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- For E. coli strains with the lac genotypes show below, use a plus sign (+) to indicate the synthesis of β-galactosidase and permease and a minus sign (–) to indicate no synthesis of the proteins.(A) strain A strain B pro-Pase protease DOCKING pro-Pase protease SNARES exist as complementary partners that carry out membrane fusions between appropriate ves- icles and their target membranes. In this way, a vesicle with a particular variety of v-SNARE will fuse only with a membrane that carries the complementary t-SNARE. In some instances, however, fusions of identical membranes (homotypic fusions) are known to occur. For example, when a yeast cell forms a bud, vesicles derived from the mother cell's vacuole move into the bud where they fuse with one another to form a new vacuole. These vesicles carry both v-SNARES and t-SNARES. Are both types of SNARES essential for this homotypic fusion event? FUSION Pase (B) 100 75 To test this point, you have developed an ingenious assay for fusion of vacuolar vesicles. You prepare vesicles from two different mutant strains of yeast: strain B has a defective gene for vacuolar alkaline phosphatase (Pase); strain A is defective for the protease…Under what conditions will the following partial diploid strain of E. coli convert chorismate to tryptophan (assume trp mutants function similarly to lac mutants)? trpR* trpP trpO* trpE* trpD* trpC* trpB* trpA*/ trpR trpP trpO° trpE trpD trpC trpB trpA ect the one BEST answer (2 oints! O never O only when tryptophan levels are low O constitutively O only when tryptophan is present O only when chorismate levels are low
- Given the following complementation chart for holes in Monstera, give me the biochemical (phenotype) pathway. A В D E Holes Class 1 + + + - - Class 2 + + Class 3 + + + Class 4 Class 5 + + - - + +Give only typing answer with explanation and conclusion For the genotype shown below, which best describes the expression of the B-galactosidase gene. I+ Oc Z+ / F’ Is Constitutive Repressed Inducible None of the aboveFor each of the following mutant E. coli strains,plot a 30-minute time course of concentration ofβ-galactosidase, permease, and acetylase enzymesgrown under the following conditions: For the first10 minutes, no lactose is present; at 10 minutes, lactosebecomes the sole carbon source. Plot concentration onthe y-axis, time on the x-axis. (Don’t worry about theexact units for each protein on the y-axis.)a. I− P+ o+ Z+ Y+ A+ / I+ P+ o+ Z− Y+ A+b. I− P+ ocZ+ Y+ A− / I+ P+ o+ Z− Y+ A+c. IsP+ o+ Z+ Y+ A+ / I− P+ o+ Z− Y+ A+d. I− P− o+ Z+ Y+ A+ / I− P+ ocZ+ Y− A+e. I− P+ o+ Z− Y+ A+ / I− P− ocZ+ Y− A+
- The intermediates A, B, C, D, E, and F all occur inthe same biochemical pathway. G is the product of thepathway, and mutants 1 through 7 are all G−, meaningthat they cannot produce substance G. The followingtable shows which intermediates will promote growthin each of the mutants. Arrange the intermediates inorder of their occurrence in the pathway, and indicatethe step in the pathway at which each mutant strain isblocked. A + in the table indicates that the strain willgrow if given that substance, an O means lack of growth.SupplementsMutant A B C D E F G1 + + + + + O +2 O O O O O O +3 O + + O + O +4 O + O O + O +5 + + + O + O +6 + + + + + + +7 O O O O + O +Four different uracil auxotrophs of Neurospora are tested for growth on uracil and uracil precursors. The data are shown in the table below. A plus sign (+) means growth. Mutant 1 is defective for which enzymatic step? Compound A B C D Uracil Mutant 1 - + - - + Mutant 2 - + - + + Mutant 3 + + - + + Mutant 4 - - - - + D to A A to D D to B C to A A to CDescribe the molecule shown in the image. Evaluation at Atomic Resolution of the Role of Strain in Destabilizing the Temperature Sensitive T4 Lysozyme Mutant Arg96-->His
- Some people have a genetic predisposition for developing priondiseases. Examples are described in Table 25.6. In the case ofGerstmann-Straüssler-Scheinker disease, the age of onset istypically 30–50 years, and the duration of the disease (whichleads to death) is about 5 years. Suggest a possible explanationwhy someone can live for a relatively long time withoutsymptoms and then succumb to the disease in a relativelyshort time.A classic way to isolate thymidylate synthase–negative mutants of bacteriais to treat a growing culture with thymidine and trimethoprim. Most ofthe cells are killed, and the survivors are greatly enriched in thymidylatesynthase–negative mutants.(a) What phenotype would allow you to identify these mutants?(b) What is the biochemical rationale for the selection? (That is, why are themutants not killed under these conditions?)(c) How would the procedure need to be modified to select mammalian cellmutants defective in thymidylate synthase?Among the following structures, the drug that can be given orally against B-lactamase-producing strain: is: CO-H OCH COOH I COOH II NH2 HO COOH III IV COOH Oll ONone of the above OlI OIV