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- From the Hill Plot below, the KD of the first binding event for the receptor-ligand system under study is: 10 8 6 4 2 0 -2 4 6 8 10 (0=1) 601 log -4- -6 -6 -4 -2 0 2With the following information: Cr20,2- + 14 H* + 6 e¯ =2Cr** + 7 H2O E° = 1330 mV Cr(OH)3(s) = Cr³+ + 3 HO- pK, = 30,2 HCRO4¯ + H2O =Cr0,2- + H3O* pKa = 6,51 %3D 2 HCrO4¯ = Cr20,²- + H2O log Ka = 1,63 2 H2O = HO¯ + H3O* log K, = -14 Calculate the standard potential of: HC•O,²- + 4 H20+3e¯= Cr(OH)3(s) + 5 HO- |The following is a Hill Plot for a receptor-ligand interaction: 00 6 (0-1) 60 log 4 2 0 -2 -4 -6 -6 0 2 4 6 8 10 log [L] (nM) T What fold-difference exists between the KD of the first and the KD of the second binding event? 1,000,000 6 10,000,000,000 2 10
- For a tungsten carbene (catalyst) binding to THF (ligand) at 25 oC in per-deuterotoluene solvent, the chemical shift of the unbound catalyst alpha hydrogen was determined to be 794.6 Hz and the peak for the fully bound catalyst alpha hydrogen was observed at 842.4 Hz. Furthermore, the binding constant (or formation constant) Kf was found to be 15.40 M-1. Given the following initial concentrations of catalyst and ligand, calculate the percent THF bound you would expect to see at 25 oC. Record your answer to the nearest tenths of a percent, as a number with no units (Ex. 3.4% ----> enter "3.4") Co = 1.000 M Lo = 0.1000 MThe two structures for Iron - penta - carbonyl: Ço OC. oc-Fe" oc co (A) (B) .Structure A has a rCO = 2A1 + B1 + E .Structure B has a rCO = 2A'1+ E' + A"2 The IR spectrum of Fe(CO)5 gave 3 different CO stretches at 1521 cm-1, 1548 cm-1 and 1732 cm-1 1. What of the 2 structures is observed and why that structure? and what could be seen of this compound in a raman spectro?Calculate the absorbance at 280 nm that is expected for a 17 microM solution of peptide GRAYISH, if a 10-cm cuvette is used. For the extinction coefficient, take into account that e280(Trp) = 5690 M-1 cm-1 and e280(Tyr) = 1280 M-1 cm-1.
- Transferrin is an iron-transport protein found in blood. Desferrioxamine B is an iron chelator used to treat patients suffering from iron overload. Both are colourless in the absence of iron. The following data was obtained in aqueous solution using a 1.00 cm path length cell for both species when fully complexed with iron: Molar absorptivity M-1 cm- A (nm) iron-transferrin iron-desferrioxamine B 428 3540 2730 470 4170 2290 Calculate the absorbance at 470 nm of a solution that is 11.0 u M in iron-transferrin and 69.5 u M in iron-desferrioxamine B, assuming both are fully complexed and that the cell path length is 1.00 cm. O A. 0.0206 O B. 0.206 O C. 0.412 O D.0.103The absorption coefficient of rhodopsin at 496 nm is 40,000 M-1cm-1. If you have a 1M solution of rhodopsin, how many times will you dilute the solution so that the diluted solution will give you an absorption reading at 496 nm that is in the range of 0.1-1.0. And what will be the absorption by the diluted solution?1) Pd (II) with Au (III) methiomeprazine (C19 H24 N2 S2) complex. A mixture of their complexes is being analyzed. Pd (II) complex at 480 nm, The measurement results for Au (II) with a maximum peak at 635 nm are as follows. Of this mixture What is its concentration? (b = 1) Pd(II) ɛ Au(III)ɛ 2.96x 103 A 480 nm 3.55x 103 0.533 635 nm 5.64x 102 1.45x 104 0.590
- 1. Question: Pd (1I), Au (III) methiomeprazine (C19 H24 N2S2) with the complex. A mixture of their complexesis being analyzed. Pd (II) complex at 480 nm, The measurement results for Au (III) with max peak at 635 nm are as follows. of the mixture What is the concentration?(b=1) Pd(II) Au(III) Mixture 480 nm 3,55x103 2,96x103 0,533 635 nm 5,641x0³ 1,45x10 0,590The resolution product of Ag2SO3 is 1.5 x 10-14. Calculate E0 for Ag2SO3(s) + 2e- ↔ 2 Ag(s) + SO32-. Ag+ + e- ↔ Ag E0 = + 0,799 VWhy is it reasonable that the Ksp of NiCl2 should be so high? given: NiCl2~~>Ni2+(aq)+2Cl-(aq) ksp=497.504 ksp=[Ni2+][Cl-]^2 [Ni2+]=4.992 [Cl-]=9.983