Organic Chemistry
Organic Chemistry
5th Edition
ISBN: 9780078021558
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 12, Problem 12.7P
Compound Molecular formula before hydrogenation Molecular formula after hydrogenation Number of rings Number of pi bonds
A C 10 H 12 C 10 H 16 ? ?
B ? C 4 H 10 0 1
C C 6 H 8 ? 1 ?

Complete the missing information for compounds A, B, and C, each subjected to hydrogenation.

The number of rings and π bonds refers to the reactant (A, B, or C) prior to hydrogenation.

Expert Solution & Answer
Check Mark
Interpretation Introduction

Interpretation: The missing information in the given table is to be completed.

Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.

Answer to Problem 12.7P

The missing information about compounds A, B and C is completed in the table given below.

Compound Molecular formula before hydrogenation Molecular formula after hydrogenation Number of rings Number of pi bonds
A C10H12 C10H16 2 3
B C4H8 C4H10 0 1
C C6H8 C6H12 1 2

Explanation of Solution

For compound A:

Before hydrogenation, the molecular formula is C10H12.

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 10C's is 2(10)+2=22.

The number of H's fewer than the maximum is calculated by formula,

FewerthanmaximumH's=MaximumH'sActualH's

Substitute the values of maximum number of H's possible and actual H's in the above formula.

FewerthanmaximumH's=22H's12H's=10H's

The degree of unsaturation is calculated by the formula,

Degreeofunsaturation=H'sfewerthanthemaximum2H'sremovedforeachdegreeofsaturation=102=5

Hence, the degree of unsaturation before hydrogenation is five. After hydrogenation, the molecular formula is C10H16.

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 10C's is 2(10)+2=22.

The number H's fewer than the maximum is calculated by formula,

MaximumH'sActualH's=FewerthanmaximumH's

Substitute the values of maximum number of H's possible and actual H's in the above formula.

FewerthanmaximumH's=22H's16H's=6H's

The degree of unsaturation is calculated by the formula,

Degreeofunsaturation=H'sfewerthanthemaximum2H'sremovedforeachdegreeofsaturation=62=3

Hence, the degree of unsaturation after hydrogenation is three.

The number of pi bonds in A is calculated by the formula,

Numberofπbonds=(DegreeofunsaturationbeforehydrogenationDegreeofunsaturationafterhydrogenation)

Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.

Numberofπbonds=53=2

Hence, the number of pi bonds is two.

Number of rings is calculated by the formula,

Degreeofunsaturation=Numberofπbonds+Numberofrings

Substitute the values of degree of unsaturation and number of pi bonds in the above formula.

5=2+NumberofringsNumberofrings=52=3

Hence, the number of rings is three.

For compound B:

After hydrogenation, the molecular formula is C4H10.

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 4C's is 2(4)+2=10.

The number of H's fewer than the maximum is calculated by formula,

FewerthanmaximumH's=MaximumH'sActualH's

Since both maximum number of H's possible and actual H's are same. The number of H's fewer than the maximum is zero.

Hence, the degree of unsaturation after hydrogenation is zero.

The number of pi bonds in B is calculated by the formula,

Numberofπbonds=(DegreeofunsaturationbeforehydrogenationDegreeofunsaturationafterhydrogenation)

Substitute the values of number of pi bonds and degree of unsaturation after hydrogenation in the above formula.

Degreeofunsaturationbefore hydrogenation=0+1=1

Hence, degree of unsaturation before hydrogenation is one.

Before hydrogenation,

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 4C's is 2(4)+2=10.

The degree of unsaturation is calculated by the formula,

Degreeofunsaturation=H'sfewerthanthemaximum2H'sremovedforeachdegreeofsaturation1=H'sfewerthanthemaximum2H'sfewerthanthemaximum=2

Hence, the number of H's fewer than the maximum is two.

The number H's fewer than the maximum is calculated by formula,

FewerthanmaximumH's=MaximumH'sActualH's

Substitute the values of maximum number of H's possible and H's fewer than the maximum in the above formula.

ActualH's=10H's2H's=8H's

Hence, the molecular formula before hydrogenation is C4H8.

For compound C:

Before hydrogenation, the molecular formula is C6H8

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 10C's is 2(6)+2=14.

The number H's fewer than the maximum is calculated by formula,

FewerthanmaximumH's=MaximumH'sActualH's

Substitute the values of maximum number of H's possible and actual H's in the above formula.

FewerthanmaximumH's=14H's8H's=6H's

The degree of unsaturation is calculated by the formula,

Degreeofunsaturation=H'sfewerthanthemaximum2H'sremovedforeachdegreeofsaturation=62=3

Hence, the degree of unsaturation before hydrogenation is three.

Number of rings is calculated by the formula,

Degreeofunsaturation=Numberofπbonds+Numberofrings

Substitute the values of degree of unsaturation and number of rings in the above formula.

Numberofπbonds=31=2

Hence, the number of pi bonds is two.

The degree of unsaturation after hydrogenation is equal to the number of rings present in the compound. Hence, degree of unsaturation after hydrogenation is one.

After hydrogenation,

The maximum number of H's possible for nC's is 2n+2.

The maximum number of H's possible for 10C's is 2(6)+2=14.

The degree of unsaturation is calculated by the formula,

Degreeofunsaturation=H'sfewerthanthemaximum2H'sremovedforeachdegreeofsaturation1=H'sfewerthanthemaximum2H'sfewerthanthemaximum=2

Hence, the number of H's fewer than the maximum is two.

The number H's fewer than the maximum is calculated by formula,

MaximumH'sActualH's=FewerthanmaximumH's

Substitute the values of maximum number of H's possible and H's fewer than the maximum in the above formula.

