w Solid, unknown acid were contaminated with pure, adsorbed water prior to weighing out the Sample, what effect (i.e. higher, lower, or none) would this have on the determined molar mass? Explain your answer.
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- Why are adsorbate particles attracted and retained on the surface ofadsorbent?Qmax is maximum adsorption of acetic acid on activated carbon.If there is another organic compound that has high affinity to activated carbon in the same acetic acid solutions. How Qmax of acetic acid adsorption will change?Lower, Higher or same? EXPLAINIf initial and equilibrium concentration of acetic acid before and after the adsorption is 1 gmol/liter respectively and the volume of solution taken is 50ml.Then the weight of acetic acid adsorbed/unit mass of charcoal is a. 1 g b. 2 g с. 3 g d. 0 g
- i. Why Redox active gels are considered as ideal candidate to tune shapes, color, solubility, or display sol-togel transitions? Explain it with one example.What effect does molecular size have on the adsorption process?Question 3 3.1 Briefly describe why (and how) adsorption takes place on a solid surface. 3.2 Use your knowledge of adsorption isotherms according to Brunauer to compare adsorption behaviours depicted by graphs A and B below. (A) (B) 30 30 25 25 20 20 15 15 10 10 5 5 0.2 0.4 0.6 0.8 1 0.0000001 0.00001 0.001 0.1 p/p° p/p Vads [cm3/g] STP Vads (cm3/g] STP
- Q1) Describe in detail Process of Adsorption, its types and Industrial application.kindly answer this problem and follow this format GIVEN REQUIRED SOLUTION and write regibly thank you so much For the adsorption of a substance A from aqueous solution by charcoal at25oC the freundlich constants are n=3.0 and k=0.50 for y in grams per gramand C in grams per liter. What weight of a W is adsorbed by 2 g of charcoalfrom 1 L of a solution containing originally 2 g of the substance?3. Find the molar absorptivity coefficient, the R? assuming that Concentration Measured (ppm) absorbance the path length is 1 cm and the equation of the data. (give your 0.01 0.0715 0.03 0.2986 0.05 0.4995 answer rounded off to two 0.07 0.5563 0.1 0.794 decimal place with complete 0.12 0.9521 units). 0.14 1.1096 0.16 1.3864 0.18 1.4221 0.2 1.5163 0.23 1.7039 0.25 0.27 1.9034 2.2484