Using C++  common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. Ex: If the input is: 1712 the output is: 1712 has 29 days in February. Ex: If the input is: 1913 the output is: 1913 has 28 days in February. Your program must define and call the following function. The function should return the number of days in February for the input year. int DaysInFeb(int userYear) #include using namespace std; /* Define your function here */  int main() {    /* Type your code here. Your code must call the function. */    return 0; }

C++ Programming: From Problem Analysis to Program Design
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Author:D. S. Malik
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Chapter8: Arrays And Strings
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Using C++

 common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines the number of days in February for that year.

Ex: If the input is:

1712

the output is:

1712 has 29 days in February.

Ex: If the input is:

1913

the output is:

1913 has 28 days in February.

Your program must define and call the following function. The function should return the number of days in February for the input year.

int DaysInFeb(int userYear)

#include <iostream>
using namespace std;

/* Define your function here */ 

int main() {
   /* Type your code here. Your code must call the function. */

   return 0;
}

Expert Solution
Step 1

Logic:- 

check for leap year logic. 

If userYear%400==0 

 then it is leap year simply return 1 from function. 

Else if(userYear%100==0)

 then it is not leap year return 0 from function. 

Else if(userYear%4==0)

 then it is leap year and return 1 from function. 

 

In main check for returned value and display messages accordingly. 

End. 

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