What are the R f values of the spots on this TLC plate? Solvent front |7.9 7.2 8.4 1.6 1.4 Baseline O 0.17 and 0.19. O 0.17 and 0.36. 0.18 and 0.38. O 0.19 and 0.22. O 0.19 and 0.42.
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- Silica gel is very polar stationary phase. Therefore, more polar molecule sticks to silica gel on the TLC plate and has higherRfvalue. True False1. A two-component mixture is analyzed by paper TLC. Component A is more soluble in the mobile phase than component B. The following result is obtained. Calculate the Rifor each component and label the identity of each Frond (3-0,4)CM3D2.6cmr A (2-6-04 m = 2.2cm B C67-0.ycm=0.3cm RF (A= 2.2cm = 0.85 2. Lem spot. 2 39で Solvent Front A0-2.6m %3D 3cm Spoting Line Rf (8- 0.3cm 2. Scm = 0.12 %3D 2. Which one is the more polar component? Explain IS morC polo Because its Rf Is low 3. If a more polar solvent (mgbil phase) is used for the above experiment, the result will be: O Both component A and Component B will travel further up the plate-Distance may verur b) Only Component A will travel further up the plat c) Only Component B will travel further up the plat d) They will travel on the plate the same distance as when a less polar Choose one of the answers and explain 4. Paper chromatography works as the same principle as TLC however, cellulose paper (the same as filter paper) is used for…True of false? 1. Raman Spectroscopy can be used in the airport to detect the presence of Alcohol in the bags? 2. Furnace atomisation is used when the concentration of the sample in the ppb level? 3. 24 karat of gold mean the percent of gold in the object is 75%?
- Determine the Kovats retention index for an unknown C9 sample using the retention times 1.3 min for benzene, 16.4 min for p-xylene, 18.7 min for the unknown C9 sample, and 20.4 min for p-divinyl benzene. Question 1 options: 864.862 846.801 892.106 920.663The following Rf values were computed from a normal phase chromatography experiment. Arrange them from most polar to least polar. I - 0.25 II - 0.84 III - 0.56 IV- 0.67 Group of answer choices II > IV > III > I I > III > IV > II I > II > III > IV IV > II > III > IWhat are the disadvantages of uses the Thick layer stationary phase in Thin layer Chromatography (TLC)? Please shortly answer at your own words. Answer should be to the point ( specific 4-5 lines).
- Which statements are true for molecular exclusion chromatography?I Molecular exclusion chromatography separates on the basis of size.II Small molecules can fit in the pores of the stationary phase and effectively pass through a larger volume, and elute last.III The pores in the stationary phase are too small for large molecules to pass through, so large molecules elute first.IV Molecular exclusion chromatography with a hydrophilic stationary phase and an aqueous solvent is called gel permeation chromatography. A. I, II, III B. III and IV C. II only D. I and II only E. I, III, and IVWhich statements are true for molecular exclusion chromatography?I Molecular exclusion chromatography separates on the basis of size.II Small molecules that freely pass through the stationary phase, Kav = 0.III Small molecules can fit in the pores of the stationary phase and effectively pass through a larger volume, and elute last.IV The pores in the stationary phase are too small for large molecules to pass through, so large molecules elute last.V Molecular exclusion chromatography with a hydrophilic stationary phase and an aqueous solvent is called gel permeation chromatography. A. II and V B. I, II, and IV C. III, IV, and V D. No correct combinations given above E. I, III, and IV F. I, II, III, and VIon exchange chromatography can be used to separate a mixture of cations and anions, true or false?
- The following data are for a liquid chromatographic column: Length of Packing 24.7 cm Flow rate 0.313 mL/min Vm 1.37 ml Vs 0.164 ml A chromatogram of a mixture of species A, B, C, and D provided the following data: 1. Width of Peak Base Retention Time, min (W), min Nonretained 3.1 A 5.4 0.41 13.3 1.07 C 14.1 1.16 D 21.6 1.72 Calculate the retention factor.The following data are for a liquid chromatographic column: Length of Packing 24.7 cm Flow rate 0.313 mL/min Vm 1.37 ml Vs 0.164 ml A chromatogram of a mixture of species A, B, C, and D provided the following data: Width of Peak Base Retention Time, min (W), min Nonretained 3.1 A 5.4 0.41 13.3 1.07 14.1 1.16 D 21.6 1.72 Calculate the plate height for the column.Two components in an HPLC separation have retention times that differ by 15 s. The first peak elutes in 9.0 min, and the peak widths are approximately equal. The dead time to was 65 s. Use a spreadsheet to find the minimum number of theoretical plates needed to achieve the following resolution. R. values: 0.50 0.75, 0.90, 1.0, 1.10. 1.25, 1.50. L75. 2.0 and 2.5. How would the results change if peak 2 were twice as broad as peak 1?