) at t = t0 is the line parallel to the tangent vector r'(t0) that passes through (ƒ(t0), g(t0), h(t0)). For each of the following functions, find an equation of the line tangent to the curve at t = t0. Choose an orientation for the line that is the same as the direction of r'. r(t) = ⟨3t - 1, 7t + 2, t2⟩; t0 = 1arrow_forward(5) Let ß be the vector-valued function 3u ß: (-2,2) × (0, 2π) → R³, B(U₁₂ v) = { 3u² 4 B (0,7), 0₁B (0,7), 0₂B (0,7) u cos(v) VI+ u², sin(v), (a) Sketch the image of ß (i.e. plot all values ß(u, v), for (u, v) in the domain of ß). (b) On the sketch in part (a), indicate (i) the path obtained by holding v = π/2 and varying u, and (ii) the path obtained by holding u = O and varying v. (c) Compute the following quantities: (d) Draw the following tangent vectors on your sketch in part (a): X₁ = 0₁B (0₂7) B(0)¹ X₂ = 0₂ß (0,7) p(0.4)* ' cos(v) √1+u² +arrow_forwardMotion around a circle of radius a is described by the 2D vector-valued function r(t) = ⟨a cos(t), a sin(t)⟩. Find the derivative r′ (t) and the unit tangent vector T(t), and verify that the tangent vector to r(t) is always perpendicular to r(t).arrow_forward
- Header & Footer Text Consider the vector-valued function = ( 4 cos(t) + 2 sin(t), -cos(t) + V5 4 sin(t), V105 f(t)%3D 20 V105 VI05 sin(e) (a) Compute the first derivative and the nmagnitude of the first derivative. (Hint: Make sure to simplify your answer for the magnitude as much as possible! There will be magic cancellations.) (b) Are ^r(t) and ^r0°(t) perpendicular for all t? (Hint: You do not need to compute the second derivative. Use the formula (1*OF)' = (*"(t) · (1) = 26"(1) · i'(1) and your answer from part a.) (c) Use your answer from part b. to compute the principal normal vector in termns of the second derivative r00(E). (Hint: Your answer should involve the symbol r 0t). Do not compute the second derivative).arrow_forward1) Consider the vector function ?(?) = 〈cos(3?) , 2sin(−3?) ,?〉. Analyze the function, then sketch a graph.arrow_forwardThe motion of a point on the circumference of a nolling wheel of radius 4 feet is described by the vector function F(0) - 4(26t sin(261))i + 4(1 - cos( 26 Find the velocity vector of the point. ü(t) = Find the acceleration vector of the point. a(t) Find the speed of the point. s(t)= Submit Questionarrow_forward
- esc Find the second derivative of the vector-valued function r(t) = (4t + 3 sin(t))i + (5t + 3 cos(t)) 7'' (t) = Check Answer F1 @ [244 116,535 2 F2 W #3 80 F3 LL $ 4 AUG Q F4 R Q % 5 0 F5 T tv F6 & Y 7 F7arrow_forwardDetermine the domain of the vector function r(t) = cos(4t) i + 7In(t - 5) j - 10 k Evaluate if the vector function is possible at the value of t=8, round to two tenths Find the derivative of the vector function r(t)arrow_forwardLet F(t) = (31³-3, 4et, -sin(4t)) Find the unit tangent vector T(t) at the point t = 0 T(0) = < 0 Question Help: Add Work " Videoarrow_forward
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