a.
Interpretation:
The number of carbon atoms in 45.6 g sample of ethanol needs to be determined.
Concept introduction:
In 1 mol of any substance, there are
a.
Answer to Problem 42PP
Explanation of Solution
Given information:
The mass of ethanol is 45.6 g and molecular formula of ethanol is CH3CH2OH.
Calculation: From the given formula, molar mass of ethanol can be calculated from
Therefore,
The mass of ethanol is given 45.6 mol. The number of moles can be calculated as follows:
From the molecular formula 1 mol of ethanol contains 2 mol of C atoms. Thus, the number of moles of C atoms will be:
Now, in 1 mol of any substance there are
Therefore, number of carbon atoms is
b.
Interpretation:
The number of hydrogen atoms present in the sample needs to be determined.
Concept introduction:
In 1 mol of any substance, there are
b.
Answer to Problem 42PP
The number of hydrogen atoms present in the sample is
Explanation of Solution
From the molecular formula 1 mol of ethanol contains 6 mol of H atoms. Thus, the number of moles of H atoms will be:
Now, in 1 mol of any substance there are
Therefore, number of hydrogen atoms is
c.
Interpretation:
The number of oxygen atoms present in the sample needs to be determined.
Concept introduction:
In 1 mol of any substance, there are
c.
Answer to Problem 42PP
The number of oxygen atoms present in the sample is
Explanation of Solution
From the molecular formula 1 mol of ethanol contains 1 mol of O atoms. Thus, the number of moles of O atoms will be:
Now, in 1 mol of any substance there are
Therefore, number of oxygen atoms is
Chapter 10 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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