Water flows steadily downward along a pipe that is inclined at 30° below the horizontal, as shown. Pressure difference PA-PB is due partly to gravity and partly to friction. Evaluate the pressure difference if L = 1.5 m and h = 15 cm. Use p= 1000 kg/m³ and u = 1.12 x 103 Ns/m² for the water and p= 13600 kg/m³ and u= 1.57 x 103 Ns/m² for the mercury.

Water flows steadily downward along a pipe that is inclined at 30° below the horizontal, as shown. Pressure difference PA-PB is due partly to gravity and partly to friction. Evaluate the pressure difference if L = 1.5 m and h = 15 cm. Use p= 1000 kg/m³ and u = 1.12 x 103 Ns/m² for the water and p= 13600 kg/m³ and u= 1.57 x 103 Ns/m² for the mercury.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Problem (2) Neglecting friction, find the horizontal force of the water (N) on the horizontal bend shown in the figure. V, = 10 m/s %3D 8 cm dia. V2 4 cm Answer:
A pipeline with roughness ks = 1.0mm and diameter D = 8.8cm connects two reservoirs. The reservoirs are both open to the atmosphere and differ in surface elevation by H = 40m. The two reservoirs with the connecting pipe are shown in the figure below. You can assume density of water = 1003kg/m³, dynamic viscosity of water = 0.001Pas and acceleration due to gravity 9.81m/s². Local losses must be considered; assume reasonable values as introduced in the ENGG2500 lectures. Reservoir 1 = Pipe with: D,K, m. H a) What is the friction factor of the pipe for a flow rate of Q =44L/s? Provide your answer to 3 decimal places. The friction factor f = = b) For this case, what is the length of the pipe? Provide your answer to 3 decimal places. The length is L Reservoir 2
Problem (3) Find the rate of change of h(t) (mm/s) if water is the fluid at all locations. Use V₁ = 7.1 m/s and Q = 1000 L/min. m₂ = 10 kg/s 4 cm dia. V₁ Answer: 120 cm h(t) 8
A vertical U-tube partially filled with alcohol (SG= 0.99) is rotated at a specified rate about its left arm. Compute for the following: (a) angular velocity of the tube's rotation if the alcohol is on the brink of spilling (b) pressure at point B during the rotation of the tube Please provide explanation per line of solution. thanks 10 cm 20 cm B +12.5 cm - 12.5 cm 25 cm
A cylindrical tank 0.9 m in radius rests atop a platform 6 m high. Initially the tank is filled with water (p = 1 x 103kg/m3) to a depth ho= 3 m. A plug whose area is 6.3 cm2 is removed from an orifice in the side of the tank at the bottom. What is the speed of the stream as it strikes the ground?
(b) Use Bernoulli's energy balance equation (E = PV + 0.5*mU²), assume volume flow rate remains constant along the pipe such that (Q=UA), and assume that pressure is balanced manometer to perform the following derivations: (i) (ii) (iii) 1- P2 in the pipe (substitute U2 in this step). an expression for P₁ an expression for P₁ P2 in the U-tube manometer. Set the expressions in parts (i) and (ii) equal to one another and derive the flow equation: U₁ = 2 (Pm -1) gh BA - 1
Water flows through a Venturi meter, as shown in the figure. The pressures of the water at locations a and b in the pipe support columns of water that differ in height by L = 12 in. The atmospheric pressure is 14.7 Ibf/in?, the specific volume of water is 0.01604 ft/lb, and the acceleration of gravity is g = 32.0 ft/s?. Patm = 14.7 Ibr/in.? g = 32.0 ft/s² Water v = 0.01604 ft/lb Determine the difference in pressure between points a and b, in Ibf/in2?. Does the pressure increase or decrease from point a to point b? Sten 1
Q2/ A fluid containing (water, oil, sand) flowing through the tube and open to the atmosphere as shown in the figure below.. Note that p°- 1.013*105 Pa Calculate the absolute pressure (Pa). Density: Pwater = 1000 kg/m Pail = 800 kg/m Pand = 200 kg/m P. h3=12 cm hg al2cm oIL Pa h25 cm ng = 6 cm %3D Sand water
In the following figure the long tube is filled with water at 20°C. When valve A is closed, P₁-P₂ = 75kPa. When valve A is open and water flows at 500 m³/h, P₁ – P₂ = 160kPa What is the loss in lift due to friction between 1 and 2, for the condition in which the water flows? (p = 998 kg ,g = 9,812) m 73 1) Bomba R.SA (2)
As shown in the figure below, a cylindrical tank with a hole in the bottom and an air vent in the top is being filled with water. Given the following: Dtank = 4 ft hill = 8 ft NOG height of water in tank when tank is filled Qin = 10 gal/min %3D NOT UPL TO CHE diameter of hole Find: volumetric flowrate into tank EGG EXAM into the tank in slugs/second OT UPS XAM O NOT U EXAM (c) The rate at which the water level in the tank is mass flowrate (in slugs/second) of the water (b) The mass flowrate (in slugs/second) out of the tank UPLOAD TO CHE NOT UPLOAD when the water level reaches the fill height DO NOT UPL rising (in inches/minute) when the water level NOT UPL PLOAD TO CHEGG NOT UPLOAD TO CHEGG EXAM TO CHEGG EXAM OD TO CHEGG UP reaches the filled height то снE LOAD vent Dtank DO DO DO NOT UPLOADTO EXAM EX DO 0 DONOT UPLOA T Dhole G EXAM TO CNGO UPLOA hole mdotout
A pump discharges 8000 liters per minute of a certain brine solution (SG=1.20) to an evaporating pond. The intake line is 25cm in diameter and is at the same level as the pump discharge line, which is 15cm in diameter. The pressure at the inlet of the pump is -170mm of mercury. The pressure gage connected to the pipe discharge reads 150 kPa, and its center is 2.0mabove the center of the discharge flange. The vapor pressure of the brine solution is 40mm of Hg. If the pump efficiency is 80%. How much power is required?
A Closed tank of water with Length, I = 20 ft Height, h = 10.45 ft %3D Width, w = 5.6 ft Pgage = 0 kPa at the top before acceleration is accelerating at an angle of 38° with respect to the horizontal, where the x component of the acceleration is parallel to that of the length of the tank at a rate of 6.35 ft/s² . If the tank is 76% %3D full, calculate the pressure at the bottom of the left side of the tank and the force acting at the top of the tank during acceleration. Take note that the tank is fixed such that it remains parallel to the horizontal during acceleration