Chapter 12, Problem 12.93SP

(a)

Interpretation Introduction

Interpretation:

For the substitution reaction of molybdenum hexacarbonyl, the overall reaction has to be given.

(b)

Interpretation Introduction

Interpretation:

For the substitution reaction of molybdenum hexacarbonyl, the molecularity of each elementary reaction has to be given.

Concept introduction:

Molecularity of reaction:

Unimolecular: A molecule (reactant) undergoes rearrangement itself to give one or more products is said to be unimolecuar reactions.

Bimolecular: Two molecules (reactants) undergo collisions to give one or more products is said to be bimolecular reactions.

Termolecular: Three molecules undergo collision to give one or more products is said to be termolecular reactions.

(c)

Interpretation Introduction

Interpretation:

For the substitution reaction of molybdenum hexacarbonyl, the rate law has to be given.

Concept introduction:

Rate law of a reaction:

It is an equation that related to the dependence of the reaction rate on the concentration of each substrates (reactants).

$\begin{array}{l}\text{For}\text{a}\text{reaction}\\ \\ \text{aA}\text{+}\text{bB}\stackrel{}{\to }\text{Products}\\ \\ \text{A}\text{and}\text{B}\text{are}\text{reactants}\text{and}\text{a}\text{and}\text{b}\text{are}\text{stoichiometric}\text{coefficients}\text{.}\\ \\ \text{Rate}\text{=}\text{-}\frac{\text{Δ}\left[\text{A}\right]}{\text{Δt}}\text{=}\text{k}{\left[\text{A}\right]}^{\text{m}}{\left[\text{B}\right]}^{\text{n}}\\ \\ \text{where,}\text{k}\text{-}\text{rate}\text{constant}\text{.}\end{array}$