Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 11, Problem 71P
To determine
The gravitational field strength at the surface of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
a
met
icle
an
he
$
4
R
▼
888
F4
Part A
Consider a uniform gravitational field (a fair approximation near the surface of a planet). Find
U(y)-U(yo)= Fg. ds.
where
F₁
= -mg j and ds = dy j.
Express your answer in terms of m, g, yo, and yf.
View Available Hint(s)
IVD ΑΣΦ
?
U(yf) - U (yo) =
Submit
Part B
Consider the force exerted by a spring that obeys Hooke's law. Find
II(₂)
II(-).
APR
tv
28
%
5
F5
T
6
F6
Y
&
7
F7
U
*
8
²² de
DII
F8
(
9
A
DD
F9
0
)
O
3 of 26
Review | Constants
F10
P
I
Three masses, MA = Mg = Mc = M are placed at the vertices
of a right triangle ( ill slE ¿ilia wg'} ) de), as shown in the
figure below. The distance between Ma and M, is similar
to that between Mc and Mg and is equal to R. The
magnitude of the net gravitational force exerted on Mg is
given by:
%3D
%3D
MA
A. 1.41 (GM/R)
B. 1.41 (GM/R?)
C. 1.41 (GM²/R?)
D. 1.41 (G?M/R?)
1.41 (G?M?/R?)
R
E.
Ms
Mc
R
O A
OB
Exoplanet Taphao Keow is a Jupiter-sized planet orbiting another star. It has a mass
of approximately 1×10+27[kg]. Its actual radius is not currently known, but we do
know that the radius of Jupiter is 7×107[m].
Question: If Taphao Keow had a radius that was the same radius as Jupiter, what
would it's local surface gravitational acceleration be?
O 266 [m/s2]
124 [m/s²]
70 [m/s²]
O 24 [m/s²]
O 14 [m/s²]
It would have a gravitational acceleration far larger than any of the other
answers (many orders of magnitude larger)
It would have a gravitational acceleration far smaller than any of the other
answers (many orders of magnitude larger)
Chapter 11 Solutions
Physics for Scientists and Engineers
Ch. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Prob. 3PCh. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Prob. 9PCh. 11 - Prob. 10P
Ch. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Prob. 14PCh. 11 - Prob. 15PCh. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 18PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 25PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - Prob. 36PCh. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 50PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55PCh. 11 - Prob. 56PCh. 11 - Prob. 57PCh. 11 - Prob. 58PCh. 11 - Prob. 59PCh. 11 - Prob. 60PCh. 11 - Prob. 61PCh. 11 - Prob. 62PCh. 11 - Prob. 63PCh. 11 - Prob. 64PCh. 11 - Prob. 65PCh. 11 - Prob. 66PCh. 11 - Prob. 67PCh. 11 - Prob. 68PCh. 11 - Prob. 69PCh. 11 - Prob. 70PCh. 11 - Prob. 71PCh. 11 - Prob. 72PCh. 11 - Prob. 73PCh. 11 - Prob. 74PCh. 11 - Prob. 75PCh. 11 - Prob. 76PCh. 11 - Prob. 77PCh. 11 - Prob. 78PCh. 11 - Prob. 79PCh. 11 - Prob. 80PCh. 11 - Prob. 81PCh. 11 - Prob. 82PCh. 11 - Prob. 83PCh. 11 - Prob. 84PCh. 11 - Prob. 85PCh. 11 - Prob. 86PCh. 11 - Prob. 87PCh. 11 - Prob. 88PCh. 11 - Prob. 89PCh. 11 - Prob. 90PCh. 11 - Prob. 91PCh. 11 - Prob. 92PCh. 11 - Prob. 93PCh. 11 - Prob. 94PCh. 11 - Prob. 95PCh. 11 - Prob. 96PCh. 11 - Prob. 97PCh. 11 - Prob. 98PCh. 11 - Prob. 99PCh. 11 - Prob. 100PCh. 11 - Prob. 101PCh. 11 - Prob. 102PCh. 11 - Prob. 103PCh. 11 - Prob. 104PCh. 11 - Prob. 105PCh. 11 - Prob. 106PCh. 11 - Prob. 107P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- On a planet whose radius is 1.2107m , the acceleration due to gravity is 18m/s2 . What is the mass of the planet?arrow_forwardWhat is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardLet gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forward
- Compute directly the gravitational force on a unit mass at a point exterior to a homogeneous sphere of matter.arrow_forwardA 4.4 kg mass weighs 35.64 N on the surfaceof a planet similar to Earth. The radius ofthis planet is roughly 6 × 10^6 m.Calculate the mass of of this planet. Thevalue of the universal gravitational constantis 6.67259 × 10^−11 N · m^2/kg^2.Answer in units of kg. Calculate the average density of this planet.Answer in units of kg/m^3.arrow_forwardThe density inside a solid sphere of radius a is given by p=Po a/r, where Po is the density at the surface and r denotes the distance from the center. Find the gravitational field due to this sphere at a distance 2 a from its center.arrow_forward
- A spherical shell of inner diameter R and outer diameter 3 R has a uniform density ρ. What is the magnitude of the gravitational acceleration a distance R from the center of the spherical shell?arrow_forwardThe radius Rhand mass Mh of a black hole are related by Rh = 2GMh/c2, where c is the speed of light. Assume that the gravitational acceleration agof an object at a distance ro= 1.001Rh from the center of a black hole is given by ag = G M / r2 (it is, for large black holes).(a) In terms of Mh, find ag at ro.(c) What is ag at rofor a very large black hole whose mass is 1.69 × 1015 times the solar mass of 1.99 × 1030 kg?(d) If an astronaut with a height of 1.73 m is at rowith her feet toward this black hole, what is the difference in gravitational acceleration between her head and her feet ahead-afeet?arrow_forwardWhat is the ratio of the sun's gravitational pull on Mercury to the sunfs gravitational pul on the earth? The radius of the orbit of Mercury is RM 5.79 x 10 m and its mass is my - 1.50 × 10 m and its mass is mp = 5,97 x 10 kg 5.97 x 1024 kg =D3.30x10 kg. The radius of the orbit of Earth is Rp 阳 AX中 FM FEarrow_forward
- The rings of the planet Saturn consist of particles of rock and ice which orbit the = 5.7 × 104ºkg. Suppose a particle has a planet. The mass of Saturn is MSat mass 2,806 kg, and is orbiting at a distance of 2,442 km from the surface of Saturn. The radius of Saturn is ľsat G = 6.67 × 10-1'm². kg¬1.s-2 60, 300 km and Calculate the magnitude of the gravitational attract between the particle and Saturn to 2 sf. Your Answer: Answerarrow_forwardWhat is the gravitational acceleration close to the surface of a planet with a mass of 4M- and radius of 4RE, where M- and RE are the mass and radius of Earth, respectively? Answer as a multiple of g, the magnitude of the gravitational acceleration near Earth's surface.arrow_forwardIn introductory physics laboratories, a typicalCavendish balance for measuring the gravitational constant G uses lead spheres of masses1.68 kg and 14.4 g whose centers are separatedby 2.7 cm.Calculate the gravitational force betweenthese spheres, treating each as a point masslocated at the center of the sphere. Thevalue of the universal gravitational constantis 6.67259 × 10−11 N · m2/kg2.Answer in units of N.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Gravitational Force (Physics Animation); Author: EarthPen;https://www.youtube.com/watch?v=pxp1Z91S5uQ;License: Standard YouTube License, CC-BY