ActualH's=14H's2H's=12H's

Hence, the molecular formula before hydrogenation is C6H12.

The missing information about compounds A, B and C is completed in the table given below.

Compound Molecular formula before hydrogenation Molecular formula after hydrogenation Number of rings Number of pi bonds
A C10H12 C10H16 2 3
B C4H8 C4H10 0 1
C C6H8 C6H12 1 2

Table 1

Conclusion

The missing information about compounds A, B and C is completed in the table 1.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Draw an expanded structural formula of pent-1-en-3-yne/ CH3-CC-CH=CH2 and then label each carbon. Indicate the longest and shortest C-H bond and predict the C—C single bond that has the highest BDE(bond dissociation energy).
Give an example of a compound with molecular formula CgH10 that satisfies each criterion. a. a compound with two a bonds b. a compound with one ring and one a bond c. a compound with two rings d. a compound with one triple bond
13 YouTube esc Cc app.101edu.co Maps H₂ H H₂ H₂ H₂ H₂CCCCC-C-CH2 CH3 CH3 CH3 :0³ F4 1 option ! 1 A F1 Q Bb Bl Z CH 2 F2 W S X H command #3 20 F3 E D C Ac Th Be QC G W G 51 Question 26 of 48 Name the compound below according to IUPAC rules. A) 5-methylnonane B) isodecane C) 2,2-dibutylethane D) 1,4,7-trimethylheptane E) decane DII F8 $ 4 R F % 5 V F5 T X G 6 B Y H & 7 F7 U | Ak Mb Hc G 17 C SCUO NE S 1s N * 00 8 J M 9 K F9 O O L 4 F10 P > & F11 Ba Gra TE { + 11 ? H t command option 11 KR₂ + ☆ C F12 +

Chapter 12 Solutions

Organic Chemistry

Ch. 12 - Problem 12.11 (a) Draw the structure of a compound...Ch. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Problem 12.14 Draw the products of each...Ch. 12 - Prob. 12.15PCh. 12 - Problem 12.16 Draw all stereoisomers formed when...Ch. 12 - Prob. 12.17PCh. 12 - Problem 12.18 Draw the products formed when both...Ch. 12 - Problem 12.19 Draw the products formed when each...Ch. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Problem 12.22 Draw the products formed when each...Ch. 12 - Prob. 12.23PCh. 12 - Problem 12.24 Draw the organic products in each of...Ch. 12 - Prob. 12.25PCh. 12 - Prob. 12.26PCh. 12 - Problem 12.27 Draw the products of each Sharpless...Ch. 12 - Prob. 12.28PCh. 12 - 12.29 Draw the products formed when A is treated...Ch. 12 - Prob. 12.30PCh. 12 - 12.31 Devise a synthesis of the following compound...Ch. 12 - Prob. 12.32PCh. 12 - Prob. 12.33PCh. 12 - Prob. 12.34PCh. 12 - Prob. 12.35PCh. 12 - Prob. 12.36PCh. 12 - 12.37 Stearidonic acid (C18H28O2) is an...Ch. 12 - Draw the organic products formed when cyclopentene...Ch. 12 - Draw the organic products formed when allylic...Ch. 12 - Draw the organic products formed in each reaction....Ch. 12 - Prob. 12.41PCh. 12 - Prob. 12.42PCh. 12 - Prob. 12.43PCh. 12 - What alkene is needed to synthesize each 1,2-diol...Ch. 12 - Prob. 12.45PCh. 12 - 12.46 (a)What product is formed in Step [1] of the...Ch. 12 - Draw the products formed after Steps 1 and 2 in...Ch. 12 - 12.48 Draw the products formed in each oxidative...Ch. 12 - What alkene or alkyne yields each set of products...Ch. 12 - Prob. 12.50PCh. 12 - Prob. 12.51PCh. 12 - Prob. 12.52PCh. 12 - Prob. 12.53PCh. 12 - 12.54 An unknown compound A of molecular formula ...Ch. 12 - 12.55 DHA is a fatty acid derived from fish oil...Ch. 12 - Prob. 12.56PCh. 12 - 12.57 Draw the product of each asymmetric...Ch. 12 - 12.58 Epoxidation of the following allylic alcohol...Ch. 12 - Prob. 12.59PCh. 12 - 12.60 Identify A in the following reaction...Ch. 12 - Prob. 12.61PCh. 12 - 12.62 It is sometimes necessary to isomerize a cis...Ch. 12 - 12.63 Devise a synthesis of each compound from...Ch. 12 - Prob. 12.64PCh. 12 - Prob. 12.65PCh. 12 - 12.66 Devise a synthesis of each compound from the...Ch. 12 - Prob. 12.67PCh. 12 - Prob. 12.68PCh. 12 - 12.69 Devise a synthesis of each compound from as...Ch. 12 - Prob. 12.70PCh. 12 - Prob. 12.71PCh. 12 - 12.72 Draw a stepwise mechanism for the following...Ch. 12 - Prob. 12.73PCh. 12 - Prob. 12.74PCh. 12 - 12.75 Sharpless epoxidation of allylic alcohol X...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Chapter 4 Alkanes and Cycloalkanes Lesson 2; Author: Linda Hanson;https://www.youtube.com/watch?v=AL_CM_Btef4;License: Standard YouTube License, CC-BY
Chapter 4 Alkanes and Cycloalkanes Lesson 1; Author: Linda Hanson;https://www.youtube.com/watch?v=PPIa6EHJMJw;License: Standard Youtube License