You have the plasmid pUC18/19, which is a circular plasmid that consists of 2686 bp. What would the number of and length of the fragments be if you cut the plasmid with the following restriction enzymes or combination of enzymes? Give a schematic representation of the digestions. a. PscI & GsuIb. ScaI, PdmI & BsaXIc. ScaI, SspI & EheI2
Molecular Techniques
Molecular techniques are methods employed in molecular biology, genetics, biochemistry, and biophysics to manipulate and analyze nucleic acids (deoxyribonucleic acid (DNA) and ribonucleic acid (RNA)), protein, and lipids. Techniques in molecular biology are employed to investigate the molecular basis for biological activity. These techniques are used to analyze cellular properties, structures, and chemical reactions, with a focus on how certain molecules regulate cellular reactions and growth.
DNA Fingerprinting and Gel Electrophoresis
The genetic makeup of living organisms is shown by a technique known as DNA fingerprinting. The difference is the satellite region of DNA is shown by this process. Alex Jeffreys has invented the process of DNA fingerprinting in 1985. Any biological samples such as blood, hair, saliva, semen can be used for DNA fingerprinting. DNA fingerprinting is also known as DNA profiling or molecular fingerprinting.
Molecular Markers
A known DNA sequence or gene sequence is present on a chromosome, and it is associated with a specific trait or character. It is mainly used as a genetic marker of the molecular marker. The first genetic map was done in a fruit fly, using genes as the first marker. In two categories, molecular markers are classified, classical marker and a DNA marker. A molecular marker is also known as a genetic marker.
DNA Sequencing
The most important feature of DNA (deoxyribonucleic acid) molecules are nucleotide sequences and the identification of genes and their activities. This the reason why scientists have been working to determine the sequences of pieces of DNA covered under the genomic field. The primary objective of the Human Genome Project was to determine the nucleotide sequence of the entire human nuclear genome. DNA sequencing selectively eliminates the introns leading to only exome sequencing that allows proteins coding.
![Plasmid map of pUC18/19
Eco01091 2674 Pfol 46 BstAPI 179
Aatill 2617
Sspl 2501
Ndel 183
Ehel 235
Pdml 2294,
MCS
lacz
\2485
Bogl 2215
Scal 217
PUC18/19
2686 bp
BsaXI 659
Sapl 683
LAAII, Pscl 806
Geul 1784.
Cfr101 1779
DNA0311 176
1626
rep (PMB1)
\Cail 1217
1466
Eam11051 1694
\BseYl 1110
migratipn
*C AE CG s eTC N aTI OGA ACG IAC
Lasd- L An Len Ser a a与年r如 u Pe Ap Se Se Se
CA AAG GAC
Vet The Met
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You are given 0.7 M solution of the amino acid Lysine.
pK1 (α-carboxyl group) = 2.18
pK2 (α- amino group) = 8.95 and
pK3 (Side chain) = 10.53
Answer the following questions.
Determine the pH of the solution if you add 26 mL 0.3 M HCl to 12 mL of the 0.7 M Lysine. Assume that Lysine is in isotonic state. Show all calculations.